thanks alot for this and your other tutorials...my algebra 2 teacher's style of teaching works awfully for me, but these help significantly. I was failing the class miserably most of last marking period, but this MP I have an 85. Much appreciated :)
|| x^2 + 4x + 3 = 0 || x^2 + 1x + 3x + 3 = 0 || x(x + 1) + 3(x + 1) = 0 || since we have two (x + 1)'s, we use only one of it so we get || (x + 3) = 0 and (x + 1) = 0 || therefore we get: x = -3 and x = -1||
I don’t know if you’ll see this but, thanks. These videos were the reason I went from a f to 85 in AP math. Much props to you!
Wow! That’s awesome! Congratulations! Glad to hear my videos have been able to help you. Keep up the good work!
this is exactly what i’m learning in school right now! thank you so much for teaching students and helping them learn!!
Glad to hear it was good timing on this video for you…and glad to hear my videos are helping you.
I love the simplicity of your explanations, buddy.
Keep it up.
Super helpful when assisting the kids with hw and refreshing the memory! 🙏🏼 Grateful
Glad it was helpful!
Thank you this helped me a lot
Glad it helped
Great tutorial. Thanks!
You're welcome!
Thank you man ❤❤❤
You're welcome 😊
thanks alot for this and your other tutorials...my algebra 2 teacher's style of teaching works awfully for me, but these help significantly. I was failing the class miserably most of last marking period, but this MP I have an 85. Much appreciated :)
You're welcome, keep up the good work!
Nicely explained thank you so much mr. Mario. You are awsome
Thanks! I’m glad my video helped you understand completing the square.
Can we also learn cubic eqautions
will you look at that Mario has done it again. The vids are so helpful and are so easy to understand keep up the great
Glad you’re finding the videos helpful!
Great explanation!
Glad it was helpful!
Great
Thanks for the. Algebra 2 videos . Th
Glad you like them!
❤😂 Thanks. I needed this.
You’re welcome 😊
How do I do this when my B isnt divisible by 2
You can make it a fraction
|| x^2 + 4x + 3 = 0 || x^2 + 1x + 3x + 3 = 0 || x(x + 1) + 3(x + 1) = 0 || since we have two (x + 1)'s, we use only one of it so we get || (x + 3) = 0 and (x + 1) = 0 || therefore we get: x = -3 and x = -1||
Albert Einstein