Quadrilaterals L- 4 | Mid Point Theorem & Converse | Proof | Class 9 | Arsh Ma’am | BYJU'S
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- เผยแพร่เมื่อ 26 ก.ย. 2024
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" In this lesson, we explore the Mid Point Theorem, and we'll present a super easy proof for you to grasp. Get ready to elevate your math skills with BYJU'S.
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Hello kids! Check your understanding of the Quadrilaterals chapter by answering these 5 quick questions in the form: forms.gle/wgNDbNijsWhEoAfQA
Marvelous explanation mam😄
🔴 HOMEWORK-
IF PQ=7CM, CP=CQ=3.5cm( SINCE, C IS MIDPOINT)
SIMILARLY,
PB=BR=4.5cm
AND, QA=AR=4cm
BY THEOREM: IF MIDPOINTS OF THREE SIDES OF TRIANGLE ARE JOINED FOUR SMALLER TRIANGLES ARE CONGRUENT,
IN TRIANGLE ABC,
AB=CP=3.5cm
BC=QA=4cm
CA=BR=4.5cm
PERIMETER OF TRIANGLE= SUM OF ALL SIDES...
HENCE, PERIMETER OF TRIANGLE ABC= 4+4.5+3.5=12cm(answer)
😮
->Home Work Question
"The perimeter of the Triangle ABC is 12 cm, due to Mid-Point Theorum"
-> This Class Actually made MPT Very Easy and helped me a lot
Mam I am Pallavi Raj
Thank you mam for this amazing session and make this theorem halwa theorem 😇😀😀
🔴HOMEWORK QUESTION🔴
Given - 🔺️PQR , A, B and C are mid points and PQ is 7 cm , QR is 8 cm and PR is 9 cm.
To find - perimetre of 🔺️ABC
➡️
By MPT
CB = 1/2QR = 4cm
BA = 1/2PQ = 3.5cm
AC = 1/2RP = 4.5cm
Perimeter of 🔺️ABC = CB+BA+AC
=4cm+3.5cm+4.5cm
=12cm
Hw
Given : triangle pqr
C is the midpoint of pq
B is the midpoint of pr
A is the midpoint of qr
Pq=7cm
Qr=8cm
Pr=9cm
To prove :perimeter of triangle abc
Proof
Cb=1/2qr(by midpoint theorem)
Cb=1/2*8=4cm
Ca =1/2pr
Ca=1/2*9=4.5cm
Ba=1/2pq
Ba=1/2*7=3.5cm
Perimeter of triangle abc
4+3.5+4.5=12 cm
Mam please make a lecture on surface area and volume class 9th
13:33 If one pair of opposite sides are equal then it is known as Trapezium 14:35
The answer of homework questions is
12 cm is the perimeter of triangle ABC
Thankyou so much for explaining this theorem easily
Good job
Sh maan I live you as a student pls aap har video me padhaiye very very nice explaination
IF PQ = 7CM THEN AB = PQ/2
Therefore AB = 3.5
QR = 8CM THEN CB = QR/2
THEREFORE CB = 4
PR = 9CM CA = PR/2
THEREFORE CA = 4.5
NOW PERIMETER OF ∆ABC = AB+BC+CA
PERIMETER OF ∆ABC = 3.5+4+4.5
PERIMETER OF ∆ABC = 12CM
Hello mam
I am Shagun
Perimeter of triangle=a+b+c
where a=4cm , b=3.5cm and c=4.5 cm
That's why the perimeter will be 12cm ....….
Thank you mam this video is very helpful
Amazing Class ma'am
Crystal clear mam
Can you make one shot of theoram on area
Mam wrote BE =CD in proof of converse MPT (I think by mistake)the right one is BE || CD,so don't get confuse.
Yep you are right, it isn't equal but only parallel therefore it is not a parallelogram
Ma'am didn't give full explanation, auctually since E is mid point of AB it mean AE = EB and since we already know that AE = CD (PROVED BY CPCT EARLIER) we can can EB is = DC and parallel therefore since one pair of sides is equal and parallel, we can say that Quad EBCD is a Parallelogram. I hope that clears any confusion.
Thanks a lot mam
❤ amazing class mam
the perimeter or triangle abc equal 12
Very very very nice explanation 😊
Yes😮😊😊😊😊
Ma'am aren't you teaching us in Class 10?
Mam pls teach class 10
12 cm
Legends watching one day before exam
Tomorrow is my exam so I am watching now 🤣
Perimeter of Triangle ABC is 12cm
Thank you ma'am video was really helpful
Maam you are so cute ❤
Maam I have a doubt
HELLO MAM
Pq=7cm
Qr=8cm
Pr=9cm
Proof
Cb=1/2qr(by midpoint theorem)
Cb=1/2*8=4cm
Ca =1/2pr
Ca=1/2*9=4.5cm
Ba=1/2pq
Ba=1/2*7=3.5cm
Perimeter of triangle abc
4+3.5+4.5=12 cm
Mam thanku YOU ARE A SO CUTE MAM😘😘😘😘😘😘😘😘😘
❤
Bhai vo. Mam h unhe to maaf kr do
Thik hai
Thankyou mam
Mam hello
Given :
PQ=7cm
QR=8cm
PR=9cm
Since,
PQ=7cm
PC=CQ=3.5cm
QR=8cm
QA=AR=4cm
PR=9cm
PB=BR=4.5cm
PC=AB
PB=CA
QA=CB
In ∆ABC
AB+CA+CB=Perimeter of ∆
3.5+4.5+4=12cm
Perimeter of ∆ ABC is 12 cm
Hii mam
😅
toooo lag tooo slow my teacher completed in 20min but u took 1hr omg , but u teach good
Mam I am new my name is simran shrivas
😂🎉🎉😢😮
Hello mam l am lete
So hardd
Yes😮😊😊😊😊