Millikan's Oil Drop Experiment - A Level Physics

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  • เผยแพร่เมื่อ 6 ม.ค. 2016
  • Find more videos for Year 13 work at A Level Physics Online Members: / @alevelphysicsonlineye...
    Millikan used this apparatus to measure the fundamental charge on an electron in the early twentieth century - see how he could measure such a small value using relatively straight forward lab equipment.
    Thanks for watching,
    Lewis
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ความคิดเห็น • 50

  • @VyvienneEaux
    @VyvienneEaux 4 ปีที่แล้ว +9

    I prefer this explanation over others online because you nicely defined variables and set up an equation to crystallize the concept for us.

  • @sea5205
    @sea5205 5 ปีที่แล้ว +23

    Really well explained video!

  • @baraskparas9559
    @baraskparas9559 2 ปีที่แล้ว +6

    Congratulations on an excellent, logical presentation.

  • @Hans-pc1vc
    @Hans-pc1vc 5 ปีที่แล้ว +6

    The best explanation on TH-cam. Thank you!

  • @RayxaxD
    @RayxaxD 4 ปีที่แล้ว +1

    You made much easier to understand the experiment! Thank you!

  • @Ghost____Rider
    @Ghost____Rider 5 ปีที่แล้ว +4

    I actually enjoyed this video, thanks!

  • @atonomousunknown4285
    @atonomousunknown4285 5 ปีที่แล้ว +3

    Went from here to there but understood each step. the legos were really helpful plus Great quality vids..

  • @leonardowilhelmdicaprio999
    @leonardowilhelmdicaprio999 3 ปีที่แล้ว +2

    You cleared every bloody thing up!!!!

  • @eshaanmalasi3539
    @eshaanmalasi3539 2 ปีที่แล้ว +1

    your Lego explanations help me visualise the experiment perfectly

  • @dhruvgoel9848
    @dhruvgoel9848 ปีที่แล้ว +1

    It's actually amazing how you used legos to help us visualise the experiment.

  • @KnowledgeScroll
    @KnowledgeScroll 8 ปีที่แล้ว +21

    Great Video !!!...This derivation was insane but that's what I like about physics. :)

    • @PhysicsOnline
      @PhysicsOnline  8 ปีที่แล้ว +8

      +CXC Tutor Each step is quite simple and logical, and often uses equations we're all familiar with, but the end result can look amazingly complicated. I'm just trying to show that even these weird looking formula aren't always as bad as they first seem.

    • @KnowledgeScroll
      @KnowledgeScroll 8 ปีที่แล้ว +3

      +A Level Physics Online and you did an excellent job.

    • @PhysicsOnline
      @PhysicsOnline  8 ปีที่แล้ว +7

      Thanks - I'm going to make a few more famous experiments in Lego form soon.

  • @edwinthompson7402
    @edwinthompson7402 7 ปีที่แล้ว +1

    brilliantly explained

  • @fouzal3badi898
    @fouzal3badi898 8 ปีที่แล้ว +1

    thank you very much, bless you

  • @sharonsunil978
    @sharonsunil978 2 ปีที่แล้ว +1

    thank you so much..

  • @ImeneBellahdid-cf9gd
    @ImeneBellahdid-cf9gd 9 หลายเดือนก่อน +1

    Wooow I like it thank you so much 😍😍😍😍

  • @subashrawat5660
    @subashrawat5660 6 ปีที่แล้ว +4

    Lifesaver damn....

  • @Xd_Froze
    @Xd_Froze ปีที่แล้ว +2

    Thank you

  • @tau6511
    @tau6511 8 ปีที่แล้ว +4

    U owe my life.... xD saved me from spot test

  • @rushvi1611
    @rushvi1611 4 ปีที่แล้ว

    thank you for this video:) I am still confused about the forces on the oil droplet. If there's drag & gravity, and the droplet reaches terminal velocity (so resultant force = 0), then can we consider the weight acting on it with the Coloumb force?

  • @commodorekitty
    @commodorekitty 6 ปีที่แล้ว

    Thanks! 💖

  • @joshuaft1
    @joshuaft1 5 ปีที่แล้ว

    Legendary sir

  • @triggeredboyz7142
    @triggeredboyz7142 4 ปีที่แล้ว +1

    Thanks a lot sir!!
    Lego made me learn easily!!

    • @PhysicsOnline
      @PhysicsOnline  4 ปีที่แล้ว +1

      This is a difficult topic. So hopefully this makes it a bit easier!

    • @triggeredboyz7142
      @triggeredboyz7142 4 ปีที่แล้ว

      @@PhysicsOnline yes sir it helped me, as a student!!
      👏👏👏👏🙏🙏
      I'm your fan from now; I've shared your video!!

  • @top10foryou84
    @top10foryou84 2 ปีที่แล้ว

    can we use this method to overcome gravity and create an effect of zero gravity
    i mean by knowin th wieght of person we produce + charge equal to its weight and it will float like zero gravity

  • @rehnumaislamruhana7804
    @rehnumaislamruhana7804 2 ปีที่แล้ว

    Very helpful

  • @anirsan
    @anirsan 6 ปีที่แล้ว

    Is this important for CIE A levels?

  • @ebunoluwaojo9356
    @ebunoluwaojo9356 2 ปีที่แล้ว

    great video! But does the drag force affect the oil droplet when it is stationary

    • @wahajqamar5456
      @wahajqamar5456 2 ปีที่แล้ว +1

      no , beacuse it will only be stationary due to the PD. so when it is stationary the weight is equal to the electric field. So no drag involved .

  • @feranmiodelotan7151
    @feranmiodelotan7151 3 ปีที่แล้ว

    I'm confused. I just watched another video which says that as the oil drops came down, they lost electrons making them become positively charged. And that the top plate was negative. So the positively charged electron was attracted to the negatively charged top plate. I would appreciate if I can get an explanation for this

    • @lucksterduck
      @lucksterduck 3 ปีที่แล้ว

      I think you meant "oil drop" instead of "electron" in your second to last sentence. As for your question, I wonder if the discrepancy has to do with the fact that Millikan observed the chamber through an eyepiece, which would have inverted everything from his point of view. This would mean that the bottom plate was in fact negatively charged, only that it appeared to be the top plate as viewed through the eyepiece.

    • @feranmiodelotan7151
      @feranmiodelotan7151 3 ปีที่แล้ว

      @@lucksterduck Thanks for this. But which explanation do you think would be generally accepted?
      Exam-wise and all

  • @jasperfirth8933
    @jasperfirth8933 5 ปีที่แล้ว

    Great video, but I would have liked to know why he was getting answers which were multiples of 1.60 instead of just 1.60 flat out

    • @koko10900
      @koko10900 5 ปีที่แล้ว

      Its because 1.6 x 10^-19 C is the charge of a single electron ( The smallest quanta of charge). The oil droplets would consist of ionised atoms so some would give values of exactly the elementary charge but others would give larger multiples as more than one electron will have been removed. Thus it would provide multiples of the elementary charge rather than a single electrons charge.

  • @yasminstone3151
    @yasminstone3151 3 ปีที่แล้ว

    i dont understand from 6:37 onwards. Please help!

    • @darwinianchimp2630
      @darwinianchimp2630 ปีที่แล้ว

      How has life come to be without that explanation?

  • @koko10900
    @koko10900 5 ปีที่แล้ว +1

    Paper 3 tomorrow everyone! Good luck!

  • @babischatzis5620
    @babischatzis5620 5 ปีที่แล้ว

    these things must be explained without equations... to me

  • @kaivanshah4304
    @kaivanshah4304 4 ปีที่แล้ว

    why was the oil drop in equilibrium

    • @capt.heinrich6945
      @capt.heinrich6945 3 ปีที่แล้ว +1

      the voltage used is just right so that the negatively charged oil drop cannot fall since it is attracted by the positively charged top plate, as well as being repelled by the negatively charged bottom plate

    • @kaivanshah4304
      @kaivanshah4304 3 ปีที่แล้ว +1

      @@capt.heinrich6945 thank you

    • @capt.heinrich6945
      @capt.heinrich6945 3 ปีที่แล้ว

      @@kaivanshah4304 no problem

    • @DopeAK7
      @DopeAK7 2 ปีที่แล้ว

      @@capt.heinrich6945 so mg = EQ?

  • @FrazzleFlib
    @FrazzleFlib ปีที่แล้ว +1

    9:44 L

  • @mbaziiramark3508
    @mbaziiramark3508 ปีที่แล้ว

    Hi

  • @Scrupee
    @Scrupee 3 ปีที่แล้ว +1

    Zafir you here? 😪