37-Subquery Using ALL,ANY & EXISTS Operators in SQL | Example | Advance SQL | EXISTS vs IN vs JOINS

[@Tech.S7]

Simple very short ways.... Explained like a pro... Layman can also understand..... Good teaching 🙏

[@onestopdata4568]

great explanation

[@attacker21]

Really helpful thanks a lot

[@jamesopoku8049]

Nice tutorial, keep it up, I really like your videos 👋👋👋

[@_hulk748]

Great lecture mam thank you 🙏

[@AnandMishra-ou3tv]

Very helpful videos thnx ❤

[@sivadurga9204]

Very Precise explanation 👏

[@user-qe7pr6rx7k]

Nice explanation madam

[@CodeEra2020]

Thanks for watching

[@aryabhatt5833]

Thank you ma'am.

[@jaymahajan3871]

Good 👌😊👍😊

[@nasimahmed6832]

great work

[@maheshmenta6078]

simple explanation mam tq

[@CodeEra2020]

Thanks for watching

[@prajuyaragorla8161]

how to find deptname =it second highest sal ..like out put empno dname sal deptno

[@nandhunavrath]

The last query in this video: using 'IN' operator, shouldn't the subquery be - select customers.name
ie.,: (select customers.name from orders where orders.customer_id = customers.id)
as orders table doesn't have name column?

[@SiamData]

for the first example couldn't we just use in operator?

[@sabari752]

100th like is mine