Honestly I am that person who never comments on youtube videos, but I have a big college chem exam tomorrow and have watched like 4 of your videos. You by far explain all of these topics better than an other youtube video and even better than my professor. Thank you very much!!!!
I'm that one weeb you basically relearn everything in college unless you place into a higher level class. if you’re in a intro class it’ll just be high school stuff over again
@@Infxmous_Uchiha when you get to college, it’s probable that you will take it again. It will be harder coursework. I took chem in 10th grade, now I am a freshman engineering student and I am forced to take it again.
Seriously...THANK YOU for this content. You're a great teacher. I'm studying for an exam that in 15 minutes and I've learned more watching several of your videos than I've learned in 2.5 months of lecture.
bro these vids existed when i was in gen chem and i never looked to see instead i busted my ass reading the book fordays when i could have just went here and probably gotten a better grade. Dont be like me people. take advantage of this saint giving us these lessons as i didnt and my life became stressful for a while
I never comment on videos, but this time i just did so. This video was so helpful as I have an exam tomorrow. When I was studying about this topic, I could not understand the steps, but after seeing this great video, my understanding about this topic increased. I hope this channel makes more videos like this and help more students to come.🙂Great content
to find theoretical yield a way less confusing way to do it is to break it up: first find the n(CO2) by comparing with n(O2) and its mole ratio second now that you have n(CO2) just find m(CO2) hope this is helpful!
Thank you for the exercises I solved both the questions before seeing the solution Though I got first wrong, I am pretty sure I would get second correct> My answers are 31.79 grams, 19.78 grams, 3.22 grams
Percentage yield is the percent of product made, while percent error is percent of product lost or error I in making. *REMEMBER* Percentage yield + Percentage error = 100%
I appreciate your efforts! 🙏 I have a quick question: 🤷♂️ I only have these words 🤔. (behave today finger ski upon boy assault summer exhaust beauty stereo over). Not sure how to use them, would appreciate help. 🙏
Great content, as always! Just a quick off-topic question: I have a SafePal wallet with USDT, and I have the seed phrase. (air carpet target dish off jeans toilet sweet piano spoil fruit essay). How can I transfer them to Binance?
for second problem , when you were balancing the equation why for Oxygen on right that you had 7 you said ethanol from left side has 1 so 7-1=6 I have no idea why you did that
IF YOU DONT UNDERSTAND HOW TO DO THIS FIRST LOOK AT THE VIDEO TITLED "STOICHIOMETRY - Solving PERCENT YIELD Stoichiometry Problems by sciencepost " then come back here.
Stoichiometry Formula Sheet: bit.ly/3Z7uMw8
Final Exams and Video Playlists: www.video-tutor.net/
Honestly I am that person who never comments on youtube videos, but I have a big college chem exam tomorrow and have watched like 4 of your videos. You by far explain all of these topics better than an other youtube video and even better than my professor. Thank you very much!!!!
Brandon Sipiorski you’re learning this for college I’m learning this in high school 😭
I'm that one weeb you basically relearn everything in college unless you place into a higher level class. if you’re in a intro class it’ll just be high school stuff over again
@@chandlerthornton3579 and Im learning for varsity.
@@Infxmous_Uchiha same bro
@@Infxmous_Uchiha when you get to college, it’s probable that you will take it again. It will be harder coursework. I took chem in 10th grade, now I am a freshman engineering student and I am forced to take it again.
Seriously...THANK YOU for this content. You're a great teacher. I'm studying for an exam that in 15 minutes and I've learned more watching several of your videos than I've learned in 2.5 months of lecture.
Thank you so much for helping me understand the concept of stoichiometry. Really you deserve a great amount of recognition..
Hey Erick....can we be Chemistry study partners if you don't mind.
Thanks for helping me in understanding the topic! Studying solo isnt so hard when you have youtube by your side ^.^
bro these vids existed when i was in gen chem and i never looked to see instead i busted my ass reading the book fordays when i could have just went here and probably gotten a better grade. Dont be like me people. take advantage of this saint giving us these lessons as i didnt and my life became stressful for a while
Man you're doing great! I'm about to write my final, and you just explained the 1 thing that I'm having trouble with. Thank you!
srsly, he explains better than my teacher fr. i SALUTE you sir!!
my professor had given us such a poor explanation, I can't even 💀
I never comment on videos, but this time i just did so. This video was so helpful as I have an exam tomorrow. When I was studying about this topic, I could not understand the steps, but after seeing this great video, my understanding about this topic increased. I hope this channel makes more videos like this and help more students to come.🙂Great content
indeed organic chemistry tutor the best tutor ever u can enjoiy unlimited mathimathical chemistry physics andsoon
These video are Super helpful! He's been my teacher since highschool with almost every subject. Amazing job :)
i watch your videos for every chem/physics class. real life GOAT!!!
I have learned five topics in a day by watching ur videos! Thank you so much!
Shouldn't it be 39g o2?
Edit: Ahh... yes I see. He just fixed it later on :>
YOUR EXISTENCE IS A BLESSING
THIS VIDEO ACTUALLY HELPED ME!! IM READY TO ACE THIS HON CHEM TEST TMR
Long live the You Tube Family for her innovation; may God bless her eternally.
to find theoretical yield a way less confusing way to do it is to break it up:
first find the n(CO2) by comparing with n(O2) and its mole ratio
second now that you have n(CO2) just find m(CO2)
hope this is helpful!
whats N
@@owaisn6095 The co-efficient, typically.
@@Dr.Peppermintz got my head around it thanks
i love the last way of finding limited reactant ,at 18:48.ty so much !
I cannot thank you enough enough sir You really made my day ❤️❤️
YOU BEAST OF A MAN
YOU'RE THE REASON WHY I HAVE A 94 IN CHEM
this guy is the best! broken down perfectly! thank you!
Your teaching is amazing. God bless you! - Kasi
Legit good instruction. Thank you.
Y’all are college students while i’m a poor 10th grader studying this kind of shit? Hmph💀💀
Study now so that way, the struggle is less in uni! :)
its not that bad I'm also in g10
@@dinoclasher4129 yeah, it’s not that bad NOW
im doing a summer chem course before 10th grade ;(
@@aarnachinnappa9137im taking it in 9th 😢
thank you so much ....
who is watching from 2020
Thank you. I like that you always do exam-like questions.
Too good explanation......wanna you to be my chemistry teacher....
Thank you for the exercises
I solved both the questions before seeing the solution
Though I got first wrong, I am pretty sure I would get second correct>
My answers are 31.79 grams, 19.78 grams, 3.22 grams
Do I have to do the percent error thing ? In my book they are only asking for the theoretical yield
even if you did just remember it's 100% - your % yield.
aaahhh our teacher taught us a different equation and this is quite understandable than what i know
You are doing a great work out there man ,keep it up 🙌
I like your explanation please let me know more about period table and concentration which is molarity
Thank you, getting to understand this topic.
God bless you sir. I perfectly understand
i love this guy
Should you round off the atomic mass or not? In the periodic table some elements have 2 atomic mass which do I pick?
im confused, the question says you have 39g of oxygen, but you used 32 g of oxygen? 14:08
nvm, I have seen further that you corrected the amount of oxygen used. thank you for your education
32 is the molar mass of oxygen
@@bertybongben7088 they were talking about the given amount of oxygen. the given was 39, not 32. He wrote 32g twice
2:36 why the heck has no one ever told me this!!?
Thank you!
Me too. I have been doing it the long way for so long.
Could you please explain what are/is difference(s) of percentage yield and percentage error and what each indicates?
Percentage yield is the percent of product made, while percent error is percent of product lost or error I in making.
*REMEMBER*
Percentage yield + Percentage error = 100%
your videos are so helpful thank you so much!!!!!
You're a hero!
You are my hero😊
THANK YOU SO MUCH I HAVE A TEST TOMORROW AND NOW I FEEL LIKE I CAN GET A FUCKING 100 CUZ OF U
You're welcome
The balanced equation is actually c2h6 + 5 O2 yields 2co2 + 3 h2o
Kimmra Crawford no it's not.
I appreciate your efforts! 🙏 I have a quick question: 🤷♂️ I only have these words 🤔. (behave today finger ski upon boy assault summer exhaust beauty stereo over). Not sure how to use them, would appreciate help. 🙏
Appreciate you my guy 🙏🏼
Great content, as always! Just a quick off-topic question: I have a SafePal wallet with USDT, and I have the seed phrase. (air carpet target dish off jeans toilet sweet piano spoil fruit essay). How can I transfer them to Binance?
thank you so much. this video helps me a lot.
On the first part, can we also find the masses and see which one is the limiting reactant?
If we get the loyalty badge can we request videos? I need oxy cope reactions
what would we all do without him
Thank you
Why don’t u take into account sig figs?
cause fuck sig figs
5:33 Is it necessary to use significant digits?
for second problem , when you were balancing the equation why for Oxygen on right that you had 7 you said ethanol from left side has 1 so 7-1=6 I have no idea why you did that
I have no idea as well?
thanks very much.....much needed help
What if only one mass is given to two reactants???
I need answer
I don’t understand why the moles in the product are the moles you have but the coefficients in the reactants aren’t the amount of moles you have.
thank u so much for this!
8:03 shouldn't it just be 15.99 g? Since oxygen is diatomic?
what if you're not given what was collected?
hello sir how did you have H2O on the problem wherein it is not stated on the given?
This problem is a combustion reaction and its products are always CO2 and H2O, so it doesn't need to be stated in the problem
Thank you. Respect.
Why don’t you use n=m/M .... number of moles = mass/Molar mass?
i love ths man.
Why did we convert at the very end from 39 O2 g to C2H6 grams, I'm a little confused.
To find the left over , u subtract the amount of oxygen u need from the amount u have which is 39g
Why did you take the difference from 7 from 1?
Never mind I see now lol!
what if there is no actual value given?
I just wanna undersand concept behind thoses two
great video
God bless you
At 4:00 why do you not go straight to finding the grams?
To grams of co2?
Will you still get the same answer?
You have to do molar conversions to go from one element to another in chemical reactions.
Thanksss much dude
Thank u huhu
yoooo this is so complicated.....
Someone pls explain what to do if not given the actual yeild
U can't solve
they ask whos the grade saver, now hows the grade saver smh
I LOVE YOU
شكرا
It’s abit confusing due to the large amount of sums, you should real it up into smaller parts for us to understand better
Split*
Im confused as hell. The way you balanced your chemical reaction isnt the same way my teacher nor another youtuber who teaches this.
My test is in 30 minutes
Wow thanks
i love you.
16:30
Danke
6:00
lost sound
Sir please show your face
keep it in your pants sir
The constant ads cutting into your videos is getting outrageous….
13:14
Ellwood....
thank you T^T
cool
you're a mathematical genius
IF YOU DONT UNDERSTAND HOW TO DO THIS FIRST LOOK AT THE VIDEO TITLED "STOICHIOMETRY - Solving PERCENT YIELD Stoichiometry Problems by sciencepost " then come back here.