The best video as far as the explanation and concept clearing is concerned. You touched all the necessary point that was needed to be clarified. Hope to see more of your videos
This is confusing.. the Pressure PA on the cylinder in left is basically equal to your rho*g*h1 because it is the same gas and its pressure will be the same at all points once you open that cylinder..If its not the same pressure yet then it will continue to push the orange fluid up until it becomes stable and can't push further. Also, atmospheric pressure can't be neglected in an open manometer. How could you neglect 101.325 KPa which is a huge magnitude.
Great video but some improvement needed. The U tube is open at the end of both limbs. So there is atmospheric pressure acting on both sides of the limb. So the correct equation is Patm + Pa + r1gh1 = Patm + r2gh2. 2) Using the same equation for determining vacuum pressure Patm + Pv + r1gh1 + r2gh2 = Patm This equation correctly describes the pressure dynamic at play. It was very unclear in your video why the pressure on right limb was 0.
The best video as far as the explanation and concept clearing is concerned. You touched all the necessary point that was needed to be clarified. Hope to see more of your videos
If the right side is open, there is also the pressure from the atmosphere specified at a certain level
This is confusing.. the Pressure PA on the cylinder in left is basically equal to your rho*g*h1 because it is the same gas and its pressure will be the same at all points once you open that cylinder..If its not the same pressure yet then it will continue to push the orange fluid up until it becomes stable and can't push further. Also, atmospheric pressure can't be neglected in an open manometer. How could you neglect 101.325 KPa which is a huge magnitude.
amazing sir is really help full for every one even for a gate
Thank you for your effort ❤️
SUPER EXPLANATION SIR. THANK YOU
thank u sir very nice video upload some more for venturimeter
Thank you very much
Thank you sir ❤
Thank you.
Thanks a lot sir.. All my doubts where really clarified.. are you a malayali!?
Thank you so much
Thank you sir ❤❤❤🎉
Thank You Sir, Very Helpful! LongLive Indians!
Hahaha, they smell but they are smart :-D
well explained
sir it is alright but here at right limb there exist atmospheric pressure but you not mention in general equation
super sir.......
tq sir
means how to measure pressure inside tank n pressure diffrnt of gap of tank..
plz upload video to pressure calculation of tank n pressure diffrnt of tank,how to calculate liquid tank pressure
Super bro
Please explain why datum line is drawn
don't atmospheric pressure act in the right limb?
not all heroes wear capes :'')
the name of prograamme u used
in second case, how the pressure becomes zero in right limb.?????
sir why we didn't add the atmospheric pressure on the right limb as it is open not closed ?
ahmed fawzy becoz of negligible value...
What happen if h2 is less than h1
liked
Enough idea 💡🙄
Why didn't you consider Atmoshperic pressure in the right limb?
We can consider, but I have neglected it. If it is mentioned in the problem, we have to consider.
Subtitles*
Great video but some improvement needed.
The U tube is open at the end of both limbs. So there is atmospheric pressure acting on both sides of the limb. So the correct equation is
Patm + Pa + r1gh1 = Patm + r2gh2.
2) Using the same equation for determining vacuum pressure
Patm + Pv + r1gh1 + r2gh2 = Patm
This equation correctly describes the pressure dynamic at play.
It was very unclear in your video why the pressure on right limb was 0.
Atmospheric pressure is neglected there...
Find the hight please sir
utube on youtube
#mano_tube
slow down and pronounce words
Good video..But do try to improve your spoken language. Its feels as though there isnt any passion in it.