How to find Phase Shift in Sin and Cos Graphs

How to find the phase shift and horizontal shift in sine and cosine graphs and functions.
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[@adammarley5616]

Thank you!!! this was one of the best videos I found

[@danthetutor2624]

Only one of the best? Looks like I've got more work to do.

[@ThePreppar]

Ok, so how do I find a phase shift between two sin graphs?

[@danthetutor2624]

I’d imagine you’d have to find the phase shift for both and then subtract them.

[@GrimBehelit]

​@danthetutor2624 how do you subtract pi(a)/a. a being any number

[@ThePreppar]

@@danthetutor2624 like one is the shifted wave…

[@ThePreppar]

@@GrimBehelit what?

[@GrimBehelit]

​@@ThePreppar if you don't understand that I don't think you'll understand even if I elaborate.

[@LMangia]

this was really helpful. thank you man

[@dnuma5852]

ah yes my favorite explanation, it is to the right because its the opposite of what you think. its just since to reach any given point x on a curve without a horizontal translation on a curve with a translation, one must position oneself x+c along the x curve, since x+c-c=0. for positive c, this infers a translation to the right.

[@qbasant287]

this is the best vid!! it was really helpful thanku

[@danthetutor2624]

Glad you liked it!

[@qbasant287]

@@danthetutor2624 i lovedd itt

[@Lisinfilm]

Awesome, awesome, thank you 👍

[@ryanchiang9587]

2pi

[@TreSwayy]

Thanks for this, got confused on this because on Khan Academy, phase shift isn't explained nor is the factoring part.

[@danthetutor2624]

And that’s why Khan Academy isn’t as good as Dan the Tutor. But that’s just my unbiased opinion.

[@marwanelallaly-yz8gn]

you could also use addition formula to show this sin(x+90)=sinxcos90+cosxsin90 which equals cosx

[@danthetutor2624]

Yes, that is true. I didn't even realize that until you said it.

[@memsuniverse]

great explanation thank you

[@danthetutor2624]

Happy to help!

[@cube6338]

Thanks, I really need this😭

[@danthetutor2624]

Always happy to help!

[@yugpanchal8422]

Great explanation was really helpful. Thank you so much!

[@danthetutor2624]

Thank you for watching!

[@christianzorilla895]

Oh my god thank you😭 this is really helpful, i have a presentation about this in the next 2 days and im stressing because I cant understand what a thing stated in the module

[@danthetutor2624]

Believe me, I’ve been there. Happy to help!

[@Gucci-UwU]

Ong this was actually helpful

[@cheesychester9647]

legend. thanks

[@danthetutor2624]

Thanks G