Please watch 1:46 and input the relevant frequency or use a signal generator 5:18 (under INSTRUMENTS) , that is the 7th item in that list. Those are the options available.Hope It will help you
When the operating frequency is equal to cut off frequency, the gain is equal to 0.707 Af (Af is the passband gain of the filter (1+R2/R1).So that gain is about =0.707 Af = 0707x 2 = 1.414. output amplified voltage is about = 1.414 x 5 Vpp = 7.07 Vpp.For further study please refer www.electrical4u.com/active-low-pass-filter/
the one actually explain stuff 🙌
Thank you....glad to help you
please how much did you purchase the software
Thank you so very much!
No worries!...👍👍👍
Thank you so much my completely doubt clear on oscilloscope
Happy to help you....
It works! :-) Thanks
You're welcome!
how to changes the frequency input?
Please watch 1:46 and input the relevant frequency or use a signal generator 5:18 (under INSTRUMENTS) , that is the 7th item in that list. Those are the options available.Hope It will help you
What type of input do we give to the filter
For this low pass filter ,the input is a sin waveform
if the input is 5Vpp shouldn't the output be 10Vpp? since the gain is 2
When the operating frequency is equal to cut off frequency, the gain is equal to 0.707 Af (Af is the passband gain of the filter (1+R2/R1).So that gain is about =0.707 Af = 0707x 2 = 1.414. output amplified voltage is about = 1.414 x 5 Vpp = 7.07 Vpp.For further study please refer www.electrical4u.com/active-low-pass-filter/
Thanks alot bro
Always welcome
is there a reason why you chose 10K and not something else?
No, it is to get gain of 2 (for an example).