Hello Professor, I was wondering, why when deducing the period of the pendulum, on the left we put [M]^0, [L]^0, [T]^1, but the gravitational acceleration is not considered?
We want period on the left side, of the formula, so only T appears. On the right side of the equals sign in the formula are all the factors period could depend on. So we put gravitational acceleration on the right side.
Thanks Prof. I have another question, I have to take the physics 1 exam in my university (I study computer science) by watching this playlist will I cover everything I should know? Or do I have to study in depth through books?
@ I always recommend books. Many are available online free of cost, or you may buy them from second hand bookstores really cheap. Problem solving is key to internalizing physics concepts, watching my videos is all well and good, but to become proficient in the subject you have to work out as many problems as possible: learn to do the setup, use appropriate equations, solve, then examine units and various limits to see if the solution makes sense algebraically, and only at the very end, substitute numbers with units.
Good question. The reason has to do with proportional reasoning in experiments. When you keep everything fixed and vary just one thing, then you expect proportionality with respect to the one thing you varied. A sum form would not satisfy this requirement.
@@DR_VIV OK, yes, I thought the same. So basically it's case-dependent and you just have to come up with a reasonable speculation for each problem. I thought that perhaps there would be a general rule or something. Thanks!
@@hnhl2770 take a simple example: distance traveled depends on initial speed, acceleration and time. You cannot come up with a multiplicative formula with all three factors. (There is a theorem in dimensional analysis called “pi theorem”, look it up, it tells you how many independent factors you can have.) So to find a formula, you proceed by stages. Set acceleration to zero: then you deduce D = VT. Then set initial velocity equal to zero. Then you deduce D’ = c AT^2. The actual formula must be a sum of D and D’, and as we all know from elementary kinematics, the factor c is 0.5.
![จากรุ่นใหญ่สุดรวยในเกม FIVEM สู่การติดคุกแก๊งแตกในชีวิตจริง [สรุปแก๊งOREO]](http://i.ytimg.com/vi/Vjj8EX4qpiU/mqdefault.jpg)
I never thought I would watch physic videos out of boredom but here I am, also very informative video
yeah same
Thank you so much for the course I really appreciate it
Interesting and powerful technique
these videos are so helpful!! thank you for your service!
Thank you very much sir!
Thank you for this. I havent ever taken physics at all. Im totally new. And have to take it. Hopefully i can learn. Starting from the ground
Go slow and think deeply
Thank you!
I just want to know what kind of pen you are using
Hello Professor, I was wondering, why when deducing the period of the pendulum, on the left we put [M]^0, [L]^0, [T]^1, but the gravitational acceleration is not considered?
We want period on the left side, of the formula, so only T appears. On the right side of the equals sign in the formula are all the factors period could depend on. So we put gravitational acceleration on the right side.
Thanks Prof. I have another question, I have to take the physics 1 exam in my university (I study computer science) by watching this playlist will I cover everything I should know? Or do I have to study in depth through books?
@ I always recommend books. Many are available online free of cost, or you may buy them from second hand bookstores really cheap. Problem solving is key to internalizing physics concepts, watching my videos is all well and good, but to become proficient in the subject you have to work out as many problems as possible: learn to do the setup, use appropriate equations, solve, then examine units and various limits to see if the solution makes sense algebraically, and only at the very end, substitute numbers with units.
thank you very much professor, more people like you in this world
12:11
How does (L 1/2)(L -1/2) equal the square root of of L/g?
Thank you
Ysl7 l L1 st
But why do you assume that given those "ingredients" as you call them, the period is their product?
Good question. The reason has to do with proportional reasoning in experiments. When you keep everything fixed and vary just one thing, then you expect proportionality with respect to the one thing you varied. A sum form would not satisfy this requirement.
@@DR_VIV OK, yes, I thought the same. So basically it's case-dependent and you just have to come up with a reasonable speculation for each problem. I thought that perhaps there would be a general rule or something. Thanks!
@@hnhl2770 take a simple example: distance traveled depends on initial speed, acceleration and time. You cannot come up with a multiplicative formula with all three factors. (There is a theorem in dimensional analysis called “pi theorem”, look it up, it tells you how many independent factors you can have.) So to find a formula, you proceed by stages. Set acceleration to zero: then you deduce D = VT. Then set initial velocity equal to zero. Then you deduce D’ = c AT^2. The actual formula must be a sum of D and D’, and as we all know from elementary kinematics, the factor c is 0.5.