8.2.1-PDEs: Finite Divided Difference for Elliptic PDEs with Irregular Boundaries

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  • เผยแพร่เมื่อ 6 ก.ย. 2024
  • These videos were created to accompany a university course, Numerical Methods for Engineers, taught Spring 2013. The text used in the course was "Numerical Methods for Engineers, 6th ed." by Steven Chapra and Raymond Canale.

ความคิดเห็น • 15

  • @ozzyfromspace
    @ozzyfromspace 5 ปีที่แล้ว +2

    "Make a fine mesh and eat a sandwich while it's running"
    You're so wise, Jacob-san 😂🙏🏾🕊️✌🏾

  • @dimRizo
    @dimRizo 9 ปีที่แล้ว

    Jacob, you are the man!! Thanks!

  • @miscellaneous4195
    @miscellaneous4195 5 ปีที่แล้ว

    You wrote wrong equation but came up with the right one at the end. You Need to change negative to positive in equation d2T/dx2 (+) d2T/dy2 = 0

  • @imrulkayesharu8610
    @imrulkayesharu8610 2 ปีที่แล้ว

    Can you please upload a video solving problems relating this formula?

  • @king0vdarkness
    @king0vdarkness 6 ปีที่แล้ว

    Awesome video! Much easier to understand, thank you! Please can I ask how you would find alpha 1 (if alpha 2 and delta x are defined)?

    • @king0vdarkness
      @king0vdarkness 6 ปีที่แล้ว

      Actually no worries, just found out you can use Pythagoras to find out values of alpha and beta

  • @tugced7506
    @tugced7506 8 ปีที่แล้ว

    thank you so much sir

  • @jAys92L
    @jAys92L 9 ปีที่แล้ว +1

    Hi there , your teaching is nice. however i wonder how should i determine the alpha 1 and beta 1??

    • @kvyi
      @kvyi  7 ปีที่แล้ว

      alpha and beta refer to lengths. They are measurements based on the geometry of the situation. To clarify, here's how it's done for the example above. Assume the curve shown is a circle centered in the middle of the plate. Let alpha1=beta1=1. This means the circle has radius 2*alpha1 = 2*beta1. The circle equation is x^2+y^2 = r^2. Let y=-1, since r=2, solving for x gives sqrt(3). Thus, alpha2 = sqrt(3)-1 = .732; beta2 is the same.

  • @naviddavanikabir
    @naviddavanikabir 7 ปีที่แล้ว

    @6:22
    why is the denominator divided by 2?

    • @juniomoreiramatemati
      @juniomoreiramatemati 7 ปีที่แล้ว

      I have the same doubt...

    • @SiriusBlack-qo3xi
      @SiriusBlack-qo3xi 7 ปีที่แล้ว

      Navid Davani me too

    • @kvyi
      @kvyi  7 ปีที่แล้ว

      You're adding them together and dividing by two, so the idea is that it's an average of the alphas times deltax (you can factor out the delta x if you want).

    • @tarunsantosh8811
      @tarunsantosh8811 5 ปีที่แล้ว

      Shouldn't denominator just contain alpha1*x as we are finding derivative of derivative between i-1 and i

    • @anantgairola3394
      @anantgairola3394 5 ปีที่แล้ว

      @@tarunsantosh8811 I was thinking that too. I wonder if someone (perhaps Jacob) could clarify that.