Core Java With OCJP/SCJP: RegularExpresions Part-4 || How to use Regular Expresions

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  • เผยแพร่เมื่อ 24 พ.ย. 2024

ความคิดเห็น • 35

  • @ranveervaghela7030
    @ranveervaghela7030 หลายเดือนก่อน +2

    Completed watching on Sept 30, 2024 at 2.06 AM :) :)

  • @EngineerVaibhav
    @EngineerVaibhav ปีที่แล้ว +2

    135 video completely❤🎉
    Happily completed Regular expression❤

  • @MsMKKR
    @MsMKKR 5 ปีที่แล้ว +5

    It is very useful for real time programmers. Thank you so much. Not only this but other classes are also priceless. Thank you once again

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  5 ปีที่แล้ว +1

      Hello Kiran.
      Thanks for your valuable feedback. It will boost us to do new things. Please subscribe to get updates about new videos.
      You can view all other Core Java with SCJP/OCJP Videos by Durga sir in the following link:
      goo.gl/kqvaf2

  • @raviprakashbajpai5143
    @raviprakashbajpai5143 3 ปีที่แล้ว +3

    Learning java is an addiction to me.

  • @RahulKumar-de2rw
    @RahulKumar-de2rw 4 ปีที่แล้ว +2

    By now I got complete idea of RE thanks you sir

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  4 ปีที่แล้ว

      Hello Rahul.
      Thanks for your valuable feedback. It will boost us to do new things. Please subscribe to get updates about new videos.
      You can view all other Core Java with SCJP/OCJP Videos by Durga sir in the following link:
      goo.gl/kqvaf2

  • @AshwaniBansal-ash
    @AshwaniBansal-ash 8 ปีที่แล้ว

    Wonderful Real life examples!
    People get engaged when they get these types of Examples.
    keep it Up!

  • @utsavmodh9698
    @utsavmodh9698 6 หลายเดือนก่อน +1

    Perfect 🎉

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  6 หลายเดือนก่อน

      Hello Utsav.
      Thanks for your valuable feedback. It will boost us to do new things. Please subscribe to get updates about new videos.
      You can view all other Core Java with SCJP/OCJP Videos by Durga sir in the following link:
      goo.gl/kqvaf2

  • @RahulKumar-de2rw
    @RahulKumar-de2rw 4 ปีที่แล้ว +1

    Good coverage on examples of RE

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  4 ปีที่แล้ว

      Hello Rahul.
      Thanks for your valuable feedback. It will boost us to do new things. Please subscribe to get updates about new videos.
      You can view all other Core Java with SCJP/OCJP Videos by Durga sir in the following link:
      goo.gl/kqvaf2

  • @AnkitKumar-td8rc
    @AnkitKumar-td8rc หลายเดือนก่อน

    completed the last lectures of RegX today 6 oct 2024 1:48 AM

  • @SagarKumar-m2i7w
    @SagarKumar-m2i7w 10 หลายเดือนก่อน +1

    (?i) for case insensitivity

  • @sagarjadhav5439
    @sagarjadhav5439 2 ปีที่แล้ว +4

    Is it worthy to learn this all videos which are 7 years ago recorded?

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  2 ปีที่แล้ว

      Hello Sagar.
      Plz contact our online team durgasoftonlinetraining@gmail.com or call us on this number +918885252627, 7207212427/28

  • @ajitpawar937
    @ajitpawar937 7 ปีที่แล้ว

    Great

  • @travelTronics
    @travelTronics 4 ปีที่แล้ว +3

    [a-zA-Z0-9_.$]+[.]txt ::: This regex can also take "...txt" file name.. (two dots, then .txt) . But this is an invalid file name. Could you please let me know whether I am right or wrong?

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  4 ปีที่แล้ว +1

      Hello Tronics.
      Plz contact our online team durgasoftonlinetraining@gmail.com or call us on this number +918885252627, 7207212427/28

  • @arpitrathi1334
    @arpitrathi1334 6 ปีที่แล้ว +2

    Sir, in this example of extracting all the mobile numbers, if a number of the form 929292929292 is present which is not a valid mobile number, it will still extract it as a seperate mobile number. How to overcome this without breaking the single line into multiple tokens??

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  6 ปีที่แล้ว

      Hello Arpit.
      Plz contact our online team durgasoftonlinetraining@gmail.com or call us on this number +918885252627,7207212427/28

    • @srikardhupam1895
      @srikardhupam1895 6 ปีที่แล้ว

      Bro did you find solution

    • @saurabhprakash3831
      @saurabhprakash3831 5 ปีที่แล้ว

      @@srikardhupam1895 while(m.find() && m.group().equals(line)){}

    • @navneetgupta2474
      @navneetgupta2474 5 ปีที่แล้ว

      @@saurabhprakash3831 line will contain other chars too, so it may return false.. it will return true only when there is only number present in the line

    • @muralikrishna.vajjala
      @muralikrishna.vajjala 5 ปีที่แล้ว

      I got the same doubt...we can't even use stringtokenizer here as there is no guarantee that normal text and mobile number are separated with space or any other character...if there is any solution..please post here..

  • @AmanJain-dn6pu
    @AmanJain-dn6pu 5 ปีที่แล้ว +1

    sir only these characters (/ \ : * ? " < > |) are not allowed in file names, so if i am making a file with name aman !£$¬`jain.txt than how can i make regular expression for this?
    i need to exclude only these 9 characters.

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  5 ปีที่แล้ว

      Hello Aman Jain.
      Plz contact our online team durgasoftonlinetraining@gmail.com or call us on this number +918885252627, 7207212427/28

  • @sonaalsarkar422
    @sonaalsarkar422 4 ปีที่แล้ว +1

    sir in the output file nothing is coming output

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  4 ปีที่แล้ว

      Hello Sonaal Sarka.
      Plz contact our online team durgasoftonlinetraining@gmail.com or call us on this number +918885252627, 7207212427/28

  • @speedbreaker5642
    @speedbreaker5642 8 ปีที่แล้ว

    Sir, we have to handle java.lang.ArrayIndexOutOfBoundsException !

    • @DurgaSoftwareSolutions
      @DurgaSoftwareSolutions  8 ปีที่แล้ว

      Hi Banti kumar k .

    • @speedbreaker5642
      @speedbreaker5642 8 ปีที่แล้ว

      while working on netbeans ide it will throws that exception so i said.

    • @jvsnyc
      @jvsnyc 3 ปีที่แล้ว

      @@speedbreaker5642 if (args.length != 1) { system.out.println("Wrong number of args"); return; }