Well explained video! One little nitpick, you kept saying "derivative with respect to y" (around 14m16s for example) when you meant "derivative of y with respect to t".
Suppose ( energy approach) we start at + A and end at - A, so then 1/2kA^2 -1/2kA^2 = 0 = 1/2mv^2 and we are out of luck. Btw, the most interesting question should be: what is the speed over a full cycle? From initial back to initial, (k/m*4A)^1/2? I dont get why, given the cos plots of the SHO there is neither a wave number k (not spring const!) nor any mentioning of the phase velocity omega/k = f*lambda! Where is wave length lambda??? Why, please? Velocity or speed has to satisfy this somehow, I mean frequency*lambda, right? I‘ m more interested in that and not so much the different instant v‘s in different moments of time.
Well explained video! One little nitpick, you kept saying "derivative with respect to y" (around 14m16s for example) when you meant "derivative of y with respect to t".
Thanks, sometimes I catch myself but often it slips through the cracks.
Suppose ( energy approach) we start at + A and end at
- A, so then 1/2kA^2 -1/2kA^2 = 0 = 1/2mv^2 and we are out of luck. Btw, the most interesting question should be: what is the speed over a full cycle? From initial back to initial,
(k/m*4A)^1/2? I dont get why, given the cos plots of the SHO there is neither a wave number k (not spring const!) nor any mentioning of the phase velocity omega/k = f*lambda! Where is wave length lambda??? Why, please? Velocity or speed has to satisfy this somehow, I mean frequency*lambda, right? I‘ m more interested in that and not so much the different instant v‘s in different moments of time.
I am from India I follow in months ,,I have doubt your physics videos 💯 cracking IITEJEE exam???? Please reply
Hmm...far better than Indian online lecture...