9.2 Polarity | General Chemistry

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  • เผยแพร่เมื่อ 4 ก.ค. 2024
  • Chad provides a comprehensive lesson on how to determine if a molecule is polar or nonpolar based upon its individual bond dipoles and its molecular geometry. The lesson begins with a review of electronegativity and relative bond polarity. It is then demonstrated that if the bond dipoles in a molecule sum to zero (i.e. "cancel") then a molecule is termed nonpolar, and a good example of this is CO2. It is then shown that if the central atom does not have lone pairs of electrons and if the atoms surrounding it are all the same then it will be nonpolar (as in CO2, BCl3, and CF4). It is also shown that if the central atom has lone pairs of electrons then it will USUALLY be polar (as in SO2, NF3, and H2O), but there are two MAJOR exceptions. If all the atoms surrounding the central atom are once again identical but the molecular geometry is either square planar or linear (linear with 2 bonding and 3 nonbonding electron domains) then the molecule will still be nonpolar (XeF4 and XeF2 are examples of these respectively).
    I've embedded this playlist as a course on my website with all the lessons organized by chapter in a collapsible menu and much of the content from the study guide included on the page. Check this lesson out at www.chadsprep.com/chads-gener...
    If you want all my study guides, quizzes, final exam reviews, and practice exams, check out my General Chemistry Master Course (free trial available) at www.chadsprep.com/genchem-you...
    00:00 Lesson Introduction
    00:47 Review of Electronegativity
    02:33 Bond Polarity vs Molecular Polarity
    08:24 CH2Cl2 is Polar
    11:25 CO2, BCl3, & CF4 are Nonpolar
    14:23 SO2, NF3, and H2O are Polar
    17:48 XeF4 & XeF2 are Nonpolar
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ความคิดเห็น • 25

  • @charlesharn4460
    @charlesharn4460 2 ปีที่แล้ว +13

    Loved the review on polarity. Just one thing I would like to point out, when you were talking about the polarity of water, you actually drew the dipole lines toward the hydrogens instead of toward oxygen. Best regards.

    • @ChadsPrep
      @ChadsPrep  2 ปีที่แล้ว +12

      Well that's embarrassing! But thanks for taking the time to point it out. I'll be sure to pin this comment for possible future puzzled students to see!

  • @ilanbocian1291
    @ilanbocian1291 5 หลายเดือนก่อน

    The general rule you give at 20:02 is SO HELPFUL and good to know! Makes everything much more simple. Thank you.

    • @ChadsPrep
      @ChadsPrep  5 หลายเดือนก่อน

      You're most welcome.

  • @akki3924
    @akki3924 2 ปีที่แล้ว +5

    17:12 sir I think in case of water you draw dipole moment vectors in wrong direction. Thanks for these amazing lectures though

  • @nataliiaproshunina-lc5gm
    @nataliiaproshunina-lc5gm 5 วันที่ผ่านมา

    HAPPY TEACHING, CHAD! GREAT CHANNEL!

    • @ChadsPrep
      @ChadsPrep  5 วันที่ผ่านมา

      Glad you think so!

  • @antoniorodriguez6253
    @antoniorodriguez6253 ปีที่แล้ว +3

    Are XeF2's electrons 120 degrees apart? And if so, does that mean they cancel out or how come it does not seem like they play a role in polarity?

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว +1

      the lone pairs are indeed 120 degrees apart and spread equally therefore cancelling each other out

  • @studentshir3457
    @studentshir3457 ปีที่แล้ว +1

    So clear! thanks!

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      You're welcome.

  • @angeloson2250
    @angeloson2250 2 ปีที่แล้ว +1

    Thanks Mister Chad this lesson was bothering me thank you Mr.Chad

    • @ChadsPrep
      @ChadsPrep  2 ปีที่แล้ว +1

      You're very welcome ANGELO Son! Glad it was a timely release!

  • @kawaiidesuwu7286
    @kawaiidesuwu7286 8 หลายเดือนก่อน +1

    chad u are such a chad for this i preciate u

    • @ChadsPrep
      @ChadsPrep  8 หลายเดือนก่อน

      Glad to hear it!

  • @joylynnpoppyruin3186
    @joylynnpoppyruin3186 ปีที่แล้ว +1

    Thank God I found a chemistry saviour 🙏

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Glad you found us - Happy Studying!

  • @Mekdes-o1j
    @Mekdes-o1j 10 วันที่ผ่านมา

    Thank you so much chad

    • @ChadsPrep
      @ChadsPrep  10 วันที่ผ่านมา

      You're welcome

  • @yagirlliizziie
    @yagirlliizziie 3 หลายเดือนก่อน

    I'm so confused because in C2H2CL2 my professor said that because the vectors started and ended in the same place when you draw them out, that they would indeed cancel therefore would conclude no dipole moment which means also it is a non polar molecule. Could you clarify please.

    • @ChadsPrep
      @ChadsPrep  3 หลายเดือนก่อน

      Hi Elizabeth! I think you may be confusing CH2Cl2 (in the video) and C2H2Cl2 covered by your professor. Note that these are not the same compound. CH2Cl2 has a single carbon which is sp3 hybridized and bond angles of approximately 109.5 degrees. If the Cl atoms were 180 degrees apart, it would be nonpolar, but since they are just 109.5 degrees, it is polar.
      C2H2Cl2 has 2 carbon atoms that are double bonded to each other. There are actually 3 possible isomers for this compound: 2 are polar and 1 is nonpolar. If both Cl atoms are bonded to one carbon and both H atoms to the other, then the molecule will be polar. The other option is for each carbon to be bonded to 1 Cl and 1 H atom, but there are still two isomers possible, cis and trans. The cis isomer has the Cl atoms oriented only 60 degrees apart and is still polar. But the trans isomer has them exactly 180 degrees apart and is nonpolar and I'm guessing that this might be the isomer your professor covered. Toward the bottom of the page, you can see a comparison of these last two at the following link: testbook.com/chemistry/physical-properties-of-alkenes
      Hope this helps!

    • @yagirlliizziie
      @yagirlliizziie 3 หลายเดือนก่อน

      @@ChadsPrep my apologies, you’re right. I’m using your videos to quickly review before I take the exam and overlooked that. 🤦🏻‍♀️

    • @ChadsPrep
      @ChadsPrep  3 หลายเดือนก่อน

      @@yagirlliizziie Hope you do well on your exam.

  • @banatkhalfan1241
    @banatkhalfan1241 ปีที่แล้ว

    Perfect