Hi sir niraj. What did you do to find z ,1 / sqrt(2) i ? Can you eloborate the point ? I resemble the open circuit stub matching operation but i dont understand this portion
I did explain it during 18:55 to 20:55 but to be more specific for your query, for calculation of z as 1/sqrt(2). I have converted the whole circuit into admittance so that shunt stubs can be easily added. This is like a lambda/4 transformer circuit whose load admittance is 1+j and required input input admittance before left side stub is 1-j so that after adding left side admittance of j it will become 1-j+j=1. That is why I have taken square root of 1-j and 1+j for characteristic admittance of the lambda/4 line. Using this logic for the odd mode analysis too gives 1-j load admittance to be converted into 1+j for impedance matching. Hence characteristics admittance is square root of these two. Finally characteristics admittance is converted into characteristic impedance. Do remember, these values are normalised value. Hope it helps. If you still have query, let me know. Thank you.
Very nicely presented... please make some videos on even and odd mode analysis of Directional coupler, Coupled lines and coupled line C section used in schiffman phase shifter
May I ask what does the B1 to B4 mean in the video, are they related to S parameters? And why we always have a 1/2 before the sum or difference of Gamma, T? Many thanks!
Hi sir niraj. What did you do to find z ,1 / sqrt(2) i ? Can you eloborate the point ? I resemble the open circuit stub matching operation but i dont understand this portion
I did explain it during 18:55 to 20:55 but to be more specific for your query, for calculation of z as 1/sqrt(2). I have converted the whole circuit into admittance so that shunt stubs can be easily added. This is like a lambda/4 transformer circuit whose load admittance is 1+j and required input input admittance before left side stub is 1-j so that after adding left side admittance of j it will become 1-j+j=1. That is why I have taken square root of 1-j and 1+j for characteristic admittance of the lambda/4 line. Using this logic for the odd mode analysis too gives 1-j load admittance to be converted into 1+j for impedance matching. Hence characteristics admittance is square root of these two. Finally characteristics admittance is converted into characteristic impedance. Do remember, these values are normalised value. Hope it helps. If you still have query, let me know. Thank you.
very detailed explanation sir, thankyou for making it easy to understand!
Very nicely presented... please make some videos on even and odd mode analysis of Directional coupler, Coupled lines and coupled line C section used in schiffman phase shifter
Very neatly presented. Easy to understand
Thanks
May I ask what does the B1 to B4 mean in the video, are they related to S parameters? And why we always have a 1/2 before the sum or difference of Gamma, T? Many thanks!
Sir a kind help . While writing the ABCD MATRIX, why are we neglecting the 1 ohm resistance
Sir, what is the need of Zo/ root(2) transmission line. What if we use Zo impedance transmission line?
Excellent sir
are branch line couplers and quadrature couplers same??
Yes
Thanks from Turkey
How did you get the 1+j on the left side of the stub 20:00 ?
See the video again. It's explained clearly.
sift of fase