You're trully a wizard of integrals, your work is marvelous, and I'm trying to learn as much as possible from your videos before entering university, thx man c:
you probably know the result of int 0 to infinity 1/(1+x^n), we can use this here you could've just used the substitution u/(a^(1/2N))=z which is way more simpler
I have been wondering about the following diff. equation y^4 + (y')^4 = y(y')^2 Could you try it for a video some time in the future? Love your videos, keep it up!
Even number of mistakes. U can see at 8:00 that the exponent is correct, then at 8:30, when there is a video cut, he copies the result from the previous line wrong. So the exponent shud read (1-2N)/N = 1/N - 1, i.e: the rest of the solution development and the final answer is still correct
He uses the even-ness of the polynomial in the denominator (when the text goes orange), which isn't going to work if that exponent isn't an even number.
You're trully a wizard of integrals, your work is marvelous, and I'm trying to learn as much as possible from your videos before entering university, thx man c:
I simply love solutions that involve the Beta/Gamma functions and the reflection formula. They make life so easy!
this integral probably wishes it was never born after you mercilessly dissected it and showed it for what it truly is
you probably know the result of int 0 to infinity 1/(1+x^n), we can use this here you could've just used the substitution u/(a^(1/2N))=z which is way more simpler
Hi,
"ok, cool" : 1:03 , 6:43 , 8:29 , 9:26 ,
"terribly sorry about that" : 5:25 , 6:57 , 9:20 , 10:01 .
brilliant as usual, thank you very much indeed.
I have been wondering about the following diff. equation
y^4 + (y')^4 = y(y')^2
Could you try it for a video some time in the future?
Love your videos, keep it up!
How about some quantum mechanics? Might be time to face our fears and find the eigenfunctions of angular momentum.
Kamal, which program do you use when it comes to writing and displaying your solution?
I think the exponent at 8:30 is wrong. (1-2N)/N =/= (1/2N) -1
yes
Even number of mistakes. U can see at 8:00 that the exponent is correct, then at 8:30, when there is a video cut, he copies the result from the previous line wrong. So the exponent shud read (1-2N)/N = 1/N - 1, i.e: the rest of the solution development and the final answer is still correct
Thank you
11:32 alpha must be positive
Can you solve it if N is just some real number?
He uses the even-ness of the polynomial in the denominator (when the text goes orange), which isn't going to work if that exponent isn't an even number.
asnwer=1(x+y)/(x-y)
dam thats crazy
lnx=t..u=-t..I=((πα^(1/2N-1))/2N)cosecπ/2N