y'' + 16y = sec(4x)

Determine the particular solution to the given differential equation y'' + 16y = sec(4x). In other words, find the particular solution to the given non-homogenous differential equation y''(θ) + 16y(θ) = sec(4θ) using variation of parameters with characteristic/auxiliary equations and roots.
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Separable Equations, Integration examples, integral examples, antiderivative examples, differential equations, integral practice problems, calculus 1 practice problems, differential equations practice problems, initial value problem, approximate solution, characteristic equations, auxiliary equations, roots, root solutions, complex roots, method of undetermined coefficients, variation of parameters. James Stewart Single Variable Calculus. Nagle, Saff, Snider Fundamentals of Differential Equations. In Problems 1-8, find a general solution to the differential equation the method of variation of parameters. y'' + 16y = sec(4*theta). y'' + 16y = sec(4t). y''(θ) + 16y(θ) = sec(4θ).
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