Hello Sir, I find at 8:16 the explanation that force gets "stronger and stronger" with the steeper angle of the wedge a little confusing as the same force will instantly disappear when the angle theta turns 90 (in the absence of gravity) , as the jet would be pushing the wedge with purely horizontal component and zero vertical component. Wit further increase in the angle the force will change the sign, thus at angle 90 we see a discontinuity in the force curve.
Hello there. If you listen to what he says right after, he'll add that (quote)" it would be a faulty assumption for high angles", so I guess that would explain the Theta=90° case, though I find it a bit intriguing. You might wanna consider the fact that neglecting some terms in our equations could affect the results. This is an assumption, once again. Have a good day sir. Oh damn, I'm 11 months late XD
what if u2 is different tha U and we are given the function u(x,y), what should we do? does the expression on the second side of the pipe becomes "integral(rho*u(x,y)^2*dA" or "integral(rho*U*u(x,y)dA"?, i ignored the sign here btw.
Small mistake happened here, the pressure is atmosphere, yes, but the outlet pressure force will never cancel that for inlet because of the cosine function found
It is because I moved it to the other side of the equation. I had 0 = termA - termB + f and I rewrote as f = termB-termA It is easy to mess the signs up in these problems so let me know if you think this is still an error.
Thank you so much! Got me un-stumped from about 4 key concepts just by watching examples explained so well!
Thank you so much this really saved me, my lecturer didn't even teach us this but is asking us questions harder than the examples you gave
Thank you so much ! Clear, precise and well paced !
Thanks for uploading......your explaination is great
Thank you very much, sir. I appreciate your effort 💟😊
Very good video! Clarified things for me
Hello Sir,
I find at 8:16 the explanation that force gets "stronger and stronger" with the steeper angle of the wedge a little confusing as the same force will instantly disappear when the angle theta turns 90 (in the absence of gravity) , as the jet would be pushing the wedge with purely horizontal component and zero vertical component. Wit further increase in the angle the force will change the sign, thus at angle 90 we see a discontinuity in the force curve.
Hello there. If you listen to what he says right after, he'll add that (quote)" it would be a faulty assumption for high angles", so I guess that would explain the Theta=90° case, though I find it a bit intriguing. You might wanna consider the fact that neglecting some terms in our equations could affect the results. This is an assumption, once again.
Have a good day sir.
Oh damn, I'm 11 months late XD
22:27 P_atm should be added negative because goes against normal direction and there is still negative sign outside the brackets?
The force Fx in the first sum is the force on the fluid provided to the control volume, Correct?
what if u2 is different tha U and we are given the function u(x,y), what should we do? does the expression on the second side of the pipe becomes "integral(rho*u(x,y)^2*dA" or "integral(rho*U*u(x,y)dA"?, i ignored the sign here btw.
Small mistake happened here, the pressure is atmosphere, yes, but the outlet pressure force will never cancel that for inlet because of the cosine function found
still Patm, doesnt matter about the angle. still 0.
why is the normal at 2 a plus, if its normal to the velocity, shouldn't it also be a negative
At 24.01 the sign of P1 and Patm changes from the previous equation and was wondering why that is?
It is because I moved it to the other side of the equation.
I had
0 = termA - termB + f
and I rewrote as
f = termB-termA
It is easy to mess the signs up in these problems so let me know if you think this is still an error.
I see now thank you
God bless to you. Thanks.
Thank you, this was simple and easy to understand :)
Thank you so much :)
thank you, it is so quickly but ı understand
My hero
thanks
buenardo bro