Hi Justin. Fun question there at the end. I came up with the following set of numbers: 0, 1, 2, 3, 3, 10 mean = (0+1+2+3+3+10)/6 = 19/6 = 3,17 mode = 3 median = (2+3)/2 = 2.5 I think this is the minimum set with median < mode < mean.
I'm thinking of incomes in a banana republic. Comrade El Presidente has a huge salary pushing the mean way up into the Stratosphere ... All govt employees have the same fixed salary giving a high frequency for the mode and then a huge swathe of poor with various meagre salaries pulling the median below the mode ...
you confused me at 3:44 you said mode is calculated by selecting 2 matching numbers and now here you are taking mode as highest frequency? how also how you calculated median and mean fully confused
Which measure of location will be suitable to compare, a. Heights of students in two classes, b. Size of agricultural holding, c. Average sales for various years, d. Intelligence of students, e. Per capita income in several countries, why?
Thank you for amazing videos. I have a doubt that finally, with a distribution where all samples have the same frequency, let's say 1, each sample can be a MODE?
Sounds like a square distribution. Measuring a mode for it has no meaning. As a statistician it's your job to pick the most representative data to show the reader.
We asked 10 people, how many ice creams they wanna have for free. 1 person answered 1, 2 persons answered 2, 2 persons answered 3, 3 persons answered 4, 1 person answered 5 and 1 person answered 30! 1+2+2+3+3+4+4+4+5+30 median: 3,5 (between 3 and 4) mode: 4 (the most wanted choice) mean: 5,8 (the average demand)
If you wanted to do the calculation without weighting, you would need to take the mean over all 5 million numbers. Not a problem for computers, but would be practically impossible using pencil and paper. Weighting lets us calculate the mean from a much more compact data format.
so how I calculated it was: credits carry more value than percent because you can sore high marks on a low credit level and still fail because it is weighted low. hence i worked out the maximum amount of credits that she can score per test. if 65% gives you 4 credits how much would 100% give you. with only one variable you can work it out. 65/100 *4/x this gives you 6.1 but as with credits you either get it or you don't so you have to round it up to the following number making it 7. calculate each maximum credit score giving you 28 possible credits. take the amount of credits she scored 20 and divided by max amount of credits times a 100. gives you 71.4%. so she is on average able to score 71.4% of the possible credits no matter the test difficulty or size.
Hi Justin. Fun question there at the end.
I came up with the following set of numbers:
0, 1, 2, 3, 3, 10
mean = (0+1+2+3+3+10)/6 = 19/6 = 3,17
mode = 3
median = (2+3)/2 = 2.5
I think this is the minimum set with median < mode < mean.
that's what I came up with too
exactly what I came up with!
1, 1, 2, 2, 3, 3, 3, 10
Median - 2.5
Mode - 3
Mean - 3.125
I like how you "tempt" people to try out the exercise :)
😂
If you can communicate correctly, you also can do this. Majority are moldable very easily
I'm thinking of incomes in a banana republic. Comrade El Presidente has a huge salary pushing the mean way up into the Stratosphere ... All govt employees have the same fixed salary giving a high frequency for the mode and then a huge swathe of poor with various meagre salaries pulling the median below the mode ...
you confused me at 3:44 you said mode is calculated by selecting 2 matching numbers and now here you are taking mode as highest frequency? how
also how you calculated median and mean fully confused
Which measure of location will be suitable to compare, a. Heights of students in two classes, b. Size of agricultural holding, c. Average sales for various years, d. Intelligence of students, e. Per capita income in several countries, why?
Here is another set of number: 0,1,2,3,4,4,9,10
Mean: 4.125
Mode: 4
Median: 3.5
Coincidently i got the same value bro😁😁
Got the same one mate!
Thank you for amazing videos. I have a doubt that finally, with a distribution where all samples have the same frequency, let's say 1, each sample can be a MODE?
Sounds like a square distribution. Measuring a mode for it has no meaning. As a statistician it's your job to pick the most representative data to show the reader.
Datapoint = [1,5,5,5,3,3,5,50,2] Mode = 5, Median = average of 3 and 5 which is 4, Mean = 8.2. Median
50 is not an interger between 0&10
Brilliant - I always found statistics confusing, but your explanations are very clear, Thank you.
CHALLENGE QUESTION:
{8,8,8,9,10}
MODE: 8 with Highest frequency.
Median: With 5 data, 8 is in the middle.
Mode: 8+8+8+9+10 / 5 = 43/5 = 8.6.
MEDIAN = 8 < MODE=8 < MEAN=8.6.
1,2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 10, 10, 10
median = 3.5
mode= 4
mean= 4.4
My guess is 0,1,2,3,4,5,6,6,7,8,9,10
Median=5.5
Mode=6
Mean=6.1
Median
We asked 10 people, how many ice creams they wanna have for free.
1 person answered 1, 2 persons answered 2, 2 persons answered 3, 3 persons answered 4, 1 person answered 5 and 1 person answered 30!
1+2+2+3+3+4+4+4+5+30
median: 3,5 (between 3 and 4)
mode: 4 (the most wanted choice)
mean: 5,8 (the average demand)
for census example, why its weighted mean is calculated and not the mean calculation?
because of the frequencies involved. The example asked to derive the mean number of children. Btw can you tell me, why the median is two here?
If you wanted to do the calculation without weighting, you would need to take the mean over all 5 million numbers. Not a problem for computers, but would be practically impossible using pencil and paper. Weighting lets us calculate the mean from a much more compact data format.
Flip the tail of an asymmetric distribution.
I love your voice!
My set is 2 2 1 10
The mean is 3.75
The mode is 2
The median is 1
So the mean is greater than mode which is greater than the median
Your median is (2 + 2) / 2 = 2
0, 0, 1, 1, 2, 2, 2, 9
median = 1.5
mode = 2
mean = 2.125
Thank you
Quite too late for this but , here is some values
6 6 5 6 10
median = 5
mode = 6
mean = 6.6
Great Learning.. Thanks
1.0 ,1.5 ,1.6 ,3.0 ,3.6 ,0.6
Mean = 0.64
Median = 1.55
Mode = 2 child
1,2,3,4,4,10
(7,8,8)---> this is the nearest answer
so how I calculated it was:
credits carry more value than percent because you can sore high marks on a low credit level and still fail because it is weighted low.
hence i worked out the maximum amount of credits that she can score per test.
if 65% gives you 4 credits how much would 100% give you. with only one variable you can work it out.
65/100 *4/x this gives you 6.1 but as with credits you either get it or you don't so you have to round it up to the following number making it 7. calculate each maximum credit score giving you 28 possible credits. take the amount of credits she scored 20 and divided by max amount of credits times a 100. gives you 71.4%. so she is on average able to score 71.4% of the possible credits no matter the test difficulty or size.
3, 3, 3, 4, 4, 10
0, 1, 2, 3, 3, 10
2,3,4,3,1
4,4,3,5,6
median is 3
mode is 4
mean is 4.4
1,1,2,0,10,1,1 here mode is 1 median Is 0 and mean is 2.28