Using the same reasoning it can be easily deduced that the sum of n(exp)i, for i=0 to m, is (n(exp)(m+1)-1)/(n-1).
解答は2^23ー１でいいのではないか。
Using the same reasoning it can be easily deduced that the sum of n(exp)i, for i=0 to m, is (n(exp)(m+1)-1)/(n-1).
解答は2^23ー１でいいのではないか。