Check the unified chemistry exam papers - they keep bringing up a tweak to electrophilic substitution which uses carbon dioxide. I’ll see if I can post a video on this tomorrow.
Thank you for the video- at 6:51 can anyone explain why the lone pair moves to the space between the O- and the S to form the extra bond, and not to the S directly like with the -OH nucleophile in part one does?
Hi there - good question. When the Nucleophile attacks the S atom in stage 1 it forms a brand new sigma bond between the O and S atoms. In the other stage (when the electron pair moves to the space between the O and the S in stage 2) there is already a sigma bond between the two atoms. Therefore when forming the new bond (a pi bond) we direct the electrons to the space between the 2 atoms instead. (Please note that there are still some rare tweaks to this kind of rule e.g. the diels alder reaction which has come up recently but they did show an example of the tweaked version)
Check out this summary of ALL the OCR Curly Arrow Mechanisms = th-cam.com/video/PQPQud8POB4/w-d-xo.html
can’t believe i’ve discovered this channel the day before my exam 😭
There’s still paper 3 too!
@@mrmurraygreen thanks i’ll be coming back. your videos are really good 🙏🏽
thank you! i was literally gonna ask for this video haha
also do you know where we'd be able to do unfamiliar reaction mechanics practice? thanks!
Check the unified chemistry exam papers - they keep bringing up a tweak to electrophilic substitution which uses carbon dioxide. I’ll see if I can post a video on this tomorrow.
@@mrmurraygreen thank you so much im so appreciative of all the effortt u put in to help us :)
Thank you so much for this ❤
Thank you for the video- at 6:51 can anyone explain why the lone pair moves to the space between the O- and the S to form the extra bond, and not to the S directly like with the -OH nucleophile in part one does?
Hi there - good question.
When the Nucleophile attacks the S atom in stage 1 it forms a brand new sigma bond between the O and S atoms.
In the other stage (when the electron pair moves to the space between the O and the S in stage 2) there is already a sigma bond between the two atoms. Therefore when forming the new bond (a pi bond) we direct the electrons to the space between the 2 atoms instead.
(Please note that there are still some rare tweaks to this kind of rule e.g. the diels alder reaction which has come up recently but they did show an example of the tweaked version)
⭐️⭐️