I should also mention that the "memory" I am talking about here is not the permanent deformation that you get from stretching out a balloon for the first time. The type I am showing is totally repeatable every time you blow up a balloon. Notice how the latex band went back to its original position so it was not permanently deformed.
The Action Lab I have a question I means that pressure inside a balloon is even greater than the atmospheric pressure as air expelles out in the atmosphere
Elastic structures like rubber bands and balloons are internally compressed when you stretch them out. So Even though the balloon with air in it has more total volume, the physical bounds of the rubber itself decrease. So, the thin shell of rubber has less overall volume than it's previously uninflated state. It's unintuitive to think about compression when you are stretching something but that's what happens with elastic. The spike in pressure when blowing up a balloon is probably the quantum amount of force required to overcome the rubber's inertia and is likely equal to the maximum amount of force that the rubber can exert when fully internally compressed. As the balloon stretches the surface area increases so the psi goes down, but the total pressure required to resist the elastic potential (the internal inertia of the rubber) should remain nearly the same since the total volume of rubber is the same and it's internal matrix has a fixed action potential (at least relative to the integrity of the rubber itself). When you release the air from the balloon the air pressure just decreases because it doesn't have the same quantum of inertia to overcome. When you inflate the balloon past it's maximum potential to store pressure you begin to break internal bonds in the rubber itself and it loses some of it's overall capacity to store energy in it's internal matrix (you get a stretched out and potentially busted balloon). Subsequent inflations are easier because the overall capacity to store energy is decreased and the quantum of inertia is lowered, thereby less pressure is required (or should be you can test it out). Also, when you inflate a balloon or stretch a rubber band it heats up (since it's being internally compressed and it's entropy decreases as the molecules line up) and when you release the tension it cools down (since it's being expanded). Just some cool things to think about.
"Okay, what's your guess?" "I bet it will get smaller" "Okay, give me a min to blow more air into it and then release it, so we can see what will happen" "Sure thing, nothing suspicious about that"
you might be able to get away with blowing it up less then that and then "accidentally" releasing some air, or maybe subtly releasing some air without anyone noticing, while you put it on the tube.
Now I'm thinking if there's any difference between pumping car tires right away to the required pressure vs. pumping above the required pressure first, then release some air to meet the required pressure.
Tires are made from an extremely different material, they should NOT behave this way! Both are referred to as "rubber", but a tire is made from a fully cross-linked polymer that will have far more stable and predictable properties under various stress conditions.
@@ionic_iris I agree. Not to mention with the tires being belted it' takes a good amount of pressure to increase the size once its reached the recommended psi. As opposed to when they are deflated, you can start to see a size increase fairly quickly because you are not fighting the actual material at that point.
@The Action Lab: I can help describe what you are seeing with the stress/strain curve a little bit better - including the why the release at the end acts like it does (I have a Masters in Mechanical Engineering). The first part of the curve (before the first peak) is the “elastic section.” While you are blowing up the balloon here, the balloon’s deformation is completely elastic and should always return to its original state. Interestingly enough, you can actually predict the exact slope of this line with some simple material properties. If you let the air out before reaching the peak, it will follow this exact line back. It will continue to expand elastically until it reaches the first peak - or “Yield Stress” at which the balloon’s plastic will yield, and start to permanently deform. At this point, you have started to permanently alter the bonds of the rubber, and so the rubber becomes weaker, allowing the balloon to continue to expand, even at a lower pressure. As you continue to inflate, the pressure required will start to rise. You are correct in saying that the balloon will not expand much more at this point. At a certain point, it would, of course, go past its limit and pop. Now, for when you let the air out and release the pressure: Despite all of the permanent (plastic) deformation, the material is still elastic, and still has similar elastic properties, despite the massive deformation. Therefore when you let the air out, it will still being to return to its original shape BUT ONLY the amount within its elastic region. Any deformation that occurred after the point that the material yielded (changing from elastic deformation to plastic deformation) is permanent. The curve will then follow roughly the same slope as the original line back, because it is returning from its elastic deformation. Therefore, it will form a line parallel-ish (theory vs actuality) to the elastic region, but start from where the permanent/plastic deformation ended. Great video! This is really cool stuff!
Nice explanation! I have a question, according to the stress strain diagram, 80% of the elongation of the balloon was in plastic region (and 20% in elastic). But when we deflate it, the size of the balloon decreases more than 20% (as if it's elastic region was more than 20%) Why is this so?
Sorry but rubbers don't behave that way. What you've described is the typical behavior of metals. Kindly lookup stress strain diagrams for latex rubbers and you'll realize there's no peak there. It's good to know a theory but it is just as important to know what it describes and its limitations. (I have a master's in materials science and am doing my PhD, these degrees mean nothing if the person has poor understanding of the fundamentals)
So to recap. Balloon 🎈 is difficult to blow up in the beginning. Everybody should know that. This increases pressure until the balloon 🎈 suddenly start to expand making the pressure go down. When releasing pressure same happens just reverse. The interesting 🤔 part is that if the two balloons 🎈 both are beyond this point then the pressure is the same inside and nothing happens. If one balloon 🎈 is below its “I don’t a want to be inflated point” then it will release its air into the other. Right?
I think it would be informative to check the pressure again with the probe further into the balloon and with the flow rate decreased. That fast flow of air out with the probe near the neck of the balloon is going to result in a lower pressure because fluid flow causes decreased pressure. It seemed like you were attributing that pressure drop solely to the elastic of the balloon. Perhaps you could make a disk with two holes, one for the pressure probe, and one to let air out. If the probe is deep in the balloon and you get nice laminar flow when you release the air, the probe should be mostly unaffected by the effect of flowing fluid showing a decreased pressure, as in the video that probe was definitely seeing a lot of turbulent flow.
I must say, I would have never guessed this! Good thing I didn't do one of my before video predictions lol. Just a nice reminder that you need to actually do the experiment before saying what will happen. I would have told someone that the pressure will always increase due to the increased tensional forces. Great video!
Well said! And I would've agreed with you. Now, I'm thinking it may have to do with the geometry of 3d shapes, seeing as volumes increases at a greater rate than surface area, the complexity of elastic materials' molecular structures, and other outside factors like heat. Really shows how these materials have more dynamic properties than I previously thought. Science!
I guessed it correctly because I always know blowing up a balloon is so damn hard initially and then gets so much easier. But I don't get the $20 so it was still pointless :(
Awesome video! But also something you kind of know in the back of your head if you have blown up balloons: it’s hard to get started, but once you get past a certain point it gets easier. Would love to see a follow up video from some polymer scientist explaining what happens on a molecular level.
This is a very good representation of how a hysteresis acts in real life. You have a talent in visualizing things with easy experiments everyone can understand.
You’re always patient with explaining your works. Sometimes your explanations take long because just like this video, what seems simple to people actually involves some beautiful traits of nature like Hysteria. But you are always able to explain it to a non-scientist people like us because you don’t skip details. You’re the science teacher I needed in high school. I like your channel.
Our physics teacher did this on the first day... everyone thought wrong! It is because the elasticity in the green one is more forceful, and closer to being normal, so it pushes the air to the other one, which is already blown up a lot, so no resistance holding it back from going in there
Wow! I am watching this video about one year later and you now have 1.5M subscribers. You gained 1M subscribers in one year, that's awesome! Keep up the good videos.
I have a different perspective as why this happens. It's simple when initially you blow up the balloon the rubber is not yet stretched so it requires more force/pressure to blow up the balloon. As the balloon fills with air the rubber stretches and becomes thinner so the pressure falls. Than it reaches its max stretch and the pressure strats to build up again. So in my opinion if you choose a balloon from the first state (initial infation) or last state (max stretch) and connect it with a balloon from state two (rubber is thin but not at the limit) you will always get the same results I don't think this happens because of hysteresis. Let's have a discussion here 😊
This was actually my same thought. You'd have to experiment and see if you can go back and forth on the memory. He never showed this, only the stretching effect. So it could be just stretching, and then it's just stretched, end of story.
I love those weird experiments you do. Not only they're really entertaining, but I also feel that they get me smarter everytime I watch them. (sorry for the bad English).
This particular physics also saved the lives of many babies apart from winning bets apparently. Vid by MinuteEarth th-cam.com/video/CJQlgrlB29M/w-d-xo.html
7:45 *elastomer. Rigid bodies are more elastic, for example steel is more elastic than rubber!! Elastomers are material which can be stretched a lot from a given force.
I LOVE DIS im really into physics! my dad had a professer that teached physics and still does. Im 10 and im going and learning from that professer every week! its fun!
At 4:48 I noticed something interesting. On the return journey of the latex band, it actually follows Kx=Mg equation. Notice how the green separations almost divide the 0 to 3 region in 3 equal parts (within the errors of measurement)
This was a lot more interesting than I thought it would be, yay. Congratulations on hitting 500K subscribers. It is so well deserved. Happy New Year to you and yours and thank you so much for all the videos you brought us in 2017. Best wishes for 2018
Very Interesting! I didn't realize how much hysteresis rubber has! I'd like to see how the pressure changes the second, third, and fourth time you blow up the same balloon!
"This should be really weird to you..." Nope. I mean, the balloon gets bigger. It can't have more pressure while expanding, that's not how density works. Nice try though.
With low pressure you vaccum destill the water leaving pure hydrogen peroxide 30% H2O2 ist quite dangerous (if you get some on the skin you can see it dying and getting white and peling off (+pain) 99% h2o2 sets stuff on fire....
Totally makes sense, balloons are hard to blow up at first but as soon as it starts to stretch, it gets easy. Not actually that surprising but very interesting!
GREAT VID !! I strong suspected right away the balloon of different sizes would have same internal pressure because the larger volume does not mean larger pressure. Sure the overall surface area pressure added up is larger, but then, it's over a larger area ! I think the blowing-up-spike is related to the wall being thicker when it's smaller..it takes more 'overpressure' to stretch it to thinner, but that amount required decreases as it gets larger (thinner). But you're not measuring flow which is increasing sorta as a ballon '2x' big will have like 4x volume or something conceptually (I forget the formulas). So I'm blown away by the 2 difference scenarios, and that thing 'memory' (elastic hysteresis) I will have to study that for a long time to get and intuitive grasp! I'm not a human calculator nor do I use formulas, because I'm not required to, lol, But, like many of us, I love to form mental models of behaviors that are pretty good. I think maybe if you stopped in the middle of the initial inflate effort it would not stay at that spike pressure but drop to an intermediate pressure? Kinda like conceptually 'stretch inertial' but that's maybe too loose a way to use the term inertial. It would be interesting and informative to do test inside a vacuum. That would take less pressure of course, but I'm curious if there would be any differences in the overall basic behavior. I think this would be different with different materials? Like metal springs?
I would like to add the reason why the balloon loses elasticity when inflating. When you first have the uninflated balloon, the moleculair chains are oriented like spaghetti in a bowl, twisted in eachother with no order. When you inflate the balloon, the moleculair chains get stretched untill they lie straight. During the straightening the elasticity is high (which you can see in the part just after the spyke in the graph). After that the moleculair chains are straight and then you are actually trying to pull the molecules apart. The moleculair bounds are much more rigid and thus the elasticity goes down and the volume doesnt increase as much anymore and thus the pressure goes up more quickly. As demonstrated with the elastic band and waterbottle experiment, when you relax the plastic afterwards the elasticity of the moleculair chains is pulling the plastic back into shape but that elasticity is lower because the chains dont go back to the chaos spaghetti orientation. And thus the weights arent pulled as far back as they stretched. When you deflate the balloon and leave it alone for a while the chains will become loose and relaxed again and so it will behave again like I described in the beginning after a while. Btw, Sorry for my English and I hope my story made sense XD English is not my first language :)
It starts there if you want to ignore the actual learning part. Thoght don't take this as an insult the science is just cool and deserves to be watched.
Science is a field of study. It's not the reality of how things work. This isn't because of science, it's because it's just how it works. Science figured it out, but it happening has nothing to do with science. This is how you tell when someone holds modern science as their religion.
And what are you calling BS on? I don’t even know what point you are trying to make. I constantly say “science”? I already regret responding to this troll...help me🤦🏻♂️
It makes sense how the pressure in the baloon would decrease over time after a point considering its easier to blow a balloon later on than the earlier stages, but can you give any reasons as to why that happens
Thanks for the comments. Im hard of hearing, mostly typical responses, we are okay to heck with everyone else. Hope you nevet lose your hearing fighting for your country.
Your videos are so cool that i can’t stop watching them. İ mean wo doesn’t like sience! ( if you don’t like sience why are you even watching this video )
Isnt it just simpler to explain the ruber is stretchier when it heats up from deformation? That explains the hanging bucket. Also you didnt let it cool down either way.
I should also mention that the "memory" I am talking about here is not the permanent deformation that you get from stretching out a balloon for the first time. The type I am showing is totally repeatable every time you blow up a balloon. Notice how the latex band went back to its original position so it was not permanently deformed.
The Action Lab i subscribed ❤
The Action Lab I have a question I means that pressure inside a balloon is even greater than the atmospheric pressure as air expelles out in the atmosphere
Amit Kumar, yes pressure in the balloon is greater than the atmospheric pressure
The Action Lab wow thanks
Elastic structures like rubber bands and balloons are internally compressed when you stretch them out. So Even though the balloon with air in it has more total volume, the physical bounds of the rubber itself decrease. So, the thin shell of rubber has less overall volume than it's previously uninflated state. It's unintuitive to think about compression when you are stretching something but that's what happens with elastic. The spike in pressure when blowing up a balloon is probably the quantum amount of force required to overcome the rubber's inertia and is likely equal to the maximum amount of force that the rubber can exert when fully internally compressed. As the balloon stretches the surface area increases so the psi goes down, but the total pressure required to resist the elastic potential (the internal inertia of the rubber) should remain nearly the same since the total volume of rubber is the same and it's internal matrix has a fixed action potential (at least relative to the integrity of the rubber itself). When you release the air from the balloon the air pressure just decreases because it doesn't have the same quantum of inertia to overcome. When you inflate the balloon past it's maximum potential to store pressure you begin to break internal bonds in the rubber itself and it loses some of it's overall capacity to store energy in it's internal matrix (you get a stretched out and potentially busted balloon). Subsequent inflations are easier because the overall capacity to store energy is decreased and the quantum of inertia is lowered, thereby less pressure is required (or should be you can test it out).
Also, when you inflate a balloon or stretch a rubber band it heats up (since it's being internally compressed and it's entropy decreases as the molecules line up) and when you release the tension it cools down (since it's being expanded). Just some cool things to think about.
6:32 "And then here's what happens if you keep blowing up the balloon" I was half-expecting you'd literally keep going until it popped in your face.
That would have been the right thing to do. I'm utterly disappointed.
I was so nervous
Same lmao
"Okay, what's your guess?"
"I bet it will get smaller"
"Okay, give me a min to blow more air into it and then release it, so we can see what will happen"
"Sure thing, nothing suspicious about that"
you might be able to get away with blowing it up less then that and then "accidentally" releasing some air, or maybe subtly releasing some air without anyone noticing, while you put it on the tube.
What if you ask the question first and then setup the equipments
Just be like oh I forgot this ones not supposed to be the same size
Accidentally release all the air, blow it up too much and then they'll be like "hey no, it was smaller before", then release just some of the air.
LMAO
Robin: "Why does it work?"
Batman: "Because science!"
Robin: *mind blown*
Bat Man your profile picture goes so well with it 😂
"because I'm rich"
Sanskar Teotia more money than Donald trump.
"Because im batman"
The problem is they didn’t give me my money.
Send someone to break their thumbs
The Action Lab😂😂😂
Call Nino.... He would clean him up
The Action Lab i bet u he already broke their ears, arms, and legs
yes their legs
Rekt
Man, i learn so much from this channel! Thank you!
John Cena nice meme
Are you the real John Cena.
Clorox Bleach that’s the whole point🤦🏾♂️
John Cena says you can’t see me
Kennibone Pretty sure clorox is trolling
John Cena so r u the creator of rdkube
i've discovered something incredible.
6:45 as the volume of the baloon increases, the volume of my headphones decreases
Exactly😆
Now I'm thinking if there's any difference between pumping car tires right away to the required pressure vs. pumping above the required pressure first, then release some air to meet the required pressure.
Egarolla
If you inflate tires so much they visibly change shape, then yes.
Well according to this, they will be slightly larger in size if you inflate then deflate
(As they'll need more air to keep the same pressure)
Tires are made from an extremely different material, they should NOT behave this way! Both are referred to as "rubber", but a tire is made from a fully cross-linked polymer that will have far more stable and predictable properties under various stress conditions.
@@ionic_iris I agree. Not to mention with the tires being belted it' takes a good amount of pressure to increase the size once its reached the recommended psi. As opposed to when they are deflated, you can start to see a size increase fairly quickly because you are not fighting the actual material at that point.
Tires have significantly less elasticity per surface area than the balloon rubber so the effect is likely greatly diminished.
This really "blows" me away...
DO2 N.G.M The only thing that blows is that joke.
Macy Lane What even blows better is your mom
I'm crying 😂
Lets not BLOW things out of proportion.
Get ready to get the wind knocked outta ya... don’t be surprised if you explode. Heh.
@The Action Lab: I can help describe what you are seeing with the stress/strain curve a little bit better - including the why the release at the end acts like it does (I have a Masters in Mechanical Engineering).
The first part of the curve (before the first peak) is the “elastic section.” While you are blowing up the balloon here, the balloon’s deformation is completely elastic and should always return to its original state. Interestingly enough, you can actually predict the exact slope of this line with some simple material properties. If you let the air out before reaching the peak, it will follow this exact line back.
It will continue to expand elastically until it reaches the first peak - or “Yield Stress” at which the balloon’s plastic will yield, and start to permanently deform. At this point, you have started to permanently alter the bonds of the rubber, and so the rubber becomes weaker, allowing the balloon to continue to expand, even at a lower pressure.
As you continue to inflate, the pressure required will start to rise. You are correct in saying that the balloon will not expand much more at this point. At a certain point, it would, of course, go past its limit and pop.
Now, for when you let the air out and release the pressure: Despite all of the permanent (plastic) deformation, the material is still elastic, and still has similar elastic properties, despite the massive deformation. Therefore when you let the air out, it will still being to return to its original shape BUT ONLY the amount within its elastic region. Any deformation that occurred after the point that the material yielded (changing from elastic deformation to plastic deformation) is permanent. The curve will then follow roughly the same slope as the original line back, because it is returning from its elastic deformation. Therefore, it will form a line parallel-ish (theory vs actuality) to the elastic region, but start from where the permanent/plastic deformation ended.
Great video! This is really cool stuff!
Nice explanation!
I have a question, according to the stress strain diagram, 80% of the elongation of the balloon was in plastic region (and 20% in elastic). But when we deflate it, the size of the balloon decreases more than 20% (as if it's elastic region was more than 20%)
Why is this so?
Sorry but rubbers don't behave that way. What you've described is the typical behavior of metals. Kindly lookup stress strain diagrams for latex rubbers and you'll realize there's no peak there. It's good to know a theory but it is just as important to know what it describes and its limitations. (I have a master's in materials science and am doing my PhD, these degrees mean nothing if the person has poor understanding of the fundamentals)
You must be fun at parties.
The party don’t start till I walk in...
The Action Lab lol
lol so true!
Santiago Ferrari I can shoot a milk dud from my ass 15 feet across a room
Kevin Durant 2017 NBA Finals MVP Um...buddy, it wasn't a milk dud. 😩
A youtuber with brain, thank God hahaha ❤ I watch every video, love you
Check out smarter every day channel as well, you’ll like it👍
Action Lab taught me the art of the Hustle 💰💰
Figgie Smalls haha dank profile
cody hedges ty m8
Hey everybody have this same picture you do , where is this from?
So to recap. Balloon 🎈 is difficult to blow up in the beginning. Everybody should know that. This increases pressure until the balloon 🎈 suddenly start to expand making the pressure go down. When releasing pressure same happens just reverse.
The interesting 🤔 part is that if the two balloons 🎈 both are beyond this point then the pressure is the same inside and nothing happens. If one balloon 🎈 is below its “I don’t a want to be inflated point” then it will release its air into the other. Right?
*NOICE*
Nigel 100, Nice or Noise?
@@henrik-j1l **Snap** NOICE
this nerd deserves more subscribers, honestly.
yep love this nerd
He's not a nerd just scientifically smarter than you
Now he has 2 mil subs
Now 3.8m
4.51m
You're wrong
I got it right in the second time I saw it!
There you are, people have been asking where you were
The Action Lab
Well now they know!
Pro Player 1⃣ missed you
TryChan
Yo you even changed your pfp
How ya doing
Pro Player 1⃣ good ... i get trought puberty thats why ;)
Please put bubble wrap in vacuume chamber
Sparsh Arora smart thinking
Sparsh Arora it will just explode and not even make the satisfying pops (sound)
Sparsh Arora it will just pop and that will be the end
Sparsh Arora nice idea... like his comment so he can see it
Sparsh Arora no he should put a vacuum inside a vacuum chamber that's inside a vacuum chamber.
"It's not a trick. It's science"
**explains the science so you know how to do the trick**
I think it would be informative to check the pressure again with the probe further into the balloon and with the flow rate decreased. That fast flow of air out with the probe near the neck of the balloon is going to result in a lower pressure because fluid flow causes decreased pressure. It seemed like you were attributing that pressure drop solely to the elastic of the balloon.
Perhaps you could make a disk with two holes, one for the pressure probe, and one to let air out. If the probe is deep in the balloon and you get nice laminar flow when you release the air, the probe should be mostly unaffected by the effect of flowing fluid showing a decreased pressure, as in the video that probe was definitely seeing a lot of turbulent flow.
Thanks!
Good job. The correct pronunciation is: hista-reesis.
Guess we need to change the saying, "Is the balloon half full or half empty."
😂😂😂😂
I must say, I would have never guessed this! Good thing I didn't do one of my before video predictions lol. Just a nice reminder that you need to actually do the experiment before saying what will happen. I would have told someone that the pressure will always increase due to the increased tensional forces. Great video!
Yeah this one was really interesting for me!
Well said! And I would've agreed with you. Now, I'm thinking it may have to do with the geometry of 3d shapes, seeing as volumes increases at a greater rate than surface area, the complexity of elastic materials' molecular structures, and other outside factors like heat. Really shows how these materials have more dynamic properties than I previously thought. Science!
I said it will maintain homeostasis.
I guessed it correctly because I always know blowing up a balloon is so damn hard initially and then gets so much easier. But I don't get the $20 so it was still pointless :(
Awesome video! But also something you kind of know in the back of your head if you have blown up balloons: it’s hard to get started, but once you get past a certain point it gets easier. Would love to see a follow up video from some polymer scientist explaining what happens on a molecular level.
3:40 Damn, Thought you were going to do some Bottle Flipping trick shots!
You might be my favorite science TH-camr
1 Consistent
2 Concise yet coherent
3 I now know a fun party trick
Everything is great except when you say pressure in pounds per square inches 🙂
Deflated baloon will deflate, inflated baloon will inflate... now let's watch the video.
3:23 oh I 'member
edit: anyone got the reference?
theodor bourelius member berries
I member
MEMBER BERRIES!!!!!
I member
This is a very good representation of how a hysteresis acts in real life.
You have a talent in visualizing things with easy experiments everyone can understand.
Appears that the latex string didn't remember where it was earlier!😂😂🤣🤣
You’re always patient with explaining your works. Sometimes your explanations take long because just like this video, what seems simple to people actually involves some beautiful traits of nature like Hysteria. But you are always able to explain it to a non-scientist people like us because you don’t skip details. You’re the science teacher I needed in high school. I like your channel.
Thanks for your channel man, you’re my favorite youtuber! All your videos are brilliant and interesting!!!
The hint was actually helpful! I guessed it would decrease in size because that seemed counterintuitive
Is it just me I got this in recommendations after 3 years
Me also bro😅
congratulations on the 500,000 subs! way to go!
Our physics teacher did this on the first day... everyone thought wrong! It is because the elasticity in the green one is more forceful, and closer to being normal, so it pushes the air to the other one, which is already blown up a lot, so no resistance holding it back from going in there
From this channel i learned a lots of things ,please make more videos like this
Could have said every bit of this with.. "it stretches the rubber"
The age old question - "How to scam people with balloons?", finally got its answer.
7:05 One of the scariest things in the first world. 😁
Wow! I am watching this video about one year later and you now have 1.5M subscribers. You gained 1M subscribers in one year, that's awesome! Keep up the good videos.
I got $25 ...😂😂😂
Lol good for u
Well, u have 2M now, good job, love ur videos and keep up the good work
3 million!
I have a different perspective as why this happens.
It's simple when initially you blow up the balloon the rubber is not yet stretched so it requires more force/pressure to blow up the balloon.
As the balloon fills with air the rubber stretches and becomes thinner so the pressure falls.
Than it reaches its max stretch and the pressure strats to build up again.
So in my opinion if you choose a balloon from the first state (initial infation) or last state (max stretch) and connect it with a balloon from state two (rubber is thin but not at the limit) you will always get the same results
I don't think this happens because of hysteresis.
Let's have a discussion here 😊
This was actually my same thought.
You'd have to experiment and see if you can go back and forth on the memory. He never showed this, only the stretching effect.
So it could be just stretching, and then it's just stretched, end of story.
Wow! Never knew balloons were so smart! 😂
Gave me serious anxiety when you kept blowing that balloon up… ☹️
I love those weird experiments you do. Not only they're really entertaining, but I also feel that they get me smarter everytime I watch them.
(sorry for the bad English).
You said I was wrong, but I'm right.
"...because balloon has a memory" LOL😂😂😂😂😂😂
This particular physics also saved the lives of many babies apart from winning bets apparently. Vid by MinuteEarth th-cam.com/video/CJQlgrlB29M/w-d-xo.html
That is awesome! Thanks for sharing!
7:45 *elastomer.
Rigid bodies are more elastic, for example steel is more elastic than rubber!!
Elastomers are material which can be stretched a lot from a given force.
Can I still bet on the green baloon and win, with a blue and red one? 🤔
Nah fam just say the green one will decrease in size and pop it
hornetluca
🤦♀️ yeah, colours don't mean shit
@@greendayatthedisturbed3099 woooosh
James, in all my classes in engineering , the word was pronounced, his-ter-eee-sis .
I love this channel .
I LOVE DIS
im really into physics!
my dad had a professer that teached physics and still does. Im 10 and im going and learning from that professer every week! its fun!
A newborn's lungs sorta do the same thing when they're born. It's pretty cool
You- "I wrote a little program for my pressure measuring machine"
Me....I can't even write a thank you card :/
At 4:48 I noticed something interesting. On the return journey of the latex band, it actually follows Kx=Mg equation. Notice how the green separations almost divide the 0 to 3 region in 3 equal parts (within the errors of measurement)
Very good video, lots of interesting information that I could do better off with knowing
This was amazing! When I tried to work it out before getting the answer, the piece missing was the elastic hysteresis. So cool!
5:20 dont waste time
This was a lot more interesting than I thought it would be, yay.
Congratulations on hitting 500K subscribers. It is so well deserved.
Happy New Year to you and yours and thank you so much for all the videos you brought us in 2017.
Best wishes for 2018
Had I the memory of a baloon........
Very Interesting! I didn't realize how much hysteresis rubber has! I'd like to see how the pressure changes the second, third, and fourth time you blow up the same balloon!
"This should be really weird to you..."
Nope. I mean, the balloon gets bigger. It can't have more pressure while expanding, that's not how density works.
Nice try though.
If the rubber acted like a metal or most other materials that follow Hooks law, the volume and pressure would both increase as you blew in more air.
Also, you feel the pressure in your mouth, so everybody who's ever blown up a balloon should be familiar with this initial spike.
I love your channel so much. Very educational and entertaining. Hard combo to do. Props man. Keep the content flowing
Put hydrogen peroxide in a vacuum chamber!
It's Ethan! water?
With low pressure you vaccum destill the water leaving pure hydrogen peroxide
30% H2O2 ist quite dangerous (if you get some on the skin you can see it dying and getting white and peling off (+pain)
99% h2o2 sets stuff on fire....
Wow. Despite being an engineer I failed this test. What a shame !
Kudos to you, Man !!👌
It solidified my concept of hysteresis too.
I lost 20$ :/
He got confused
@Dylan Prothero instructions unclear
Totally makes sense, balloons are hard to blow up at first but as soon as it starts to stretch, it gets easy. Not actually that surprising but very interesting!
They may both be smart, but NEITHER of them could spell the word BALLOON!!!
So smart and you should have your own tv show 👍
7:02 It chapter 2 Flashbacks
Really informative man! Thanks :)
We call it plastic and elastic deformation
GREAT VID !! I strong suspected right away the balloon of different sizes would have same internal pressure because the larger volume does not mean larger pressure. Sure the overall surface area pressure added up is larger, but then, it's over a larger area ! I think the blowing-up-spike is related to the wall being thicker when it's smaller..it takes more 'overpressure' to stretch it to thinner, but that amount required decreases as it gets larger (thinner). But you're not measuring flow which is increasing sorta as a ballon '2x' big will have like 4x volume or something conceptually (I forget the formulas).
So I'm blown away by the 2 difference scenarios, and that thing 'memory' (elastic hysteresis) I will have to study that for a long time to get and intuitive grasp! I'm not a human calculator nor do I use formulas, because I'm not required to, lol, But, like many of us, I love to form mental models of behaviors that are pretty good. I think maybe if you stopped in the middle of the initial inflate effort it would not stay at that spike pressure but drop to an intermediate pressure? Kinda like conceptually 'stretch inertial' but that's maybe too loose a way to use the term inertial. It would be interesting and informative to do test inside a vacuum. That would take less pressure of course, but I'm curious if there would be any differences in the overall basic behavior. I think this would be different with different materials? Like metal springs?
Same question was asked in IIIT UGEE2020 one of famous institute in INDIA
...Osmosis ...now tell us about the smeared out density of matter, Mr. Science
Nice
Great! It solidified really well my knowledge about hysteresis
Hello I love ur vids btw thank u for liking my comment on ur other video about what happens to ivory soap in the worlds first vacuum chamber microwave
Kristian Vittrup so you want another like?
Lol
Totally different video 👌👍👍 awesome
You are pronouncing hysteresis incorrectly. The E before sis is a long EEEEE. Its like History Sis.
I would like to add the reason why the balloon loses elasticity when inflating. When you first have the uninflated balloon, the moleculair chains are oriented like spaghetti in a bowl, twisted in eachother with no order. When you inflate the balloon, the moleculair chains get stretched untill they lie straight. During the straightening the elasticity is high (which you can see in the part just after the spyke in the graph). After that the moleculair chains are straight and then you are actually trying to pull the molecules apart. The moleculair bounds are much more rigid and thus the elasticity goes down and the volume doesnt increase as much anymore and thus the pressure goes up more quickly. As demonstrated with the elastic band and waterbottle experiment, when you relax the plastic afterwards the elasticity of the moleculair chains is pulling the plastic back into shape but that elasticity is lower because the chains dont go back to the chaos spaghetti orientation. And thus the weights arent pulled as far back as they stretched. When you deflate the balloon and leave it alone for a while the chains will become loose and relaxed again and so it will behave again like I described in the beginning after a while.
Btw, Sorry for my English and I hope my story made sense XD English is not my first language :)
I got that straight away, intuitively. Think I have had too much experience with NOS balloons xD
Great video , this channel has taught me so many things, thanks
Vary cool
This was an awesome video! I had no idea baloons acted like that. I almost always learn something on your cahnnel.
Starts 5:00
It starts there if you want to ignore the actual learning part. Thoght don't take this as an insult the science is just cool and deserves to be watched.
Great video! Very interesting results, but makes total sense now.
Science is a field of study. It's not the reality of how things work. This isn't because of science, it's because it's just how it works. Science figured it out, but it happening has nothing to do with science. This is how you tell when someone holds modern science as their religion.
Dude, it was a joke...chill
How is it a joke when you constantly say it? I call BS.
And what are you calling BS on? I don’t even know what point you are trying to make. I constantly say “science”? I already regret responding to this troll...help me🤦🏻♂️
Saying something happens because of science in every video is not some gag...
... or they're just not grammar Nazis who feel good about making baseless assumptions about people.
It makes sense how the pressure in the baloon would decrease over time after a point considering its easier to blow a balloon later on than the earlier stages, but can you give any reasons as to why that happens
Please cut the cheesey music. We cannot hear what you are saying
Private Use I think the music is to hide microphone noise if it were gone there would be a static noise in the background
... I didn't even notice the music.
Joshua Omer same
Canaan
You can use technology to remove the ambient noises though. Even Audacity, a free program, has this feature.
Thanks for the comments. Im hard of hearing, mostly typical responses, we are okay to heck with everyone else. Hope you nevet lose your hearing fighting for your country.
Your videos are so cool that i can’t stop watching them. İ mean wo doesn’t like sience! ( if you don’t like sience why are you even watching this video )
If you've ever blown a balloon, you'll notice it always takes a great amount of effort to get it started. Pretty simple really.
Here's an idea:
Design an experiment with two gases of different densities and different colors. Might be fun, clickbaity, and educational...
So elegant. Thank you. 😃
1:04 wait you do physics, chemistry, and programming and electronics too??!!
Nice
👍
Isnt it just simpler to explain the ruber is stretchier when it heats up from deformation? That explains the hanging bucket. Also you didnt let it cool down either way.
It's simple gas eqn man.... If pv=nrt.....
N increase..... V also increase so p adjusts itself to maintain thi equivalence...
I wished I understanded.. :/