it is shown at around min 15 in this video th-cam.com/video/l_hP52q8dGo/w-d-xo.html, hope John doesn't mind me linking another channels video but i could not explain it very well as i have just learned it and english isn't my first language. I'm a year later but it might be useful for someone with the same question.
Just take all the co-efficients and add the squares of them and then inverse the root of the added number. i.e. 1/(2^2+(-1)^2+(-1)^2)^(1/2). That's the general rule.
@@DeepakSingh-qz5zuI'm just a humble disciple of yours, o great stupendous magnificient King! You are the lord❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🫨🥳🥳😶🌫️😴🥶🥶😔🫎🦌🫏🦊🐈🦁🍆🫑🍆🍏🍓🍐🫐🫐🍈🫐🥕🍉🥕🛖🏕🏥🏤🧱🛖🏗🏞🏞🏕🏞🏞🏕🎍⚾️🎇🏆🎎🎑🎟🎈🎟🎉🎉🎑🎊🎑🎊👟🧥🥾👛🧥👘🥻🧥🥻🥽🥻🧥🚳🚱🚷⚠️🛃⚠️🛃🚸🛃♿️➡️↩️♿️📵🚸🚸🛂🚻🛂🚷➡️➡️➡️🚾🇦🇺🇦🇪🇦🇱🇦🇪🇦🇱🇦🇼🇧🇫🇧🇫🏴🇦🇲🇦🇲🇦🇷🏴☠️🇦🇨🇦🇶🇦🇼🇧🇬🇧🇫🇨🇼🇨🇭🇩🇲🇨🇮🇨🇳🇨🇵🇪🇭🇧🇾🇨🇦🇪🇨🇧🇿🇨🇻🇨🇫🇩🇲🇧🇻🇨🇲🇨🇮🇩🇲🇨🇮🇨🇮🇨🇦🇨🇱🇨🇺
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Better than how my prof explained it. I actually get the topic now!
Thanks so much❤, but if we want to get the eigenvalues corresponding to this orbitals then how we get them?
Thanku sir
Why is the E 3 ?
how did u derived the 3rd basis at 8:50
it is shown at around min 15 in this video th-cam.com/video/l_hP52q8dGo/w-d-xo.html, hope John doesn't mind me linking another channels video but i could not explain it very well as i have just learned it and english isn't my first language. I'm a year later but it might be useful for someone with the same question.
How was the square root of 6 gotten? Thanks!
Just take all the co-efficients and add the squares of them and then inverse the root of the added number. i.e. 1/(2^2+(-1)^2+(-1)^2)^(1/2). That's the general rule.
@@sandippaul468 Thank you very much!
@@sandippaul468 such a genius you are!!! your concepts are really clear Sir. Thank you so much. You made my dayyy.
@@DeepakSingh-qz5zuI'm just a humble disciple of yours, o great stupendous magnificient King! You are the lord❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🫨🥳🥳😶🌫️😴🥶🥶😔🫎🦌🫏🦊🐈🦁🍆🫑🍆🍏🍓🍐🫐🫐🍈🫐🥕🍉🥕🛖🏕🏥🏤🧱🛖🏗🏞🏞🏕🏞🏞🏕🎍⚾️🎇🏆🎎🎑🎟🎈🎟🎉🎉🎑🎊🎑🎊👟🧥🥾👛🧥👘🥻🧥🥻🥽🥻🧥🚳🚱🚷⚠️🛃⚠️🛃🚸🛃♿️➡️↩️♿️📵🚸🚸🛂🚻🛂🚷➡️➡️➡️🚾🇦🇺🇦🇪🇦🇱🇦🇪🇦🇱🇦🇼🇧🇫🇧🇫🏴🇦🇲🇦🇲🇦🇷🏴☠️🇦🇨🇦🇶🇦🇼🇧🇬🇧🇫🇨🇼🇨🇭🇩🇲🇨🇮🇨🇳🇨🇵🇪🇭🇧🇾🇨🇦🇪🇨🇧🇿🇨🇻🇨🇫🇩🇲🇧🇻🇨🇲🇨🇮🇩🇲🇨🇮🇨🇮🇨🇦🇨🇱🇨🇺
In A1 part it should be underroot 2 not underroot 3