Graphing a Derivative Function | MIT 18.01SC Single Variable Calculus, Fall 2010
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- เผยแพร่เมื่อ 6 ม.ค. 2011
- Graphing a Derivative Function
Instructor: Christine Breiner
View the complete course: ocw.mit.edu/18-01SCF10
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
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Thanks from an old man (75) who is going back and relearning what I missed in high school and college. You mam are an excellent teacher!
How will this be useful at your age?
Cesar Ruiz Intrigue and knowledge aren’t limited by age
@@alejandroruiz6672 The dumbest people are those who think they have learned enough
@@alejandroruiz6672 Math is ageless so, age is not a concern.
@@alejandroruiz6672 most of the best scientists we have today are old, 60yo+
are they supposed to stop their learning and research ?
This is an awesome lecture by professor Christine Breiner on Graphing a Derivative Function. MIT thank you so much for these amazing instructors.
Great video. Very clear, might actually pass my test tomorrow.
Thank you so much. You have no idea how much this saved me at 1 in the morning
I love her that way of teaching ❤️. This is perfect for understanding!.
Thanks so much MIT, this was the exact thing I needed to sketch on my midterm. Thank you thank you!
Thanks a lot Madam,
I am watching your videos daily and I am proud to say that you put me in time machine and shifted to my first year degree Calculus class in college.
My lecturer was also very good in conveying the message, but at that time it was a bit difficult for me to grasp the concept initially but later picked up with confidence. But now it is like standing under a shower of information and I enjoyed soaking to the core. Thanks again
Follower from Tamilnadu India
Your a great teacher christine! Hoping to meet you at MIT next year.
Thank you! 3rd video I’ve watched. This is clearest
This video is so helpful. Thank you very much Christine!
Thank you very much, I've studies differential calculus before and I just learned just now that a derivative is the graph of the slope of a function
Great video and clearity of the concept
Thank you so much! The last minute or so were icing on the cake!
Thank you so much! It finally gets me out of great confusing.
It took watching a few times, but got my head round it.
all i can say is that ive been struggling with this for more than 2 lectures, but somehow in 12 minutes of listening to you,i completely understand it! THANK YOU SO MUCH!
These professors and teachers on videos are better than professors in college.
A very simple explination that gave me a methode of graphing the derivative
this was actually so helpful, thank u!
Thank you I understand about sketching derivative function now. I was so confuse at first. It's so clear now.
THANK YOU SO MUCH! U EXPLAINED IT SO WELL
you are so calming omg
Thank you for this great video, helped a lot
I love this video. it helped me a lot! thanks
Awesome, thank you so much for making this video
Speechless.......explained so well
you r so good at teaching this really helped!
Best explanation ever!
...one of the best VIDEO i ever watch 100/100 Extra-ordinary
Thank you MIT! This helps me a lot :)
excellent excellent video! I finally understand this!
Better than my professor. Excellent! Thank you! :)
It is beautiful !
this was great! thanks so much!
i love u christine! ur amazing
SOOO useful helped A LOT!
Very well explained !
VERY EXCELLENT MADAM, DUE TO PRESENCE OF UNBELIEVABLE COACHING
Thanks a lot! Really helpful. God bless you!
Thank you for the explanation
GREAT VID!
Awesome vid was reccomended by my calc teacher
it's very clearly explained.. especially for a visual learner like me :D
thankyou very much..
great explanation!
great explanation! thank you
Amazing job :)
great explanation
Thank you, this is very helpful, but it looks like at the beginning and the end the slope is fairly constant as the line seems pretty straight. I think the beginning and end of the graph of f'(x) should be closer to flat.
I think it's just the was she drew it, I think the slopes are meant to go to -inf and inf at each end.
Thanks so freakin much!
helped a bunch thanks
The leftmost curve is constant for a period so the derivative function should be a horizontal line till it near the zero piont.
god bless you you are a life saver
I Really Like The Video Graphing a Derivative Function From Your
so nice of u
omg you are the best!!!!!!!!
Can you demonstrate how to graph the derivatives when there are removable discontinuity (holes in f(x) graph) and non-differentiables (cusp or sharp corner with f(x) graph), maybe using the same graph?
thank you so much !!!!!!!!!!!!!!!!!!!!!!!!!!!!
you girl you work magicc i gotta say
Excellent, mam
finally I am cherishing the dream to learn in MIT...I can feel myself in the classroom
Very helpful thanks a lot
Very cool!
Excellent course, didactic and tasteful candy brain!
do you know how to speak english lol
helpful thanks!
I agree with you 100% , thanks .
@7:20 I believe the derivative function should come up and ride the axis for close to two measures instead of bouncing off.
Wishing you are here in our school.
Thank you :)
you are awesome
thank you
some people are born teachers and explainers. Christine is one of those people.
LIFE SAVIOR!!!!!!
Awsome!
please name all the videos by their topics! it'll help us more. Thank you
what happens when g(x)=f(nx) , where n is positive integer.
I think it will look the same but only the values on the x-xis have to change.
It would be helpful to have the equation of the curve you have drawn.
How does the second derivative compare graphically?
Great video! Only 2 issues I had were:
1) The ends of the graph look like straight lines or constant slope tangents so the derivatives should have actually been closer to constant than continuously increasing/decreasing.
2) The part in the middle actually doesn't make sense to me as a continuously decreasing curve. If it is continuously decreasing then how is there a point where the tangent is zero?
Agree
Now I can officially say I go to MIT.
the derivative of x^2 which is 2x prove that you aren't right cuz it never go horizontal even in high amounts of x it is always the y=2x line
Bravo.
MIT professors LOVE that super thick chalk !
I wish that my math professors in college would have been this explanatory.. I'm serious!! A couple of them went furiously fast because they were either fast talkers or they were full-time at another University and part-time where I was attending college AND OUR CLASS DIDN'T START UNTIL 6:00 P.M. AND WE WERE THERE UNTIL 9:30 SO HE WAS READY TO GO HOME!! ONE OF MY MATH TEACHERS MISSED ONE WEEK BECAUSE HE HAD A DEATH IN THE FAMILY AND THE NEXT WEEK BECAUSE HIS NECK HURT. IT WAS AT THE VERY END OF THE TERM AND OUR CLASS WAS TWO AND A HALF WEEKS BEHIND. WE CAME INTO CLASS AND HAD TO TEST AND THEN THE LAST WEEK AND A HALF OF CLASS RUSHED THROUGH EVERYTHING THAT WE MISSED FOR 2 WEEKS. IT WAS A MESS! WE TOOK OUR FINAL FIVE DAYS AWAY AND IT STILL DIDN'T HELP. I HAD 96.5 BEFORE HE WAS OUT AND THEN AFTER I GOT A 75 ON MY FINAL AND A 70 ON ANOTHER TEST; THE NEXT TWO CHAPTERS WE FLEW THROUGH IN A WEEK THAT HAPPENED TO BE THE MOST DIFFICULT, I ENDED UP WITH AN 89.5. I'M JOKINGLY ASKED HIM IF HE GAVE ANY EXTRA CREDIT OR I COULD WORK ON IT HE TOLD ME "NO".
I'M GETTING READY TO GO BACK TO COLLEGE AND FINISH TWO YEARS OF COLLEGE TO BE A MATH TEACHER.. I'VE ALWAYS LOVED MATH. IN GRADE SCHOOL I HAD ALL EXCELLENT MATH TEACHERS EXCEPT FOR ONE, WHO WAS BORING. SHE HAPPENED TO BE MY GEOMETRY TEACHER. ALL OF MY OTHERS WERE GREAT AND I LOVED MATH. THE INSTRUCTORS HELP SO MUCH!!
nice!
lmao i got a test tmw for high school AB calc and im watching MIT vids yessir
Why can't my professor be this simple??!?! lol, Thanks :)
How so?
But this is verging on bollocks!
F'(x), the slope of the f(x), to the left is almost constant until it nears the first stationary point, and so f'(x) should be almost horizontal until it nears the first stationary point, and it is nothing like horizontal, it is over 45 degree slope upwards!. The same problem occurs on her depiction of the derivative on the right side of the graph.
And the question at the end was almost meaningless.
Nice
Great video, however just be careful about how long the gradient being = 0 lasts for. Her graph is technically wrong as there should be a break in the middle of the 'w' as the gradient stays 0 for a while. But in terms of teaching this, fantastic.
Thank you for confirming because I had asymptotes at those two points and could not understand the 'w'.
heelo,how are you doing.i like view mathematic of mit.thanks a lot
Seven years ago you were very charming professor. Are you still so charming? I hope you are. Thanks
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patrickjmts videos are much better..when i saw this function...i made the graph at once...credit goes to Patrick[.]com he should also teach in MIT
damn, i wish i had handwriting as neat as that.. ,_,
what is the equation ?
+zadran zadrani y=g(x) + 3 u just add a constant I think that is it.
Though, her sketch is wrong on the left and right side. Don't be confused.
@anakmudajaman why are you capitalizing every word...?
High School Calculus FTW!
not really much help if you don;t complete the lesson.
COME TEACH AT MY SCHOOL