Thanks a lot Madam, I am watching your videos daily and I am proud to say that you put me in time machine and shifted to my first year degree Calculus class in college. My lecturer was also very good in conveying the message, but at that time it was a bit difficult for me to grasp the concept initially but later picked up with confidence. But now it is like standing under a shower of information and I enjoyed soaking to the core. Thanks again Follower from Tamilnadu India
all i can say is that ive been struggling with this for more than 2 lectures, but somehow in 12 minutes of listening to you,i completely understand it! THANK YOU SO MUCH!
Thank you, this is very helpful, but it looks like at the beginning and the end the slope is fairly constant as the line seems pretty straight. I think the beginning and end of the graph of f'(x) should be closer to flat.
Great video! Only 2 issues I had were: 1) The ends of the graph look like straight lines or constant slope tangents so the derivatives should have actually been closer to constant than continuously increasing/decreasing. 2) The part in the middle actually doesn't make sense to me as a continuously decreasing curve. If it is continuously decreasing then how is there a point where the tangent is zero?
I wish that my math professors in college would have been this explanatory.. I'm serious!! A couple of them went furiously fast because they were either fast talkers or they were full-time at another University and part-time where I was attending college AND OUR CLASS DIDN'T START UNTIL 6:00 P.M. AND WE WERE THERE UNTIL 9:30 SO HE WAS READY TO GO HOME!! ONE OF MY MATH TEACHERS MISSED ONE WEEK BECAUSE HE HAD A DEATH IN THE FAMILY AND THE NEXT WEEK BECAUSE HIS NECK HURT. IT WAS AT THE VERY END OF THE TERM AND OUR CLASS WAS TWO AND A HALF WEEKS BEHIND. WE CAME INTO CLASS AND HAD TO TEST AND THEN THE LAST WEEK AND A HALF OF CLASS RUSHED THROUGH EVERYTHING THAT WE MISSED FOR 2 WEEKS. IT WAS A MESS! WE TOOK OUR FINAL FIVE DAYS AWAY AND IT STILL DIDN'T HELP. I HAD 96.5 BEFORE HE WAS OUT AND THEN AFTER I GOT A 75 ON MY FINAL AND A 70 ON ANOTHER TEST; THE NEXT TWO CHAPTERS WE FLEW THROUGH IN A WEEK THAT HAPPENED TO BE THE MOST DIFFICULT, I ENDED UP WITH AN 89.5. I'M JOKINGLY ASKED HIM IF HE GAVE ANY EXTRA CREDIT OR I COULD WORK ON IT HE TOLD ME "NO". I'M GETTING READY TO GO BACK TO COLLEGE AND FINISH TWO YEARS OF COLLEGE TO BE A MATH TEACHER.. I'VE ALWAYS LOVED MATH. IN GRADE SCHOOL I HAD ALL EXCELLENT MATH TEACHERS EXCEPT FOR ONE, WHO WAS BORING. SHE HAPPENED TO BE MY GEOMETRY TEACHER. ALL OF MY OTHERS WERE GREAT AND I LOVED MATH. THE INSTRUCTORS HELP SO MUCH!!
But this is verging on bollocks! F'(x), the slope of the f(x), to the left is almost constant until it nears the first stationary point, and so f'(x) should be almost horizontal until it nears the first stationary point, and it is nothing like horizontal, it is over 45 degree slope upwards!. The same problem occurs on her depiction of the derivative on the right side of the graph. And the question at the end was almost meaningless.
Great video, however just be careful about how long the gradient being = 0 lasts for. Her graph is technically wrong as there should be a break in the middle of the 'w' as the gradient stays 0 for a while. But in terms of teaching this, fantastic.
Can you demonstrate how to graph the derivatives when there are removable discontinuity (holes in f(x) graph) and non-differentiables (cusp or sharp corner with f(x) graph), maybe using the same graph?
Lol there is a mistake on the left side.... The slope is almost constant so the dirivative should be around the same all the time and not decreasing...
Thanks from an old man (75) who is going back and relearning what I missed in high school and college. You mam are an excellent teacher!
How will this be useful at your age?
Cesar Ruiz Intrigue and knowledge aren’t limited by age
@@alejandroruiz6672 The dumbest people are those who think they have learned enough
@@alejandroruiz6672 Math is ageless so, age is not a concern.
@@alejandroruiz6672 most of the best scientists we have today are old, 60yo+
are they supposed to stop their learning and research ?
Thanks a lot Madam,
I am watching your videos daily and I am proud to say that you put me in time machine and shifted to my first year degree Calculus class in college.
My lecturer was also very good in conveying the message, but at that time it was a bit difficult for me to grasp the concept initially but later picked up with confidence. But now it is like standing under a shower of information and I enjoyed soaking to the core. Thanks again
Follower from Tamilnadu India
Great video. Very clear, might actually pass my test tomorrow.
This is an awesome lecture by professor Christine Breiner on Graphing a Derivative Function. MIT thank you so much for these amazing instructors.
all i can say is that ive been struggling with this for more than 2 lectures, but somehow in 12 minutes of listening to you,i completely understand it! THANK YOU SO MUCH!
These professors and teachers on videos are better than professors in college.
Thank you so much. You have no idea how much this saved me at 1 in the morning
I love her that way of teaching ❤️. This is perfect for understanding!.
Thank you, this is very helpful, but it looks like at the beginning and the end the slope is fairly constant as the line seems pretty straight. I think the beginning and end of the graph of f'(x) should be closer to flat.
I think it's just the was she drew it, I think the slopes are meant to go to -inf and inf at each end.
A very simple explination that gave me a methode of graphing the derivative
Thanks so much MIT, this was the exact thing I needed to sketch on my midterm. Thank you thank you!
Thank you very much, I've studies differential calculus before and I just learned just now that a derivative is the graph of the slope of a function
VERY EXCELLENT MADAM, DUE TO PRESENCE OF UNBELIEVABLE COACHING
Thank you so much! It finally gets me out of great confusing.
It took watching a few times, but got my head round it.
@7:20 I believe the derivative function should come up and ride the axis for close to two measures instead of bouncing off.
Thank you I understand about sketching derivative function now. I was so confuse at first. It's so clear now.
some people are born teachers and explainers. Christine is one of those people.
Your a great teacher christine! Hoping to meet you at MIT next year.
The leftmost curve is constant for a period so the derivative function should be a horizontal line till it near the zero piont.
Thank you so much! The last minute or so were icing on the cake!
the derivative of x^2 which is 2x prove that you aren't right cuz it never go horizontal even in high amounts of x it is always the y=2x line
Best explanation ever!
finally I am cherishing the dream to learn in MIT...I can feel myself in the classroom
Better than my professor. Excellent! Thank you! :)
it's very clearly explained.. especially for a visual learner like me :D
thankyou very much..
Great video and clearity of the concept
Great video! Only 2 issues I had were:
1) The ends of the graph look like straight lines or constant slope tangents so the derivatives should have actually been closer to constant than continuously increasing/decreasing.
2) The part in the middle actually doesn't make sense to me as a continuously decreasing curve. If it is continuously decreasing then how is there a point where the tangent is zero?
Agree
Thank you! 3rd video I’ve watched. This is clearest
...one of the best VIDEO i ever watch 100/100 Extra-ordinary
you are so calming omg
Awesome vid was reccomended by my calc teacher
Speechless.......explained so well
THANK YOU SO MUCH! U EXPLAINED IT SO WELL
you girl you work magicc i gotta say
This video is so helpful. Thank you very much Christine!
this was actually so helpful, thank u!
Now I can officially say I go to MIT.
I wish that my math professors in college would have been this explanatory.. I'm serious!! A couple of them went furiously fast because they were either fast talkers or they were full-time at another University and part-time where I was attending college AND OUR CLASS DIDN'T START UNTIL 6:00 P.M. AND WE WERE THERE UNTIL 9:30 SO HE WAS READY TO GO HOME!! ONE OF MY MATH TEACHERS MISSED ONE WEEK BECAUSE HE HAD A DEATH IN THE FAMILY AND THE NEXT WEEK BECAUSE HIS NECK HURT. IT WAS AT THE VERY END OF THE TERM AND OUR CLASS WAS TWO AND A HALF WEEKS BEHIND. WE CAME INTO CLASS AND HAD TO TEST AND THEN THE LAST WEEK AND A HALF OF CLASS RUSHED THROUGH EVERYTHING THAT WE MISSED FOR 2 WEEKS. IT WAS A MESS! WE TOOK OUR FINAL FIVE DAYS AWAY AND IT STILL DIDN'T HELP. I HAD 96.5 BEFORE HE WAS OUT AND THEN AFTER I GOT A 75 ON MY FINAL AND A 70 ON ANOTHER TEST; THE NEXT TWO CHAPTERS WE FLEW THROUGH IN A WEEK THAT HAPPENED TO BE THE MOST DIFFICULT, I ENDED UP WITH AN 89.5. I'M JOKINGLY ASKED HIM IF HE GAVE ANY EXTRA CREDIT OR I COULD WORK ON IT HE TOLD ME "NO".
I'M GETTING READY TO GO BACK TO COLLEGE AND FINISH TWO YEARS OF COLLEGE TO BE A MATH TEACHER.. I'VE ALWAYS LOVED MATH. IN GRADE SCHOOL I HAD ALL EXCELLENT MATH TEACHERS EXCEPT FOR ONE, WHO WAS BORING. SHE HAPPENED TO BE MY GEOMETRY TEACHER. ALL OF MY OTHERS WERE GREAT AND I LOVED MATH. THE INSTRUCTORS HELP SO MUCH!!
It is beautiful !
great explanation! thank you
Wishing you are here in our school.
I love this video. it helped me a lot! thanks
But this is verging on bollocks!
F'(x), the slope of the f(x), to the left is almost constant until it nears the first stationary point, and so f'(x) should be almost horizontal until it nears the first stationary point, and it is nothing like horizontal, it is over 45 degree slope upwards!. The same problem occurs on her depiction of the derivative on the right side of the graph.
And the question at the end was almost meaningless.
It would be helpful to have the equation of the curve you have drawn.
Very well explained !
Excellent course, didactic and tasteful candy brain!
do you know how to speak english lol
excellent excellent video! I finally understand this!
Thank you for this great video, helped a lot
Thank you for the explanation
you r so good at teaching this really helped!
Thanks a lot! Really helpful. God bless you!
i love u christine! ur amazing
I Really Like The Video Graphing a Derivative Function From Your
Awesome, thank you so much for making this video
great explanation
great explanation!
Excellent, mam
SOOO useful helped A LOT!
Great video, however just be careful about how long the gradient being = 0 lasts for. Her graph is technically wrong as there should be a break in the middle of the 'w' as the gradient stays 0 for a while. But in terms of teaching this, fantastic.
Thank you for confirming because I had asymptotes at those two points and could not understand the 'w'.
I agree with you 100% , thanks .
helped a bunch thanks
god bless you you are a life saver
Thank you MIT! This helps me a lot :)
Thanks so freakin much!
Can you demonstrate how to graph the derivatives when there are removable discontinuity (holes in f(x) graph) and non-differentiables (cusp or sharp corner with f(x) graph), maybe using the same graph?
thank you
Though, her sketch is wrong on the left and right side. Don't be confused.
please name all the videos by their topics! it'll help us more. Thank you
this was great! thanks so much!
Amazing job :)
thank you so much !!!!!!!!!!!!!!!!!!!!!!!!!!!!
lmao i got a test tmw for high school AB calc and im watching MIT vids yessir
so nice of u
MIT professors LOVE that super thick chalk !
GREAT VID!
Very helpful thanks a lot
patrickjmts videos are much better..when i saw this function...i made the graph at once...credit goes to Patrick[.]com he should also teach in MIT
Very cool!
omg you are the best!!!!!!!!
helpful thanks!
you are awesome
what happens when g(x)=f(nx) , where n is positive integer.
I think it will look the same but only the values on the x-xis have to change.
Thank you :)
LIFE SAVIOR!!!!!!
How does the second derivative compare graphically?
Awsome!
Bravo.
توضيح النقاط الحرجه
How so?
Seven years ago you were very charming professor. Are you still so charming? I hope you are. Thanks
Lol there is a mistake on the left side.... The slope is almost constant so the dirivative should be around the same all the time and not decreasing...
the same on the right actually
Rekt In Pisses nice one MIT
I think you got confused with the 2nd derivative there, which would be constant.
No, YOU are mistaken, it's a curve not a linear graph.
Dude, don't be so literal with the drawing, it looks more like a curve than a linear piece wise function. Use your imagination!
heelo,how are you doing.i like view mathematic of mit.thanks a lot
Why can't my professor be this simple??!?! lol, Thanks :)
damn, i wish i had handwriting as neat as that.. ,_,
nice!
Nice
what is the equation ?
+zadran zadrani y=g(x) + 3 u just add a constant I think that is it.
COME TEACH AT MY SCHOOL
not really much help if you don;t complete the lesson.
@anakmudajaman why are you capitalizing every word...?