Very helpful video sir, thank you so much. But could you please explain why didn't you divide Iₒ(ω) by Iᵢₙ(ω) to obtain H(ω). Isn't H(ω) the transfer function? I really appreciate your lightning fast responses to our doubts!
The current in branch "A" is equal to the current entering the branch point times the ratio of (impedance in branch "B") / (impedance in branch "A" + impendance in branch "B")
The formulas you wrote for reactance, I believe that is incorrect. The impedance is written with the imaginary component, which is what you have written now, and the reactance simply looks at the coefficient and ignores the imaginary component for example: Z_L = jwL Z_C = 1/(jwC) X_L = wL X_C = 1/(wC)
I do not know what would be of me without your videos! They are really helpful!
Glad we can be of help. Thanks for sharing.
Very helpful video sir, thank you so much. But could you please explain why didn't you divide Iₒ(ω) by Iᵢₙ(ω) to obtain H(ω). Isn't H(ω) the transfer function? I really appreciate your lightning fast responses to our doubts!
Is it always Z1 over Z2+Z1?
The current in branch "A" is equal to the current entering the branch point times the ratio of (impedance in branch "B") / (impedance in branch "A" + impendance in branch "B")
Excellent explanation. Thank you!!
1000000000000 of thank you sir. ......
Transfer functions made my life easier, guess I have to thank Laplace for that.
The formulas you wrote for reactance, I believe that is incorrect. The impedance is written with the imaginary component, which is what you have written now, and the reactance simply looks at the coefficient and ignores the imaginary component for example:
Z_L = jwL
Z_C = 1/(jwC)
X_L = wL
X_C = 1/(wC)
i believe it's for total impedance: Z=R+X
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