your question reveals a lack of understanding about HOW we move around the transition table ...... there is NO WAY to move from column 4 to column 2 in ANY row at ANY time ..... you can only move to a column on either side of the current state .... therefore from column 4 in row 4 you have only two "ways to move" you can either move to column 3 or column 1 ..... hope that helps you 🙂
Hey Mr. , If we have more than 2 stable states (3 stable states to be exact) in one culumn , is it right to say that it's a critical race ? .. and Thanks a lot for the explanation
the number of stable states in a column does not cause race (a race is caused when BOTH Y1 and Y2 try to change state at the SAME time)..... however, IF there is a race in a column, it will be CRITICAL if there is more than ONE stable state in that column..... so two (or more) stable states will lead to critical condition IF a race can occur in that column
In order for a race to occur BOTH bits within a square must change when moving to an adjacent square... that cannot happen in Row 3 .... we have 11 and 10 .... only one bit changes state
a race occurs whenever both outputs have to change 'at the same time' (in a properly designed system this should never happen). A critical race means that the final state depends upon the outcome of the race. A non-critical race means that. no matter what the race outcome, the final state is always the same.
thanks a lot for great explanation
crisp and clear
Thank your sir for this wonderful explanation. Do you have references(papers, books) for this topic?
Why is there no race when moving from column 4 to column 2 in row 4?
your question reveals a lack of understanding about HOW we move around the transition table ...... there is NO WAY to move from column 4 to column 2 in ANY row at ANY time ..... you can only move to a column on either side of the current state .... therefore from column 4 in row 4 you have only two "ways to move" you can either move to column 3 or column 1 ..... hope that helps you 🙂
@@StephenMendes Thank you very much, I understand now.
This is great. Thanks for the clear explanation.
Hey Mr. , If we have more than 2 stable states (3 stable states to be exact) in one culumn , is it right to say that it's a critical race ? .. and Thanks a lot for the explanation
the number of stable states in a column does not cause race (a race is caused when BOTH Y1 and Y2 try to change state at the SAME time)..... however, IF there is a race in a column, it will be CRITICAL if there is more than ONE stable state in that column..... so two (or more) stable states will lead to critical condition IF a race can occur in that column
May I ask why are there no race in row 3?
In order for a race to occur BOTH bits within a square must change when moving to an adjacent square... that cannot happen in Row 3 .... we have 11 and 10 .... only one bit changes state
totallly confusing , lol; spent over 30mins , still have no clue !
Thanks alot
Thank you sir :)
Welcome.... appreciate your comment 😊
i do not understand the critical race part. can you please try and explain further.
a race occurs whenever both outputs have to change 'at the same time' (in a properly designed system this should never happen). A critical race means that the final state depends upon the outcome of the race. A non-critical race means that. no matter what the race outcome, the final state is always the same.