Evaluating A Nice Radical

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[@stvp68]

Tutti in music: everyone sing!

[@tejpalsingh366]

4-(-1)= 5

[@FrancisZerbib]

We’re not everyone. We’re someone

[@dan-florinchereches4892]

I will try the following :
y=√x and E = x-2√x = y^2-2y => y^2-2/y=5 y^3-2y^2+2y^2-5y-2=0
y*E+2y^2-4y+4y-5y-2=0
y*E+2E -y -2=0
y(E-1)+2(E-1)=0
(y+2)(E-1)=0
so E must be 1

[@loboshill4573]

X= ?

[@yakupbuyankara5903]

1