Great explanation. For someone who may be interested to know more, the situation where you get a zero row in the Routh array, it is indicative of a system having poles on the imaginary axis, the partition between RHP and LHP. Which means that if you encounter a system having a zero row in the Routh Array and then you do the substitution as ma'am suggested in the video and end up getting all positive coefficients in the first column, it DOESN'T mean that your system is ASYMPTOTICALLY STABLE. It is MARGINALLY STABLE and the output will be oscillatory in nature. If we talk about bounded stability then having positive coefficients in the first column is sufficient to tell about stability as marginally stable systems are also boundedly stable. Hope it is helpful.
Anyone can help me if after getting 0 in any row we apply above rule which is shown in video but does not change in any pole means all poles are positive what will be conclusion Did it is marginally stable or only stable?
The problem above is neither stable nor unstable but marginally stable since they are poles on the jw axis/imaginary axis! but my main question is how do we find the number of poles on the jw axis/imaginary axis since they are always in pairs?
please i think should say 1 times 5 or 2 times 3, since you multiplying than say one into 5 because (into) is usually used when dividing. But your videos are good and helpful very great full
Actually mam,I can't deny your help which made me more confident but a little thing is your title says it case no 1 but you wrote it no. 2 in the lecture.Please edit the title .Same happened in the lecture of case no 1!
Thankyou fo the video, can u please clarify, For the auxillary polynomial, what if we get lets say, S^6 row to have all zeros and now auxillary polynomial will be S^7. We now use odd number arrangement for the auxillary polynomial equation?
If all the terms get zero in the even power then we have to take the above one that is odd ?? but we have to consider positive as you told. Please solve it
@Devalla Rakesh then what if we get all zeros in the row of say s^4 then we have to take s^5 row to get the auxiliary equation, then how could we make auxillary equation in that case, should it start from s^4 or what??
nice video mam,,and very cute accent u have ,but my question is if the row which becomes 0 is not even like if it is not s4 but s3 than how can we make charc. eq. with all even enteries thanku
I think the question itself is not fulfilling the necessary condition for RH criterion. (coefficient should be of same sign) or am i missing something?
in the characteristic equation given .the coefficients of the polynomial doesn't posses same sign .so can't we directly tell Routh criteria does not applicable for this characteristic equation
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Great explanation.
For someone who may be interested to know more, the situation where you get a zero row in the Routh array, it is indicative of a system having poles on the imaginary axis, the partition between RHP and LHP.
Which means that if you encounter a system having a zero row in the Routh Array and then you do the substitution as ma'am suggested in the video and end up getting all positive coefficients in the first column, it DOESN'T mean that your system is ASYMPTOTICALLY STABLE. It is MARGINALLY STABLE and the output will be oscillatory in nature.
If we talk about bounded stability then having positive coefficients in the first column is sufficient to tell about stability as marginally stable systems are also boundedly stable.
Hope it is helpful.
it is helpful.i will also like to know how to get the number of poles on the imaginary axis?
Anyone can help me if after getting 0 in any row we apply above rule which is shown in video but does not change in any pole means all poles are positive what will be conclusion
Did it is marginally stable or only stable?
Thank you for this tip sir
Mam we watched your videos in lockdown to prepare for our exam. Your videos are very easy to understand . Thanks mam
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You made this problem as simple as you can , super madam the way of explanation is mind blowing
You are a real life saver mam .it helped me a lot keep making videos mam👍
I have mastered many of my courses from your tutorials, keep it up maam
I was afraid a lot for my exam , i watched topicwise videos from this series it helped me a lot in my Exam, Thank you So much Ma'am 😊
Thank you so much ma'am. By studying from your lectures, I topped in my college in this course. Regards❤
aare good thing my name is Rishabh hopefully I meet he same fate
Best of luck to you brother
Congratultion sir
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Tomorrow is my exam Could I complete my syllabus
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Yaa
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Very nice videos mam. Excellent style to teach with easy explanations and understanding.
Thank you so much for helping me in my mechatronics exam
I am very very thankful to you for such a good explanation
Tq mam
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I'm watching this at 2x speed, it's good 👍
It's so easy explained by mam
Thank you so much
The problem above is neither stable nor unstable but marginally stable since they are poles on the jw axis/imaginary axis! but my main question is how do we find the number of poles on the jw axis/imaginary axis since they are always in pairs?
Mam your teaching is excellent madam I watched ur STLD and SS I topper mam🤗🤗🤗🤗😍😍😍🤗🤗🤗
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Yah yar I also
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Mam I Watch your video it is very useful for everyone
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tq mam Ur teaching way is superb
Hello...yeh do you telling me how she got the new equation...pls
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please i think should say 1 times 5 or 2 times 3, since you multiplying than say one into 5 because (into) is usually used when dividing. But your videos are good and helpful very great full
Great teaching 🙏
Thank you madam. Very clear explanation
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Really very good explanation mam
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Thank U Mam for this great explanation
Very important knowledge
keep the speed to 1.5X
2X
still same lol
im watching it at 2x speed but still it feels the same
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@@fifty1050 just tap 1 to 9 you feel very fast
good explanation🙏
Actually mam,I can't deny your help which made me more confident but a little thing is your title says it case no 1 but you wrote it no. 2 in the lecture.Please edit the title .Same happened in the lecture of case no 1!
Good explanation ✨
Thanks you so much for stability problem video !
Thank you mam aaj hamre pepar ye same question aaya tha
very nice explanation
Thank you. Am watching today 19th January 2025. From Nigeria.
Thanks for this explanation
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Thanks ma, but the last column will be positive if you finish it,the answer won't be -8
Ossum explanation thank you so much mam
Thanks a lot mam, u r doing a good job
19/11/2019 have exam thank you for this video
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Thankyou fo the video, can u please clarify, For the auxillary polynomial, what if we get lets say, S^6 row to have all zeros and now auxillary polynomial will be S^7. We now use odd number arrangement for the auxillary polynomial equation?
thank you very much mam😇😇👍
You are the best!
Superb video Mam..
Your lectures are so helpful. I wanna donate to your channel. Any links maam??
If all the terms get zero in the even power then we have to take the above one that is odd ?? but we have to consider positive as you told.
Please solve it
Good explanation mam 👍
Thank you ma'am ♥️
You are awesome thank you ❤
Awesome Mam
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excellent explanation ma'am
Thanks you mam 😍😍😍
Excellent!!!!!
How to explain your way too great...Thank you mam
What if auxillary equation is odd powers?
I thought of asking the same
@Devalla Rakesh thankyou very much!!!
@Devalla Rakesh then what if we get all zeros in the row of say s^4 then we have to take s^5 row to get the auxiliary equation, then how could we make auxillary equation in that case, should it start from s^4 or what??
@@AakashSharma-vn9wv start with s^5 bro then go on with s^3 and s^1
Take derivative once and get even power.
nice video mam,,and very cute accent u have ,but my question is if the row which becomes 0 is not even like if it is not s4 but s3 than how can we make charc. eq. with all even enteries
thanku
I have the same question bro......but I don't know the answer. If you will get the answer please you share with me.
Stuck at same place
is it compulsory to start the auxiliary equation from +ve power of s.?
She missed the negative sign in S column
for Writing coeffs. of "s".. first write all even power coeffs. if first power of s is even and vice versa.
I think the question itself is not fulfilling the necessary condition for RH criterion. (coefficient should be of same sign) or am i missing something?
Gjb mam
But madam u are not mentioned, no of poles on imaginary axis
Thanks
What if the s^4 row becomes zero or s^2 row is zero then the previous row will have odd power! How to form aux. equation in that case?
Yeah even i didn't get that😅
If s^4 row become zero the auxillary equation would be s^5+3s^3-4s^1
at 14:14, u said 2nd case of special case but in video title says Case I
Chup jhatu
if zeroes appear at s⁴. How to take auxiliary polynomial.
in the characteristic equation given .the coefficients of the polynomial doesn't posses same sign .so can't we directly tell Routh criteria does not applicable for this characteristic equation
great🔥
very nice 😍🇮🇶
Thank you! Go on...
the order of the auxilary polynomial considerd only even that is perfectly fine
why we cannot considerd as odd terms
Mam , I have a doubt , if we have zeros on s4 line then how to write the auxiliary equation ???
same doubt:(
Thanks a lot
Thank you Mam!
Thank you madam !!!
thanks alot useful
Is this system marginally stable ???????
Thank you
How many pole on imagina axis????
Video starts at 2:57. Thanks me later
Chup 😶
Thank you mam
please provide ROOT LOCUS topic as well
Is this course for Chemical Engineering Student for Control Course ?
Awesome