The last problem, maximum error in the region is bounded by 1.331113*10^-4, the answer you get is more than 10 times that. I mean I understand you have taken maximum values but consider the region, M won't even overshoot sin(0.1) you have taken 1 as M, that's where the discrepancy comes from.
It's kind of gross how much of an overestimate we take by using M, for an account max R1 for first 2 variable example is 0.025 you got 0.06, which is not wrong but more than double the error, for second example max R1 is 0.01161 much less than 0.0221 you get.
The last problem, maximum error in the region is bounded by 1.331113*10^-4, the answer you get is more than 10 times that. I mean I understand you have taken maximum values but consider the region, M won't even overshoot sin(0.1) you have taken 1 as M, that's where the discrepancy comes from.
17:10 M must be equal to 1 as fxx, fyy and fxy is counted on (0,0). "0.1" is given upper bound value for both x-x0 and y-y0.
Yes you r correct, the answer that is given below the problem statement is also coming from taking M as 1.
@@thatnaman with e^0.1 ans will be 0.0221 which is approx 0.02
(e^x)(sin or cos )
22:32 error estimating of 3 variable
There's a problem in last ques - we r told that the region for approximation is R : |x|
How is M =sin (0.2), shouldn’t it be sin (0.1)?
It's kind of gross how much of an overestimate we take by using M, for an account max R1 for first 2 variable example is 0.025 you got 0.06, which is not wrong but more than double the error, for second example max R1 is 0.01161 much less than 0.0221 you get.
Sorry but I could not get (17:05-17:30) how the maximum value of sin or cos is 1 in |X|
bhai its given in the question
Max value of sin or cos function is always 1
If you restrict sin to that domain max value of sin is sin(0.1) but he's taking overestimate everywhere, so it's okay
In three variable first problem error upper limit can be 3.5*10^-4, the answer we get with that max approximation is more than 4.5times that
Very good...
Excellent.. 👌
Marvellous💯
GOD LEVEL
Find the quadratic approximation of f(x, y) = xY at (1, 1)
Nice
thanks sir
So we overestimate everytime, that's sad
Plzzz solve this
Every question is wrong
How do u know?
Find the quadratic approximation of f(x, y) = xY at (1, 1)
It should be itself
The approximation will give the same function because R2 will be zero