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Thanks mate , it helped a lot , straight to the point and well explained.
Thanks for your kind words! I hope that you will enjoy my other videos!
Thank you for this. Really needed this. Keep up the good work👏
My pleasure! I am glad to hear that it was helpful. Will do! Thanks for your kind words!
Thank you so much. It's really helpful for me
Glad to hear!
lets say, there is a single 1 in a column but its a negative, would that still work?
You can simply multiply the row of -1 by -1 to turn it into +1.
so basically for all lineal transformation we work whit the associated matrix of a certain basis?
Yes, every linear transformation between finite vector spaces is associated with a matrix.
so the basis of the migae can be read of the matrix by looking back at the columns that consisted of just a single 1 and otherwise 0?
Yes, that is correct.
Thanks for the help!
My pleasure!
thanks that was helpful
Thank you for this video
So is finding the basis for the image the same as finding a basis for the column space?
Yes, it is since the image is a collection of all linear combinations of column vectors.
@@wishizuk But you can put the vectors as rows right, or do we by convention always put the vectors as columns
thanks king
Thanks mate , it helped a lot , straight to the point and well explained.
Thanks for your kind words! I hope that you will enjoy my other videos!
Thank you for this. Really needed this. Keep up the good work👏
My pleasure! I am glad to hear that it was helpful. Will do! Thanks for your kind words!
Thank you so much. It's really helpful for me
Glad to hear!
lets say, there is a single 1 in a column but its a negative, would that still work?
You can simply multiply the row of -1 by -1 to turn it into +1.
so basically for all lineal transformation we work whit the associated matrix of a certain basis?
Yes, every linear transformation between finite vector spaces is associated with a matrix.
so the basis of the migae can be read of the matrix by looking back at the columns that consisted of just a single 1 and otherwise 0?
Yes, that is correct.
Thanks for the help!
My pleasure!
thanks that was helpful
My pleasure!
Thank you for this video
My pleasure!
So is finding the basis for the image the same as finding a basis for the column space?
Yes, it is since the image is a collection of all linear combinations of column vectors.
@@wishizuk But you can put the vectors as rows right, or do we by convention always put the vectors as columns
thanks king
My pleasure!