I'm trying to calculate using a 40-1 gearbox to achieve 550 nm of torque which is the end piece of equipment needing.... what size motor on the input of the gearbox needed to achieve that
Hi, thank you for your question. It looks like you’re intending to achieve a 550Nm torque output with a lower torque motor. This link will provide you a brief overview on how torque is transmitted through gear trains: www.engineeringtoolbox.com/gear-output-torque-speed-horsepower-d_1691.html Assuming a 90% gear efficiency, you can achieve a 550Nm torque output with approximately 15.3Nm of input torque. Feel free to send any additional information to our SCHUNK Automation Applications group (automation-apps@us.schunk.com) if you would like our team of engineers to review your application.
Hi Sir, I am a Mechanical Design Engineer, & Facing Problems of Design Calculations more. so please can you tell me from where i will get that all Design Calculation? Thank You Very Much Sir....😍
The mass moment of inertia of the carriage/payload can be approximated by the equation I=mr^2 when sizing for a linear actuator motor where m is the mass of the carriage+payload, and r is the radius of the ball screw or belt pully. This approximation treats the carriage as a point load. The radius of the ball screw or pully is used because we are trying to measure the resistance to change of the ball screw or pully rotation due to the mass of the carriage. Keep in mind this does not include the inertia from the ball screw or pully and in reality the calculation is more complicated. For more information or assistance, please contact: automation-apps@us.schunk.com
The lead of the ball screw is the linear distance you get per one revolution of the ball screw; however the lead of the system is equal to the linear distance from one rotation of the input, in this case a motor. Most of the time when we use this equation, we are trying to solve for the torque required by the motor, so we include the gearbox into the lead equation. For more information or assistance, please contact: automation-apps@us.schunk.com
The torque equation presented in the training video applies to horizontal and vertical motion. The force value tends to be less during a horizontal motion as the moving payload is not move against or with gravity. The force value for horizontal motion would be the payload times acceleration (due to the move) plus friction force (payload x gravity x friction). Please contact the SCHUNK Automation Team at automation-apps@us.schunk.com for application review and assistance.
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Cleared Every Doubts In this Video & Also I appreciate Your Humble Teaching & Efforts. Thank You Very Very Much Sir .🙂🙂🙂🙂🙂
Great video information 👍 thank you for sharing your knowledge ♥️🇵🇭
in ball screw calculation, circumference i consider as coupling dia or ball screw dia
I'm trying to calculate using a 40-1 gearbox to achieve 550 nm of torque which is the end piece of equipment needing.... what size motor on the input of the gearbox needed to achieve that
Hi, thank you for your question. It looks like you’re intending to achieve a 550Nm torque output with a lower torque motor. This link will provide you a brief overview on how torque is transmitted through gear trains: www.engineeringtoolbox.com/gear-output-torque-speed-horsepower-d_1691.html
Assuming a 90% gear efficiency, you can achieve a 550Nm torque output with approximately 15.3Nm of input torque. Feel free to send any additional information to our SCHUNK Automation Applications group (automation-apps@us.schunk.com) if you would like our team of engineers to review your application.
Hi Sir, I am a Mechanical Design Engineer, & Facing Problems of Design Calculations more. so please can you tell me from where i will get that all Design Calculation? Thank You Very Much Sir....😍
hello sir can you tell me how i can calculate moment of inertia of carriege manually...which type of data i should need
The mass moment of inertia of the carriage/payload can be approximated by the equation I=mr^2 when sizing for a linear actuator motor where m is the mass of the carriage+payload, and r is the radius of the ball screw or belt pully. This approximation treats the carriage as a point load. The radius of the ball screw or pully is used because we are trying to measure the resistance to change of the ball screw or pully rotation due to the mass of the carriage. Keep in mind this does not include the inertia from the ball screw or pully and in reality the calculation is more complicated. For more information or assistance, please contact: automation-apps@us.schunk.com
I thought that lead means how much linear distance you get per one revolution of the ball screw. not per a motor revolution behind the gearbox.
The lead of the ball screw is the linear distance you get per one revolution of the ball screw; however the lead of the system is equal to the linear distance from one rotation of the input, in this case a motor. Most of the time when we use this equation, we are trying to solve for the torque required by the motor, so we include the gearbox into the lead equation. For more information or assistance, please contact: automation-apps@us.schunk.com
What if it is horizontal?
The torque equation presented in the training video applies to horizontal and vertical motion. The force value tends to be less during a horizontal motion as the moving payload is not move against or with gravity. The force value for horizontal motion would be the payload times acceleration (due to the move) plus friction force (payload x gravity x friction).
Please contact the SCHUNK Automation Team at automation-apps@us.schunk.com for application review and assistance.