hello! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?
Got my Maths GCSE exam tomorrow and your videos have helped me bump up my grade from a miserable D grade all the way up to a B/A grade! Thank you so much!
So, say I have a mixed packet of Sweet Bell pepper seeds that contains equal parts of 5 different varieties, what is the minimum number of seeds that I would need to plant in order to ‘guarantee’ that I’ve planted one of each variety. 80% of them + 1, right?But, what if I had a bucket of seeds?! That’s a ridiculous amount of Bell peppers. So I thought, we’ll, I’m willing to utilize two rows in my seed starting tray. That’s 12 cells. There are 39 seeds in the packet. An equal 20%of each variety (orange, white, purple, yellow, and red) included in the packet, according to Burpee. What are the “odds”, “%chance”, or “probability” (i’ve been thinking about this too long and I’m not even sure which I’m asking for anymore lol) that I will have planted at least one of each variety? This brain teaser has got me stumped. Please and thank you
He takes one out, represented in the first 3 branches, then in the second branch, he decreases the denominator, symbolising he has already taken out the first ball.
Send me answers for A box contains 4 pink counters 3 green counters and 3 yellow counters . 3 counters are drawn at random one after the other without replacement . (a) Find the probability that the third counter drawn is green and the first two are of the same color. (b) Find the expected number of pink counters drawn.
Thank you so much this was so helpful!
I have an exam tmrw and my teacher forgot to tech us this and we need it for the test so thank you!!!!
@RepublicOfNewEnectra good luck
One of the best teachers on TH-cam. Thanks!!
This video just saved my life thank you 🙏🏽😭
Dw nigha u wil be fine
You wrote b instead of w in the last branch
haven't you done it wrong?
it says that 2 were taken out, so it must be out of 10 not 11
He wrote 11 because at that stage he hadn't taken the 2nd one out.
Hope this helps
hello! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?
Thanks so much this really helped my daughter
Got my Maths GCSE exam tomorrow and your videos have helped me bump up my grade from a miserable D grade all the way up to a B/A grade! Thank you so much!
Is it possible if we can simply again?
Oooh, that was easy. Thanks 🎉
Why did he use 1/3 to multiply at 2:26 though. Pls help 😭😭
1/3 is the same as 4/12 when simplified
@@Lynne.cee15how do you know the ball that is picked?
@@KayKizzy-o5yyou dint the tree diagram shows the possible probabilities
@@KayKizzy-o5ywait wdym
can you upload with different number ,I'm still confuse
You videos are nice
THANK YOU
So, say I have a mixed packet of Sweet Bell pepper seeds that contains equal parts of 5 different varieties, what is the minimum number of seeds that I would need to plant in order to ‘guarantee’ that I’ve planted one of each variety. 80% of them + 1, right?But, what if I had a bucket of seeds?! That’s a ridiculous amount of Bell peppers.
So I thought, we’ll, I’m willing to utilize two rows in my seed starting tray. That’s 12 cells.
There are 39 seeds in the packet.
An equal 20%of each variety (orange, white, purple, yellow, and red) included in the packet, according to Burpee.
What are the “odds”, “%chance”, or “probability” (i’ve been thinking about this too long and I’m not even sure which I’m asking for anymore lol) that I will have planted at least one of each variety? This brain teaser has got me stumped.
Please and thank you
Great work , Thank you
thanks bro
thanks
U took out one with no replacement yet the question says two
He takes one out, represented in the first 3 branches, then in the second branch, he decreases the denominator, symbolising he has already taken out the first ball.
Omg thank you so much
Send me answers for
A box contains 4 pink counters 3 green counters and 3 yellow counters . 3 counters are drawn at random one after the other without replacement .
(a) Find the probability that the third counter drawn is green and the first two are of the same color.
(b) Find the expected number of pink counters drawn.
call nenna
Thank you soo much
You wrote B instead of W why hmmm???
Same doubt here
indeed
i konw very simple method
=4/12*8/11+4/12*8/11+4/12*8/11
=8/33+8/33+8/33
=8+8+8/33
=24/33
thats it ☺☺☺
Ó81
Bla bla bla BORING you seemed a bit worried too cuz the pen slipped from your hand 🤣🤣🤣
Your just dumb at math lol
Thank you