Sir, if v of first lens is incident ray for second one, than incident ray is coming from right, this means distances in right should be taken as negative for second lens, therefore we should take u=-10 for second lens. Only than v becomes positive infinity or else it is becoming negative infinity. Our ray diagrams also show that image is forming at positive infinity by second lens.
what sir did is correct.Even if you take for second lens left direction as positive direction then also you will get the same result since everything becomes negative and you can cancel the -ve sign on both sides
Sir, which is the second lens in the last example you were talking about, and why is it that you were taking u =+10 and why is f=-10 for the second lens? Anyone, please feel free to answer!! Thankyou
btw, have sir written the correct formula of magnification? because in ncert its " height of image/ height of object = v/u" but sir has written height of image/ height of object with a negative sign?
yes, sir is using the sign conventions, but we don't need to...just follow NCERT rules..do this derivation without sign conventions to obtain correct resutls without any commotion
Great Sir 🙏🙏🙏🙏🙏🙏
LORD OF PHYSICS THNKS SIR
Sir, if v of first lens is incident ray for second one, than incident ray is coming from right, this means distances in right should be taken as negative for second lens, therefore we should take u=-10 for second lens. Only than v becomes positive infinity or else it is becoming negative infinity. Our ray diagrams also show that image is forming at positive infinity by second lens.
what sir did is correct.Even if you take for second lens left direction as positive direction then also you will get the same result since everything becomes negative and you can cancel the -ve sign on both sides
Sir, which is the second lens in the last example you were talking about, and why is it that you were taking u =+10 and why is f=-10 for the second lens?
Anyone, please feel free to answer!!
Thankyou
tintoo viji
Same question here
Did U get its solution?
Sir, is f of the second lens taken with respect to the second convex lens and u with respect to the concave lens or convex lens?
Sir , why we study only power of a lens and not power of a concave mirror or convex mirror??
brother same result
Sir kya asp board copies bhi check krte h
i will be greatfull if you explain numaricals on combination of lens and mirror.
first lens has two focal lengths... how can we write f for each lens
sir at 17 we put -ve against u but we have already put - agaist OC
good
Sir 2016 mein combination of lens and mirror nhi h?
Sir you are great
For best result see Pradeep Kshetrapal videos at 1.5x
Shashank Singh
I m seeing like this
yes am also
I am seeing at ×2
👍
sir in last example v for second is infinity how?? isn't it should be -100
sir you have written the magnification formula to be -v/u but in ncert it is given v/u
Thank u so much sir
at 16:31...we can't apply sign conventions twice to the same optical quantity in the same derivation...and u have applied it for object distance
international Remixes have you found the solution of this doubt ?
yes!!!!.....according to NCERT..do not follow sign conventions since from the starting of the derivation..!!!at the end..the result will be correct.
btw, have sir written the correct formula of magnification? because in ncert its " height of image/ height of object = v/u" but sir has written height of image/ height of object with a negative sign?
yes, sir is using the sign conventions, but we don't need to...just follow NCERT rules..do this derivation without sign conventions to obtain correct resutls without any commotion
international Remixes alright thanks
Lecture starts at 7.06
THANKS A LOT...................
Good