Rotor is open circuited so there is no back emf thats y we r applying less voltage that is 20 to 25 % of Rated voltage to stator... I hope this is clear to u
See emf from faradays law is directly proportional to the change of flux not the flux, so from this analogy if you take phi = BA cos(wt) then if you differentiate it to obtain the emf the cos(wt) gets converted to sin(wt) now at d axis the wt i.e the angle between the B vector and A vector is zero. So the wt=0 so sin(wt)=0, so the emf becomes zero when the SMF aligns itself along the d axis. Hope you are clear
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Thank you very much sir for providing us precious knowledge free💯❣️
Sir, make more videos on all concepts.
Sir.... rotor is open circuited know?
Then what is the significance of applying less than rated voltage. What happens if rated voltage is applied ?
Rotor is open circuited so there is no back emf thats y we r applying less voltage that is 20 to 25 % of Rated voltage to stator... I hope this is clear to u
All concepts got clear.... awesome lectures
Awesome lectures sir
thanks Sir🙏❤
Sir why Isc lags Ef by 90° during short circuit
Thanks very very much
Actually EMF is directly proportional to Flux ... So whenever flux is maximum then induced emf is also maximum @ D axis... Why EMF is zero at Max flux
See emf from faradays law is directly proportional to the change of flux not the flux, so from this analogy if you take phi = BA cos(wt) then if you differentiate it to obtain the emf the cos(wt) gets converted to sin(wt) now at d axis the wt i.e the angle between the B vector and A vector is zero. So the wt=0 so sin(wt)=0, so the emf becomes zero when the SMF aligns itself along the d axis. Hope you are clear
Sir give lectures in English
Hum you tube regional language me padhne ke liye use karte hai ja tu college me dhyan se padh waha English me hi sikhate hai
Sir give lectures in English