Einstein Hilbert Action (General Relativity)

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  • เผยแพร่เมื่อ 29 พ.ย. 2024

ความคิดเห็น • 35

  • @PhysicsUnsimplified
    @PhysicsUnsimplified  4 ปีที่แล้ว +16

    The result at 4:39 for the variation of the Christoffel symbols contains a typographical error. The covariant derivatives should act on the variation of the metric, not on the metric itself. This error persists throughout the video.

    • @user-sc2cz4hp3z
      @user-sc2cz4hp3z 7 หลายเดือนก่อน

      is theses differential foms usefull like biannchi identity?

  • @ly.s.9441
    @ly.s.9441 11 หลายเดือนก่อน +1

    Wow, very clear.!! I didn't use to understand the total derivative term from the variation of Ricci tensor ever. Thanks !!. I could've not made it without you.!

  • @RuanD
    @RuanD 5 หลายเดือนก่อน

    I've watched this video so many times to review the subject. Thank you for making it!

  • @gentlyschannel4193
    @gentlyschannel4193 4 ปีที่แล้ว +10

    My only hope is that one day, after watching several hundreds of these videos, I may understand just one of them.

    • @PhysicsUnsimplified
      @PhysicsUnsimplified  4 ปีที่แล้ว +3

      It's a challenging subject, for sure. Good luck!

    • @michaellewis7861
      @michaellewis7861 4 ปีที่แล้ว +3

      Gently's Channel Watch eigenchris’s tensor algebra and calc video. You’ll get it then.

    • @miguelpedro9005
      @miguelpedro9005 4 ปีที่แล้ว +2

      you should study from the beginning. osmosis don´t work.

  • @yonggao3349
    @yonggao3349 4 ปีที่แล้ว +5

    so clear and well organized, great work!

  • @akushutako4160
    @akushutako4160 4 ปีที่แล้ว +2

    Thank you for the explanation! The style of the video is very clear

  • @ly.s.9441
    @ly.s.9441 11 หลายเดือนก่อน

    At 5:39~5:40, when Riemann tesor is contracted with g_(μ)^(ν) to make Ricci tensor, isn't "g_(μ)^(ν)" term also subject to variation?

  • @namesurname1040
    @namesurname1040 4 ปีที่แล้ว +1

    Very clear vudeo! It really helped me. But I had a question. How we define a boundary term? Thank you for your time!

  • @timokimo8206
    @timokimo8206 2 ปีที่แล้ว

    Now I can understand moon orbiting behavior

  • @VictorKenjii
    @VictorKenjii หลายเดือนก่อน

    Could you give me the bibliographical references that were used in this video?

  • @anarakberov7173
    @anarakberov7173 4 ปีที่แล้ว

    thanks for the clear explanation

  • @NH-zh8mp
    @NH-zh8mp 8 หลายเดือนก่อน

    okay, so first let me state the definition for the variational operator. This definition is referenced from Haim Brezis - Functional Analysis.
    Let H be a Hilbert space, let A ⊆ H and M is a subspace of H. Consider a functional J : A ⟶ IR, u ⟼ J[u].
    For v ∈ M and u ∈ A, We define the Gateaux derivative of J at u in direction v as the following limit when ε → 0
    lim ( J[u+εv] - J[u] )/ε =: δJ/δv [u]
    So basically, the Hilbert action S_EH is a functional. So what is the Hilbert space H, the subset A and the subspace M in this context ?

  • @ARBB1
    @ARBB1 3 ปีที่แล้ว

    Very well done

  • @fairweatherfoundry715
    @fairweatherfoundry715 4 ปีที่แล้ว +1

    Can you do a video about the Lagrangian formulation in general relativity?

    • @fairweatherfoundry715
      @fairweatherfoundry715 4 ปีที่แล้ว

      Preferably in the hand writing style video. The computer generated videos are super cool to look at, but they go really quick and are more difficult to follow.

    • @PhysicsUnsimplified
      @PhysicsUnsimplified  4 ปีที่แล้ว +2

      I would love to cover that topic. It's on my list of things to do, I just need to find the time...

  • @longsarith8106
    @longsarith8106 2 ปีที่แล้ว

    Excuse me sir. What happen if take variation of Ricci Tensor Rab with respect to variation of inverse metric tensor gab?

    • @schrodingerscat7218
      @schrodingerscat7218 ปีที่แล้ว

      If you did that you would defeat the strategy which is to get all three in terms of delta g ab downstairs. You would be in a different movie, dude.

  • @NH-zh8mp
    @NH-zh8mp 8 หลายเดือนก่อน

    what is the definition of "d^4" ?

  • @User-jr7vf
    @User-jr7vf 4 ปีที่แล้ว

    Noticed that you changed from hand writing. Are you going to stick with this new type from now on?

    • @PhysicsUnsimplified
      @PhysicsUnsimplified  4 ปีที่แล้ว

      I haven't decided. The computer generated video is very labor intensive to create. So we'll see...

  • @SunilGupta-ht5gh
    @SunilGupta-ht5gh 4 ปีที่แล้ว +1

    General relativity credit to Hilbert

  • @Godakuri
    @Godakuri 3 หลายเดือนก่อน

    Okay but you barely explained going frok one step to another

  • @pacajalbert9018
    @pacajalbert9018 3 ปีที่แล้ว

    10 sekúnd = 100 rokov

  • @shanewilson1160
    @shanewilson1160 4 ปีที่แล้ว +1

    what the fuck is this?

    • @timokimo8206
      @timokimo8206 2 ปีที่แล้ว +2

      Finally, i see response that makes sense😂

    • @schrodingerscat7218
      @schrodingerscat7218 ปีที่แล้ว

      Many years ago a man named Einstein discovered, partly by guessing, a now famous equation (no, not e equals mc squared) and a few years later someone else came along and said that this same famous equation, discovered by Einstein, could actually be derived from an action principle if you start with the right Lagrangian. Well, this is that. Now you know. Funny, I asked the same question about two years ago!