Alternative solution: 1.005^200 = (1 + 0.005)^200 If you expand that out you get 1^200 + 200 * 1^199 * 0.005 + ... Call all the later terms S and you have 1 + 200*0.005 + S = 1 + 1 + S = 2 + S S we know to be non-zero and positive therefore 2 + S > 2
Alternative solution:
1.005^200 = (1 + 0.005)^200
If you expand that out you get
1^200 + 200 * 1^199 * 0.005 + ...
Call all the later terms S and you have
1 + 200*0.005 + S
= 1 + 1 + S
= 2 + S
S we know to be non-zero and positive therefore 2 + S > 2
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1² we define the real.
Can't I use this proof to prove that 2 < 1.005 ^ 100?