everything is good and well explained but the slope calculation at 4:29 is wrong for region 1 and 2. u see for region 2 in the picture slope should be -1. i think mam took this values from some book but forgot to correctly mark the regions in the picture
take the partial derivative of the equation with both x and y. Divide them both and put the negative sign. dy/dx = -fx/fy where fx and fy are the partial derivaties.
Your video's screenshots have been included in a ppt being circulated by the professors at Thapar University. Was this intentional or without your knowledge?
U r differentiating y w.r.t x . so in this case when u take derivative of y2 w.r.t x then it becomes 2y.dy/dx . For more info u need to study basic rules of differentiation.
In region 2 derivation, it should be "p2K+1 - p2k" instead of "p2k+1-p1k" at the end of page at 19:21. Thanks for the amazing explanation
Your Handwriting/Presentation/Explanation/Voice is so good, simply splendid.
simp
practise ab exam mey hi hoga
Nice
Bhai bachche ho gye honge aapke
😂😂😂😂😂@@jaishree701
@@shashanknegi7861 bhai Shashank naam ke ladke itte nakchade kyom hotrbhain mere batch mein ek khadoos hain Shashank naam ka bahut troll krta mannr
CORRECTION
At 14:50, SEE,
Part where p1k>=0
Last red boxed value is wrong at last part where she wrote -2yk+1.r2x
Check for it
That part is wrong
thanks just wanted to confirm this
everything is good and well explained but the slope calculation at 4:29 is wrong for region 1 and 2. u see for region 2 in the picture slope should be -1. i think mam took this values from some book but forgot to correctly mark the regions in the picture
your teaching style is very simple
Excellent & deep understanding teaching....
Thanks mam for all these videos and making computer graphics easy for us to understand.
Thank you mam 😊
Nice explanation, Thank you for your effort
Worth appreciating .. thanks for the wonderful explaination.
thanks for explaining computer graphics..... wonderful teaching
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
yes can plzz answer this ques its urgent
take the partial derivative of the equation with both x and y. Divide them both and put the negative sign. dy/dx = -fx/fy where fx and fy are the partial derivaties.
Thapar university walo ne aapke video ke screenshots use kiya hai as notes for students even after paying 25 lakhs ,but still thank you very much
Making the things so much complex ..better to explain in easy way to save time 😊
It is so helpful... Thank you🔥🔥
11:31
very nice
please add more topic in computer graphic!!
very useful stuff, Thankyou!
A rare yet refreshing sight of an enthusiastic student willing to expand his knowledge.
Fills my heart with joy :'(
@@MrSachinmondal Then why are you sad lol?
Your video's screenshots have been included in a ppt being circulated by the professors at Thapar University. Was this intentional or without your knowledge?
mam , region 1 and 2 mai jab hamne cases banaye to usmai equal to zero wale case clear nhi hua!!!!
Mam can you make video on DDA circle drawing algorithm.... Plz.......
14:40 😑😮💨😮💨nooooo
Why do we have to subtract the equations.
What actually the slope of ellipse is?
Mam I think it's not the slope of curve...it's slope of the tangent at the points of curve...☝️😊
hello ma'am I want to know about the computer graphics practical basics.
Thanks for explanation, I am going to skip this question.
nice
Your voice is too cute and keep making this content plzzzz!!!!!!!!!!!
Xk+1 ko kyu ni khola?pk
its not right!'
pehele khud sekhle fir video bnaio
agar ata ni hai to video kyu bante ho faltu baccho ko galat pada rahe ho kya qualification hai tumhri?
Ye madam reply nhi krti
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
as y is a variant in itself you differentiate y terms and according to the chain rule you write dy/dx . so dy/dx(y^2) = 2y.dy/dx
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
Yes I aslo have same doubt did you clear it
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
U r differentiating y w.r.t x . so in this case when u take derivative of y2 w.r.t x then it becomes 2y.dy/dx . For more info u need to study basic rules of differentiation.
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
Can you please explain me how dy/dx(y^2) = 2*y in the slope condition derivation. Isn't it wrong?
I had same doubt b/c she had written dy/dx instead of d/dx
So correct eq will be dy^2/dx =2y.dy/dx