This program (and the associated comments below) clearly demonstrate that most people have problems with math due to bad teaching. Here the presentation is clean, orderly, divided into just the right "chunks" and, to top it off, delivered in a pleasing voice. Great job!
How can I spend 3-4 hours in lectures and be clueless, then turn around and spend 1 hour on this channel and know everything I didn't understand in the lectures?? Sometimes I feel like I'm wasting my money and that these channels should profit.
Ikr. I'm currently in high school taking bc calc so I don't have the same struggle as you with feeling like I'm wasting my money, but I can relate to what you're saying though. I never learned this in a classroom because... well school hasn't started quite yet for me. I watched all his vids on derivatives and parametric equations and now I feel like I could teach them to another student because he just does it that well.
i literally pay a thousand dollars to my university and still not understand a thing... but i do get it in a 10 minute video?? you sir are the best, you helped me a lot!
I was in tears over here, thinking I was stupid. Your content made me realize that just because you are good at math DOES NOT qualify you to teach math. I'm so very grateful. Thank you, thank you 100 times over.
You make everything so easy to understand. I am going into my first calculus course and thought I would be struggling a ton, but if I just make sure to come and learn stuff from your vids while studying everything seems like it will be a breeze.
So clearly explained. No fuss, just , this is how you do it. Thank you for saying it clearly. I have no doubt that in the future we shall come to understand what finding a derivative means in the real world and why it is used but I shall be prepared for that when the time comes. Again a big thank you.
Thanks to your videos I could finally understand 18 hours worth of lectures. My only problem is that I get flustered when I see square roots and fractions. Help me overcome this hahahaha thank you again!
Wow I wish I would have found your channel before my first calculus exam (which the entire class bombed the professor curved it by 50 points). Thank you so much for making these videos you are saving me rn!!
I kept waiting for him to take care of that radical in the denominator -- 1/(2*sqrt(x)) multiply by sqrt(x)/sqrt(x) yielding sqrt(x)/2x -- plug that in much more easily than that first form ;-)
WOW!!!!! THANK YOU, VERY MUCH, FOR MAKING THIS SO COMPREHENSIBLE!!!! I'M EAGER TO KEEP GOING!!!! THIS IS GREAT!!!! NOW, ...WHERE CAN WE "APPLY" THIS KIND OF MATH???!!!
You can often "think backwards" to get these. For example the derivative of what would give us sin ? That would have to be - cos. So we can say that the anti-derivative of sine is negative cosine. :^D
Greetings and thank you for all of the great help. Just wondering (around 5:20) why it is d/dx(x) to the exponent of 1/2? I know that the x is originally under a square root, but I'm not sure why that leads to the power of 1/2. Thanks in advance!
The way it works the square root splits everything in half (except for prime numbers). Figuratively speaking, 1 can be cut in half, but in higher math we stick to reality. Although mathematics doesn’t stop. Meaning we imagine the possibilities, not just reality. That is the power of assumption. For that assumption capacity is the source of our mathematics. As you go beyond this point; mathematics becomes a theory. Although this is my theory.
True, the order does not matter in this case, but since the quotient rule (where the order does matter) has f'g as the first term in the numerator, it is best to always start with f'g. Then you'll never run into doubt.
Jhelo Mae Betarmos haha thanks, I haven’t seen this video in ages! I’m doing graduate school mathematics now, hard to believe I still didn’t know the product rule four years ago!!
I don't even see how you get that, and I think you want the terms to be distributed. 2e^x( (1/√x) + 2√x ) will work, but that isn't much simpler. To put irrationals on the top of fractions, we can now factor out √x and get 2e^x √x( 1/x + 2).
I've just spent a year doing a maths module with the open University and come out unable to remember any of it. I watch this and it's sticking (and has taken an hour).
Why not just expand the brackets by the factor of the function then get the derivative of those terms, instead of finding two different functions of the rule separately then combining them with the primes and normal functions at the end which seems like extra complexity to remember.
You mean to recombine the factors into 3x⁴ + x² and then differentiate it to 12x³ + 2x? Yes, but I suppose we ignore that here in order to teach the rule. The only difference is choosing an expression you couldn't recombine to make it simpler That would require a more complicated outer function that might complicate the teaching process?
As he said, distribute the square root x So, it would be (3x^2 sqr x + 4x sqr x) And then, you'd place the x^3 +2x^2 on top of the fraction that is beside it, so it would be X^3 + 2x^2 ---------------- 2 sqr x You can, then, factor out a x^2 X^2 (x + 2) ---------------- 2 sqr x
can you compute the deriative of G(x)=-3x^5 X (-9x^3). I know the answer is 216x^7 but im stumped when it comes to using the product rule formula. I have half of the equation solved. g'(x)= (-3x^5) X (-27x^2) +(_______) X (______) =216x^7. PLEASEEEE HELPPPP THANK YOU IN ADVANCEEEEEEE
This program (and the associated comments below) clearly demonstrate that most people have problems with math due to bad teaching. Here the presentation is clean, orderly, divided into just the right "chunks" and, to top it off, delivered in a pleasing voice. Great job!
Feernwald84, well said. You are on point!
How can I spend 3-4 hours in lectures and be clueless, then turn around and spend 1 hour on this channel and know everything I didn't understand in the lectures?? Sometimes I feel like I'm wasting my money and that these channels should profit.
Ikr. I'm currently in high school taking bc calc so I don't have the same struggle as you with feeling like I'm wasting my money, but I can relate to what you're saying though. I never learned this in a classroom because... well school hasn't started quite yet for me. I watched all his vids on derivatives and parametric equations and now I feel like I could teach them to another student because he just does it that well.
Bro I quit going to class because I can't understand shit, but as soon as I come here everything is much more easier to understand
The understanding of any concept depends largely on the instructor and how you relate personally with the teacher.
SAME! Ive been confused a whole semester watch a few of these and im good lol
Everyone here is possessing disillusion
i literally pay a thousand dollars to my university and still not understand a thing... but i do get it in a 10 minute video?? you sir are the best, you helped me a lot!
I was in tears over here, thinking I was stupid. Your content made me realize that just because you are good at math DOES NOT qualify you to teach math. I'm so very grateful. Thank you, thank you 100 times over.
You make everything so easy to understand. I am going into my first calculus course and thought I would be struggling a ton, but if I just make sure to come and learn stuff from your vids while studying everything seems like it will be a breeze.
This video was extremely helpful, thanks! I have an exam tomorrow and I feel a lot more confident about it now
This guy is really good in explaining. I now believe I can manage to pass my calculus test. Thanks much.
So clearly explained. No fuss, just , this is how you do it. Thank you for saying it clearly. I have no doubt that in the future we shall come to understand what finding a derivative means in the real world and why it is used but I shall be prepared for that when the time comes. Again a big thank you.
I can't thank you enough. This whole semester I was so confused and as soon as I found your videos I aced my test. You are an amazing teacher!
Glad I could help! Keep up the good work. :^D
Thank you so much! I have my first calculus exam this upcoming Wednesday and you made it so simple!
Thanks to your videos I could finally understand 18 hours worth of lectures. My only problem is that I get flustered when I see square roots and fractions. Help me overcome this hahahaha thank you again!
Wow I wish I would have found your channel before my first calculus exam (which the entire class bombed the professor curved it by 50 points). Thank you so much for making these videos you are saving me rn!!
That is one crazy curve! Hope the next one goes a bit better. With some hard work I know you can do it. :^D
I m truly grateful to you for your derivative lessons....
stay blessed.
Thanks. Really helpful for 6th graders like me who can actually relate to it, unlike college lectures.
Now I got a better understanding of Product Rule instead of using the textbook.
My tuition fees should go to you instead
You are the best teacher ever, I liked your video and subscribed too, keep up the good work
This one is too easy that any not being good at maths can also get it well.thsnks
i enjoy maths whenever i watch dis guy.....kudos mhen
Great video man 😃 I like the positive vibe!
Thanks for the help.
I got kinda pissed when you didnt finish the second question
For real, do you know the answer by any chance
bruh my professors be pulling the same thing and expect us to know what to do in exams
I kept waiting for him to take care of that radical in the denominator -- 1/(2*sqrt(x)) multiply by sqrt(x)/sqrt(x) yielding sqrt(x)/2x -- plug that in much more easily than that first form ;-)
WOW!!!!! THANK YOU, VERY MUCH, FOR MAKING THIS SO COMPREHENSIBLE!!!! I'M EAGER TO KEEP GOING!!!! THIS IS GREAT!!!! NOW, ...WHERE CAN WE "APPLY" THIS KIND OF MATH???!!!
I am impressed by seeing your video i everything about calculus now thanks a lot
Waooooo!!!!!!! This is great,i had fed my brain with something unique today,thanks to myschoolsecret educator.
I'm actually understanding maths now . xD
learn math with this one simple channel ! teachers hate him
Wow...you explained it like a magic...thank you sir!!! :)
This is my introduction to this stuff, and it seems pretty straight forward, I was expecting some crazy 26 dimensional physics.
What is Antiderivative?
And, what is the derivative of Sine, Cosine, Tangent, Cotangent, Cosecant, Secant, and whatever?
(Best channel ever for ...)
You can often "think backwards" to get these.
For example the derivative of what would give us sin ?
That would have to be - cos.
So we can say that the anti-derivative of sine is negative cosine. :^D
Calculus is no longer the bugbear or Mumbo jumbo to me !.For the first time in 60 years I understood it by this video!.Ta!.
I love learning about calculus
this man is a legend
You are the best tutor ever!!! Many thanks! =D
you re an excellent Tutor
I’m a sophomore and I’m just getting an idea of Calculus and omg I understand this so much now I thought it was going to be complicated damnnnn
thanks sir for your lovely explanation!!!!so easy to understand.
Greetings and thank you for all of the great help. Just wondering (around 5:20) why it is d/dx(x) to the exponent of 1/2? I know that the x is originally under a square root, but I'm not sure why that leads to the power of 1/2.
Thanks in advance!
A square root is basically a 2 in the b part of the rational function but it’s never acc shown so it would be 1/2
The way it works the square root splits everything in half (except for prime numbers). Figuratively speaking, 1 can be cut in half, but in higher math we stick to reality. Although mathematics doesn’t stop. Meaning we imagine the possibilities, not just reality. That is the power of assumption. For that assumption capacity is the source of our mathematics. As you go beyond this point; mathematics becomes a theory. Although this is my theory.
You're a god send brother :)
True, the order does not matter in this case, but since the quotient rule (where the order does matter) has f'g as the first term in the numerator, it is best to always start with f'g. Then you'll never run into doubt.
Thank you sir for the detailed explanation.great sir🤩
Beautiful explanation. Needed it for PCAT studying and this helped me rememeber stuff that I have taken a while ago thank you so much.
Hey man, AWESOME video, super helpful. But how do you simplify the expression at 7:14?
Where does the (x^3+2x^2) go?
@@Cosmalano highest to lowest variables
Jhelo Mae Betarmos haha thanks, I haven’t seen this video in ages! I’m doing graduate school mathematics now, hard to believe I still didn’t know the product rule four years ago!!
Gosh ! Looks like I'll love calculus because of you ❤ .. lol
Thank you so much I understand more. 😄
can you share with us how to simplify the equation, please
thankyou!!!! NEEDED SOME EXPLANATION LIKE THIS
what an explanation! Salute....
Very straight forward. Thank you!
thank you so much
Thank you so much sir you helped me alot.
Thanks man it really helped 👍
thanks for this video, it's very simple to understand :)
Dude you are carrying me through my entire finals
Cool video! But in the last exercise can i factorise and write 4e^x[√x+1/(2√x)]?
I don't even see how you get that, and I think you want the terms to be distributed.
2e^x( (1/√x) + 2√x ) will work, but that isn't much simpler. To put irrationals on the top of fractions, we can now factor out √x and get 2e^x √x( 1/x + 2).
I just realized how easy derivatives are!!
You're an mvp.
I've just spent a year doing a maths module with the open University and come out unable to remember any of it. I watch this and it's sticking (and has taken an hour).
Nice work
mate your deadset legend
im in 11 class and my chemistry exam is tommorow and im not studying maths currently and this just seems fun
great work,thank you
Wow made it very clear/easy.
From where does product rule forumulae and quotient rule come from?
do you have a vdo for the power rule?
Please give description about the basic of Function
Very helpful 👍🏼
I can't seem to figure out how to solve (x+7) to the 4th power over (x+7)^2 square root(x + 7)
Isnt The First Question factorised? Why cant we simply expand it and find The Derivative?
Is this applicable in this problem? f(x) = 2x^4+3x^3-2x+7; f' (0). If so how?
on the very last equation couldn't you have factored the 2e*x
From where l can have these markers they are so amazing
I use Vis-a-vis markers. They are nice and dark, and I can erase them when I'm done. :^D
@@MySecretMathTutor l don't know whether l would get them or not....but I am really crazy for the way you write....its amazing beyond limits
what will be the answer for n√x log √x, x >o
Thanks very much
Why not just expand the brackets by the factor of the function then get the derivative of those terms, instead of finding two different functions of the rule separately then combining them with the primes and normal functions at the end which seems like extra complexity to remember.
??
You mean to recombine the factors into 3x⁴ + x² and then differentiate it to 12x³ + 2x? Yes, but I suppose we ignore that here in order to teach the rule. The only difference is choosing an expression you couldn't recombine to make it simpler
That would require a more complicated outer function that might complicate the teaching process?
in the last equation isnt the derivative of 4 =0 ?
fr tho
If it was 4 + e^x, but it's 4•e^x instead.
Thank u sooo much 😁
can someone furthermore explain or simplify the 2nd problem for me ? I kinda want to know what its outcome is
As he said, distribute the square root x
So, it would be (3x^2 sqr x + 4x sqr x)
And then, you'd place the x^3 +2x^2 on top of the fraction that is beside it, so it would be
X^3 + 2x^2
----------------
2 sqr x
You can, then, factor out a x^2
X^2 (x + 2)
----------------
2 sqr x
u should finish simplifying especially in some hard examples
Please explain rules also 😫
just one thing about the power rule can't understand why 3x^2 is equal to 6x?
it's because the power of x will multiply with the constant and 1 will minus from the power.
Like 3x^2 =3*2x^2-1 =6x^1 =6x.
It is not EQUAL, but one is the derivative of the other, yes. It would be equal for x=2 but not x=10 for example.
thanks good
this rocks 👍
And I love you videos
can you compute the deriative of G(x)=-3x^5 X (-9x^3). I know the answer is 216x^7 but im stumped when it comes to using the product rule formula. I have half of the equation solved. g'(x)= (-3x^5) X (-27x^2) +(_______) X (______) =216x^7. PLEASEEEE HELPPPP THANK YOU IN ADVANCEEEEEEE
So simple.
Y= Sin38[cos23-sin 34]
there is a mistake in the first example
I wanna help in Leibniz theorem
thankyou
ur hand in marriage?
This is my first liked video on TH-cam.
nice
n another sum (3sec x -4cosec x) (2sinx+5cosx)
In first example f'(x) by power rule =2x but can we further take its derivative d(2x)/dx =2*dx/dx=2??? Can't we do this??
What?
I could not understand the 2nd last example
if it is happening it is really happening much true believe it or not sugunakar
I don't understand why this guy complicates everything by using f and g when the formula clearly uses u and v.
I’m 5+5-2+3-2+1
Freebird!!
What level of maths is this its seem basic!..
High school to AP to University every level depending on where you are.
my college fees should go you