RC Circuit Hard HW Problem - 4 resistors 2 capacitors
ฝัง
- เผยแพร่เมื่อ 28 ก.พ. 2014
- Looks at currents and voltages in an RC circuit just after the switch is closed and after the switch has been closed a long time. Shows how to use the golden rules about how a capacitor acts like a wire when the switch is first closed and how it acts like it is removed from the circuit (acting like an open circuit in fact) after the switch is closed a long time and the capacitor(s) has been fully charged. Also shows how to calculate the voltage on the capacitors after the switch has been closed a long time. In it you will see that one capacitor is charged and the other is not.
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Beautiful explanation
You could also find the voltage difference between the plates of 1st capacitor by creating a Kirchoff loop including 6ohm, 2ohm, and the 1st
capacitor. Setting the eq.
Vc-6*1-2*0=0
Therefore, Vc = 6V
On the other hand, thank you for this nice video, sir!
Thanks so much for your explanation! I liked your analogy about capacitors acting like wires until they are fully charged. Helped me out quite a bit.
Sir,this solution is really really great. The concept of Shortcuiting the capacitor initially is new to ke. Thanx.
Thank you for this video! I learned something important!
Thank you so much this video helped out a lot!
Thank you for the excellent video! I wish you had more on this stuff!
Thanks for explaining!
Frank,
If I remember correctly, you were fairly tall, slender dude from Lewis, was it? So why did you come across this video?
Lt Col (R) Glodowski
I have a question i dont know how to solve
How can i contact you and send you the question sir?
Very well explained.
Thank you, mister!
Excellent video!
Thanku sir for this good explanation
This was cool sir
Good morning sir, please help me understanding of total horizontal and vertical, RL parallel to capacitor?
thank you. This video helped a lot.
thank u prof Alan ....i found that very useful 4 me ....plz can you help me WITH recomended book or student book with more example for resistors and capacitors connection in DC
ALAN GLODOWSKI
without the LOAD,
how much current in amps can a 4700uf hold store with a power supply DC voltage at +450vdc? the 4700uf filter cap will charge up to +450vdc but how much current is the 4700uf holding storing?
What formula can I use to calculate how much current the filter cap is storing in amps?
grateful for the vido
شكرا استمر في العمل الرائع Thank you so much
Is there a way to calculate the time constante of such a circuit ?
A simple circuit would be Tau = R*C .... but when you have multiple R and C components how do you calculate it ?
4 months late, there is thevenin equivalent circuit which deals with the exact concept you were looking for.
Well done
The title said hard , but was a piece of cake
capacitir as wires
new trick learnt
hey did u ever figure out why the cap looks like a wire at t=0
@@jjay11a I know it's two years late . but it's because at t=0 circuit is *just closed* so the charged that got *accumulated* in capacitor is almost zero .
holy shit you're actually the goat if anyone is reading this FUCK PHYSICS 142 WITH KEITH BERLAND AT EMORY UNIVERSITY
how to find
𝜏(time constant) if the RC circuit have more than one capacitor and of course 3-4 resistors
Use Thevnis circuit problem
Sir your solution for Current at t=0 is not appropriate. It should be 16/7 A in 2 ohm resistance. Plz reconsider. Regrets if I m wrong
Mans QB it takes path of least resistance. So it just go through the 2 ohm resistor
Good
Hey 6 ohm resistor just got short circuit ,how can you find the current in it
i thought capacitors behaved like open circuits in a dc source
This is what i'm wondering too.
that is when they are fully charged
For example, he uses open circuit for the caps at 3:32. He is only concerned with the first one because it disconnects the rest
Spoder Man I had stopped watching before coming there. Now i watched the full video, thank you for the information mate.
Only after ~5 effective time constants. Prior to this, current will be exponentially decaying in various loops while the capacitors are exponentially charging. Once the caps are charged (dV/dT ~0), then current is no longer flowing and Caps do indeed act like OCs. This is referred to as the "Transient Solution." and is usually not important other than to LEARN what is going on.
AC Source designs seek to achieve the more important "Steady State" solutions. These topics are used to design filters (low pass, hi pass, band pass, notch, etc). But the systems can get so messy, that computer simulations (SPICE, MATLAB) and other freq response programs are used to evaluate the SS response.
You work this circuit pretty weird
why didnt you solve it for any time t
Example to Acha liyr h smjane ke liye but .. Concept ka band bna diye h ... Jo phele bar capacitor padh ra ho wo na dekhe .. Other wise Jada doubt pak love man mai ar apna ho Jan re ho wo v concept kharab kar loge ...
Starting capacitor မှparallel resistor အကြောင်းသိ့ရှိ့ရန်
the capacitors would have a hard time filling with their annode connected to their cathode.
WTF! Dude! i thought that you were gonna calculate the voltage as a function of time....XD!!!!
Yeah I came here for that wanted to see how would he deal with complicated differential equations or is going to explain some new method to do it
@@lordvoldemort346 they are called trick my friends
@@guillermodiaz2773 you mean to say that I tell him on to solve 12th grade maths and he speaks the table of '5'
And it is a trick
Wow what an awesome trick
I was looking for something else he just solved the easiest case of the problem and that is a trick
Omg
I think you're wrong sir!! b/c capacitors behave open circuit to dc source not short circuit.
No, they act like shorts at t=0 and act like open circuits after a long time since no current can flow through them anymore. The current looks like exponential decay to zero at t>=0 when charging. Look up the graphs for this if you need a visual aid, it helps.
بالعربي
t>0 ???? fuck yah
this is pretty bad
it's actually very good and very methodical, you probably do not understand the basics of transient analysis
you did this wrong . y0u need to find R equivalent first
this is pure bullshit! what about tackling it like a real physicist instead of forming speculations? seriously what do i do with this method as long as i don't know the natural behavior of the circuit???
really bad explanation
waste of time
Example to Acha liyr h smjane ke liye but .. Concept ka band bna diye h ... Jo phele bar capacitor padh ra ho wo na dekhe .. Other wise Jada doubt pak love man mai ar apna ho Jan re ho wo v concept kharab kar loge ...