Determine the stretch in each spring for equilibrium of the 2-kg block

Determine the stretch in each spring for equilibrium
of the 2-kg block. The springs are shown in the equilibrium
position. Get the book: amzn.to/2h3hcFq

[@heidikeilback2671]

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[@lukeyoungblood4784]

King at it again with a great video

[@abigalemattingly357]

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[@FinalAnswer]

Thank you!

[@Rynntastic01]

Yo thanks dawg, this vid really helped me on a problem

[@jbbird3548]

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[@MohamedAboseliem]

Thanks for you❤❤❤

[@jesuslimon3885]

You are a god! thank you so much for doing these videos!

[@belalkasem4140]

Hi 😊
Iam very thankful for your explaining questions but i have another question that I didn't understand that..it is the same like this but the different is to calculate the weight of the block at D...can you help me?

[@Ali_T8888]

What program do u use to write on pc with mouse like this ??

[@fartbubble4088]

Why is Fd positive if it's pointing down?

[@ssm4363]

I think it is because we consider the point not the mass , if you think in this way yes the F that is downward is pulling the point downward but if you think about the mass the spring is pulling the mass up !! so we see the spring is always opposing (hooks law) , it pull mass up and pull the point that springs meet up down .

[@neomthimkhulu5896]

thank you sir i have a question on hpw tp calculate the mass of the pulley in coplanar force system and finding the uknown weight of the block

[@prospermahadjabbie4314]

i need more problem solving on equilibrium of particles

[@dontworry1568]

Where is -.707 coming from?!

[@Me12222]

cos45 = sqrt(2)/2 = .707... and the force is negative in x direction

[@edwardsam6894]

I need help man

[@jackcharcergraphics]

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[@murtez22]

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