I appreciate you effort but in this algo part 1&2 there is error, Initial Decision Parameter is of two type , but you wrote here only one and m>=1 ->P>=0 New Decision Parameter is also wrong. It May creates confusion as well as error
but sir when we take starting point as (6,4) and ending point as (3,13 ) then,,, none of the cases will work becoz there is not a single case for decrement of x corinate value since we want to go from 6 to 3 then how to solve this ?? please explain
Incomplete. I found out at the last minute before exam that you didn't mention conditions for negative slope. Students depend on your teaching and this shows irresponsibility.
bresenham circle Algo mein slope ki zarrorat nahi hoti. Line wale mein zaroori hota hai kyuki uske base pe hi fir konsa decision parameter use karna hota hai woh karte hai 2dx-dy ya 2dy-dx
Friends, if you are facing problems with Bresenhams Line Drawing Algorithm, it doesn't work at all when X1>X2 OR Y1>Y2 Please pin📌 this comment for a easy guide to everyone facing problems solving numericals.
but sir when we take starting point as (6,4) and ending point as (3,13 ) then,,, none of the cases will work becoz there is not a single case for decrement of x corinate value since we want to go from 6 to 3 then how to solve this ?? please explain
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What I notice about him is, a smiling face always putting efforts to make explanations easy. Hatts off to to this attitute of teaching😎😎
sir aapke bich bich me use kiye huye marathi words..........those are superrr awesome....
Sir, your teaching procedure is very good and I understand it very easily
lecture starts from 1:38
ty
👍🏻👍🏻👍🏻
Sir can u clear my doubt is in m>1(p>0)
Last step pk+1=pk+2x-y correct ya last step 2x-2y correct plz
Yes sir... Same doubt
What a explanation sir ek dam jabardast...
New style of teaching...i like it keep growing sir
Jo diagram tha vo thu ak dam ...dil ko chu ka gya
Bhaiya your content and way of teaching is amazing.
sir a small point I want to raise, please don't cut the videos in 2 parts and If you want to do it in two parts, please don't cut the video abruptly.
try going for (6,12) to (10,5)
HOW DO YOU PLAN TO DECREMENT??
4:27 best
😂😂😂
mind blown.. with ठोस आंकड़े😆
Bahut excellent explanation tha. Thankyou sir
MIND BLOWING EXPALNATION SIR........THANK YOU SO MUCH🙂🙂🙂
in dda the coordinfates were sometimes generated in flaoting value. Bresenhamn thus is needed.
what formulas will be used if slope is negative ?
m actually representing |m| (mod m)
use same formula as for m
Will be two conditions
|x|>|y| (neg slope)
Decision Parameter=2∆y-∆x
(Pk0)
X1=x+1
Y1=y+1
Pk+1=pk+2∆y-2∆x
|x|
I appreciate you effort but in this algo part 1&2 there is error,
Initial Decision Parameter is of two type , but you wrote here only one and m>=1 ->P>=0 New Decision Parameter is also wrong.
It May creates confusion as well as error
did you solve
Sir your content is so good but please use black marker
At 4:35 hehehe 😂😂😂 like it ❤️
4:30 pe wo hasi ka reaction kuch galat he tha:)
Myntra wala😅😅
Exam aagayaa apki yaad aa gai
but sir when we take starting point as (6,4) and ending point as (3,13 ) then,,,
none of the cases will work becoz there is not a single case for decrement of x corinate value since we want to go from 6 to 3
then how to solve this ?? please explain
sir looks like alakh pandey sirr
राम राम 🙇♂️✨
From which way I will thank you,
Now my only wish to meet you
Sir apki awaj ranveer singh jaise hai bilkul 😂❤
start from 1:50 please
few days before my exam
His laugh is giving me the Akhandanand Tripathi vibes from Mirzapur 💀💀
WATCH QUICKCS FOR THIS TOPIC AND FOR ALL STEPS FOR EXAM. HE SHOWED FOR SLOPE LESS THAN 0
Excellent 👍
Pyari Samaj gayee. :D
Hats off to you sir!!!
Aakde is emotion 😂
nyc video sir
Smile denotes the mamla(difficulty)😂
4:24 kuch yaad aaya broo
great explanation
Integral University Wale like kare
Why am I hearing Ranveer Singh teaching Computer graphics
Incomplete. I found out at the last minute before exam that you didn't mention conditions for negative slope. Students depend on your teaching and this shows irresponsibility.
Right
@@prafulkotawar9169 🤣
Yes
Bhai kyu gand fad raha h yrr kl exam h or aj pdhne betha hu 😭😭
Isn't it there condition m
Sir what is Xi ??
Are bhai chuna lga diya😂😂😂😂
Incomplete video kaise kaise log hai yha😂😂😂😂
(15,10) or (19,16) ka solved karke send kijiye na please tomorrow is my exam so please make na video on it
Bhai Kaisi demand karte ho
Sir aap rohit sharma jaise dikhte ho🙂
Hnn awaj bhi 19-20 ka hi antar hai 😂😂
Good
soo gooddddd
4:26 that laugh was something hehe
|x|>|y| (neg slope)
Decision Parameter=2∆y-∆x
(Pk0)
X1=x+1
Y1=y+1
Pk+1=pk+2∆y-2∆x
|x|
Sir brehensam algorithm mei slope nikaalne ki jarurat toh h nhi
bresenham circle Algo mein slope ki zarrorat nahi hoti. Line wale mein zaroori hota hai kyuki uske base pe hi fir konsa decision parameter use karna hota hai woh karte hai 2dx-dy ya 2dy-dx
Nice
The smile 😂 4:26
Thos aakde 😂😂🤣
Wow!
04:25 Funny Moment for ....
physics wala 2.0 😂
04:35 😂😂
kl hi exam h 😂😂😂
Sir aage se hatt jao...dikh nhi rha kuch bhi
Few hours ago 😢
Where is part2?
Koi rusian chura k legyi
4:25 😂😂
4:25😂😂😂😂
Acche se solve krke dikhaya kro
4:35 samjhaa.... nai tu nahi smjha
Friends, if you are facing problems with Bresenhams Line Drawing Algorithm, it doesn't work at all when
X1>X2
OR
Y1>Y2
Please pin📌 this comment for a easy guide to everyone facing problems solving numericals.
Rohit Sharma teaching Computer Graphics
why this guy laughed at that shape 🙂
It is what it is
4:29 dirty mind dirty mind
Laugh 😂
but sir when we take starting point as (6,4) and ending point as (3,13 ) then,,,
none of the cases will work becoz there is not a single case for decrement of x corinate value since we want to go from 6 to 3
then how to solve this ?? please explain