Sir , I have a question, this would be a fast way to do it for short data, but when I try to use this method for audio signals, it will take forever to complete the convolution. Maybe you have any idea of how I can achieve this without using the conv function (with for cycles)
Sir what if the sequence is not the same? Like x(n)={2 3 4 1}, where 3 is the n=2 and h(n)={9 8 1 3 }, where the 9 is the n=0. Can we apply the same method above?
Sir I have to say "Your way of teaching is superb"👌😊
Thanku
Great teaching ! Thanks for sharing
Very well explained, simplest way to learn
Thanku so much
Well explained sir... Thanks for sharing
Very nice video and way of teaching is too easy. Keep it up
Thanku so much
Best teacher!
Thanku so much
Very helpful video
This tutorial is just amazing
Lovely teaching 😊
You are a great teacher👩🏫
Thanku so much
Brilliant sir 🙏
Rohit sir,, great teaching by u, 👏
Thanku
Nice 👌 !
Thanku so much
This is discrete right? how do I do continuous time signal?
For discrete we used stem function and for continuous we used plot....
@@rforrohitarorasirclasses6500 i see, so do u have the video for that?
Awesome teaching sir💞
Thanku
Best👍💯
Badiya
Why do we start from 1? What if the signal starts from -4 -5 -2 or something like that sir?
Its on us 0 or 1 but we have to follow all rules of MATLAB and we can start from -4 no issue and in this i case i used matrix method
Why did you use (i-j+1) in 31 and 32 lines?
I am using matrix method for this implementation, take step by step and you understand after this
Sir , I have a question, this would be a fast way to do it for short data, but when I try to use this method for audio signals, it will take forever to complete the convolution. Maybe you have any idea of how I can achieve this without using the conv function (with for cycles)
Please send detail on rforrohitarorasirclasses@gmail.com
@@rforrohitarorasirclasses6500 Perfect , I just sent you an email!
Sir what if the sequence is not the same? Like x(n)={2 3 4 1}, where 3 is the n=2 and h(n)={9 8 1 3 }, where the 9 is the n=0. Can we apply the same method above?
Yes dear it will work
X(n)= [ 2,0,3,4,1] and h(n)= [ 9,8,1,3] and ans is y(n)= [18,16,29,66,44,21,13,3 ]
X(n)= [ 2,0,3,4,1] and h(n)= [ 9,8,1,3] and ans is y(n)= [18,16,29,66,44,21,13,3 ]
@@rforrohitarorasirclasses6500 Thank you so much Sir
superb
Nice sirji
Sab samajh aa gaya
Why we subplot 2,2,1
It's your wish to apply subplot ......
Sir I beg up please help me why are we checking the condition
Send me the exact problem on my email id. rohitjud@gmail.com
Just writing codes isn't teaching
what the