To derive an equation involving Pythagoras' theorem: - \( a \): adjacent side to the 55° angle - \( b \): opposite side to the 55° angle - \( c \): hypotenuse 1. Pythagorean Theorem:** \[ a^2 + b^2 = c^2 \] 2. Express \( a \) and \( b \) using trigonometric functions:** - From trigonometry, we know: \[ \cos(55^\circ) = \frac{a}{c} \] \[ \sin(55^\circ) = \frac{b}{c} \] 3. Solve for \( a \) and \( b \):** \[ a = c \cos(55^\circ) \] \[ b = c \sin(55^\circ) \] 4. Substitute \( a \) and \( b \) back into the Pythagorean theorem:** \[ (c \cos(55^\circ))^2 + (c \sin(55^\circ))^2 = c^2 \] 5. Simplify the equation:** \[ c^2 \cos^2(55^\circ) + c^2 \sin^2(55^\circ) = c^2 \] 6. Factor out \( c^2 \):** \[ c^2 (\cos^2(55^\circ) + \sin^2(55^\circ)) = c^2 \] 7. Use the Pythagorean identity \(\cos^2(\theta) + \sin^2(\theta) = 1\):** \[ c^2 (1) = c^2 \] This confirms that our equation holds true for any right triangle, including one with a 55° angle. ### Summary The Pythagorean theorem is inherently to sin cos tita😂😂 Bhaii nahi maroge Op bolte 🔥
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bhai mein bahut noob hoon my id in this mode is around 1.8 to 2 fluctuating in crown 2 , kuch din pehle jab gold se shuru kiya tha toh starting me 2.2 ke aaspas tha ab ghatke 1.8 jaisa hogaya he , I am very noob please help me improve my gameplay highest kill is 5 only
To derive an equation involving Pythagoras' theorem:
- \( a \): adjacent side to the 55° angle
- \( b \): opposite side to the 55° angle
- \( c \): hypotenuse
1. Pythagorean Theorem:**
\[
a^2 + b^2 = c^2
\]
2. Express \( a \) and \( b \) using trigonometric functions:**
- From trigonometry, we know:
\[
\cos(55^\circ) = \frac{a}{c}
\]
\[
\sin(55^\circ) = \frac{b}{c}
\]
3. Solve for \( a \) and \( b \):**
\[
a = c \cos(55^\circ)
\]
\[
b = c \sin(55^\circ)
\]
4. Substitute \( a \) and \( b \) back into the Pythagorean theorem:**
\[
(c \cos(55^\circ))^2 + (c \sin(55^\circ))^2 = c^2
\]
5. Simplify the equation:**
\[
c^2 \cos^2(55^\circ) + c^2 \sin^2(55^\circ) = c^2
\]
6. Factor out \( c^2 \):**
\[
c^2 (\cos^2(55^\circ) + \sin^2(55^\circ)) = c^2
\]
7. Use the Pythagorean identity \(\cos^2(\theta) + \sin^2(\theta) = 1\):**
\[
c^2 (1) = c^2
\]
This confirms that our equation holds true for any right triangle, including one with a 55° angle.
### Summary
The Pythagorean theorem is inherently to sin cos tita😂😂
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First time kuch demand kiya kindly consider @Casetoo.
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