Number of vans = v Number of cars = v+15 Number of all the vehicles = v+(v+15)= 2v+15 Out of (2v+15) vehicles, there are v vans. If the total number of vehicles is 100, how many vans there would be? v 100 ---- x 2v + 15 100v --- 2v + 15 Therefore, the number of vans in terms of v, as a percentage of the number of all the vehicles = 100v/(2v+15)%
Hmm, this is an interesting one. Let’s bite in. So, a dealership has some cars and some vans. We want to know what percent of the vehicles at the dealership are vans. Well, take the number of vans, divide by the total number of vehicles and … oh, they don’t give that to us? Okay, let’s be serious. The dealership has v vans. They also have cars, 15 more of them than they have vans. The formula for the percentage of vehicles that are vans is: P = (v / t) * 100%, where P is the percent of vehicles that are vans and t is the total number of vehicles. We aren’t told the total number of vehicles, but we are told the dealership has 15 more cars than vans. Assuming the only vehicles at the dealership are cars and vans, the total number of vehicles would be the number of vans plus the number of cars: t = v + c Since there are 15 more cars than vans, we have the following for c: c = v + 15 Now, we climb back up the ladder of equations, first for total vehicles in terms of vans: t = v + c = v + (v + 15) = 2v + 15 Now we plug this into our percentage equation: P = (v / t) * 100% = [v / (2v + 15] * 100% By the way, the “* 100%” is there to turn a decimal answer into a percentage answer (e.g., 0.42 * 100% = 42%). Interesting point: For any v >= 0, 0%
Cars = Vans + 15 Total = V + C so T = V + (V + 15) = 2V + 15
Ratio = V / T = V / (2V + 15) so Percentage = R . 100% = 100V / (2V + 15) %
great lesson
V = Vans
C = Cars
eq.1 = C = V + 15
irrespective of total
%V = V/(C+V) ×100
C = V +15
%V = (V/(V+15+V))×100
= 100V/(2V+15)
= 100/(2+15/V)
100v/2v+15%
Number of vans = v
Number of cars = v+15
Number of all the vehicles =
v+(v+15)= 2v+15
Out of (2v+15) vehicles, there are v vans.
If the total number of vehicles is 100, how many vans there would be?
v 100
---- x
2v + 15
100v
---
2v + 15
Therefore, the number of vans in terms of v, as a percentage of the number of all the vehicles =
100v/(2v+15)%
Hmm, this is an interesting one. Let’s bite in. So, a dealership has some cars and some vans. We want to know what percent of the vehicles at the dealership are vans. Well, take the number of vans, divide by the total number of vehicles and … oh, they don’t give that to us? Okay, let’s be serious.
The dealership has v vans. They also have cars, 15 more of them than they have vans. The formula for the percentage of vehicles that are vans is:
P = (v / t) * 100%, where P is the percent of vehicles that are vans and t is the total number of vehicles.
We aren’t told the total number of vehicles, but we are told the dealership has 15 more cars than vans. Assuming the only vehicles at the dealership are cars and vans, the total number of vehicles would be the number of vans plus the number of cars:
t = v + c
Since there are 15 more cars than vans, we have the following for c:
c = v + 15
Now, we climb back up the ladder of equations, first for total vehicles in terms of vans:
t = v + c = v + (v + 15) = 2v + 15
Now we plug this into our percentage equation:
P = (v / t) * 100% = [v / (2v + 15] * 100%
By the way, the “* 100%” is there to turn a decimal answer into a percentage answer (e.g., 0.42 * 100% = 42%).
Interesting point: For any v >= 0, 0%
cars = v + 15
vans = v
total vehicles = cars + vans
total vehicles = v + v +15
total vehicles = 2v + 15 --> 100%
v /(2v + 15) x 100
100v / (2v + 15)
Wait a minute, what if there is 1,566 cars and 1551 vans? You can’t just make up a number like 2.
The answer doesn't change, it's still 100V / (2V + 15) %. In that case 155100 / 3117 = 49.76%