Fourier series is nothing is but a linear combination of cosine and sine terms (see the starting of first lecture). Since sine and cosine terms are defined everywhere so Fourier series is also defined everywhere.
@@ameylandge425 Our function f is piecewise continuous function and a_n, b_n are nothing but integration of f(x)*cos, f(x)* sine respectively. Now you are asking whether this Integration exists or not? Answer is yes. Their is a theorem by Riemann which says if we have a function with countably many discontinuities then such functions are always integrable. Here our f is piecewise continuous hence countable discontinuity. Hence its integration always exists i.e. a_n and b_n exists.
Whenever a function is defined over an Interval (0,L) then we try/extend to define a function from (-L,0) in such a way that it becomes either even or odd on (-L,L) so as to get cosine or sine Series expansion respectively.
If u have from (0,2L) then if u want cosine series then to extend the function on (-2L,0) so that on interval (-2L,2L) function becomes even or odd and then u get cosine or sine series expansion respectively. Note that in this case, period will become 4L
Ngl sir ur flow is unmatched....helped me a lott!!! I can understand everything u teach....thank you for everything sir
Glad to hear that..thank you..
This lecture helped me.thanks ...
Great... happy to hear that ☺️
Sir what if any term in the fourier series is not defined ??
Fourier series is nothing is but a linear combination of cosine and sine terms (see the starting of first lecture). Since sine and cosine terms are defined everywhere so Fourier series is also defined everywhere.
@@DrMathaholic sir but if one of the coefficients is not defined for some value of n
@@ameylandge425 Our function f is piecewise continuous function and a_n, b_n are nothing but integration of f(x)*cos, f(x)* sine respectively. Now you are asking whether this Integration exists or not? Answer is yes. Their is a theorem by Riemann which says if we have a function with countably many discontinuities then such functions are always integrable. Here our f is piecewise continuous hence countable discontinuity. Hence its integration always exists i.e. a_n and b_n exists.
What will be the Fourier sine and cosine series for period 2L, where L is any
integer?
Whenever a function is defined over an Interval (0,L) then we try/extend to define a function from (-L,0) in such a way that it becomes either even or odd on (-L,L) so as to get cosine or sine Series expansion respectively.
If u have from (0,2L) then if u want cosine series then to extend the function on (-2L,0) so that on interval (-2L,2L) function becomes even or odd and then u get cosine or sine series expansion respectively. Note that in this case, period will become 4L
Any function of period p : 2L.
And this topic are same?
Yes. They are..