when input V- is 0.99 why output goes to +0.99 ..isn it should be zero ? since no input is given and both terminals at same voltage? something to quickly think about this circuit is its differential amplifier, differentiation of square wave is impulses at other end of capacitor..
What if bandwidth is finite and supply is not infinity ....is it saturated at supply voltage and the response will comparatively slower due to finite bandwidth
The time constant is RC/101. The resistance seen looking at the negative terminal is R/101.
Why time constant is RC/101 .. isn't it RC*101
Is this considered an analog design question?
Anybody know where short questions like this can be found and practiced?
when input V- is 0.99 why output goes to +0.99 ..isn it should be zero ? since no input is given and both terminals at same voltage?
something to quickly think about this circuit is its differential amplifier, differentiation of square wave is impulses at other end of capacitor..
The Output does whatever it takes to equalize both inputs. In that case the opamp outputs 0.99V to compensate the offset.
thanks for video
Nice video, thanks for sharing it :)
What if bandwidth is finite and supply is not infinity ....is it saturated at supply voltage and the response will comparatively slower due to finite bandwidth
yes..with finite bandwidth i can not respond quickly to input changes and will take some time to settle
Difference bw slew rate and Bandwidth??