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1000% over the top class.
oo sir...superb, duper, fabulous , fantastic video sir..🌹🌹🌹🌹
Very easily and detailed explanation,Thankyou Sir🙏
Very simple and amazing explanation thanks for this vidio this vidio is very helpful for me...
VERY GOOD explanation
Very well explained sir thank u so much keep supporting 😍😍
Thank you so much for these amazing videos... My preparation now depends upon you.. Good wishes for you..
the moment of inertia of ISMB400 is 422.1*10^4 but you had write 622.10^4, the whole value changed after that
No its 622.1 itself look for ISMB400 corresponding to Iyy
@@cannonbolt2987 no sir in table ismb400 ,iyy is 422.1
@@AnshumanSingh-jw8or tu ek baar phir se dekh
@@cannonbolt2987 correct
thank u so much sir . please cover rcc also. best lectures of steel on youtube.
Sir explanation is very well
Thank you 💞☺️ sir bottom my heart ❤️
Thank you so much sir.. Your videos are always helpful.
thanku for helping me out via these videos
Thanks a lot sir
Correct ans of Iyy=54.62*10^6 and final answer i.e. safe load = 1878.75KN.........as by mistake sie have multiplied by 12 instead of 2 while calculating Iyy (for plate)
Very good explanation 👍
sir how would we know if the question is built-up question or rolled question?
kya padhaya hai sir maja aa gaya
Plz sir ,send the video of laterally unsupported beam design
Very nice vedios
Sir Iyy ka value 422.1 he steel table mein
sir you are real chad
Nice explained ❤️
Thanks a lot for this video..👍
Moment of inertia in y-y axis aapne multiple by 12 kiya he vahapar 2 aayega
Well explained
Hello sirDDRCS ka lecture nhi hai kya
Thank you so much sir
sir why their is no lec. of plate girder and trusspls. do that also
Thnku so muchhh👍🏻🔥
❤❤❤❤
why we cann't take rmin from steel table?
Sir essme apne ek mistake kar di hai moment of inertia ko apne 2 se multiply ki jagah 12 se multiple Kara diya.. hai.. please check it..
Design of built-up column ka ek video upload kr skte ho sir Please
Sir truss ka kuch problem
Sir DDRCS ka lecture
Tysm sir
Which is code pls provide in description
can you provide pdf of your soln
how can we know whether the question is built up or not?
Nice explanation chlo ab bhndi bhnjya and dJ cultural 3 Nov 2k23
Slenderness ratio 10 se small ayegato kese karenge
Pr built up column section ki buckling class c di hui hoti hain
iyy nikalne le liye parallel axis theorem kyu use nahikia?????
Jarurat nhi h. Same axis h dono ka
Sir (r) minimum ke value may mistake ha r=83.36mm value ha plz solved this for new student 🙏🙏🙏🙏
Iyy me 12 multiply kese hua
Plase sir tell me???
Sir Iýý me into 12 kyu kia
2 karna hey na
Iyy ke calculation m aapne mistake ki hai
Aisa toh online cls mai bhi nahi padhate bhaiSirf PPT chalti rheti hai udhar toh
Please yrr like me diya karo ma book se padti hu code ma kitni dikkat jati hai I know humare sare problem solve ho jati h
IYY
Batho na
1000% over the top class.
oo sir...superb, duper, fabulous , fantastic video sir..🌹🌹🌹🌹
Very easily and detailed explanation,Thankyou Sir🙏
Very simple and amazing explanation thanks for this vidio this vidio is very helpful for me...
VERY GOOD explanation
Very well explained sir thank u so much keep supporting 😍😍
Thank you so much for these amazing videos... My preparation now depends upon you.. Good wishes for you..
the moment of inertia of ISMB400 is 422.1*10^4 but you had write 622.10^4, the whole value changed after that
No its 622.1 itself look for ISMB400 corresponding to Iyy
@@cannonbolt2987 no sir in table ismb400 ,iyy is 422.1
@@AnshumanSingh-jw8or tu ek baar phir se dekh
@@cannonbolt2987 correct
thank u so much sir . please cover rcc also. best lectures of steel on youtube.
Sir explanation is very well
Thank you 💞☺️ sir bottom my heart ❤️
Thank you so much sir.. Your videos are always helpful.
thanku for helping me out via these videos
Thanks a lot sir
Correct ans of Iyy=54.62*10^6 and final answer i.e. safe load = 1878.75KN.........as by mistake sie have multiplied by 12 instead of 2 while calculating Iyy (for plate)
Very good explanation 👍
sir how would we know if the question is built-up question or rolled question?
kya padhaya hai sir maja aa gaya
Plz sir ,send the video of laterally unsupported beam design
Very nice vedios
Sir Iyy ka value 422.1 he steel table mein
sir you are real chad
Nice explained ❤️
Thanks a lot for this video..👍
Moment of inertia in y-y axis aapne multiple by 12 kiya he vahapar 2 aayega
Well explained
Hello sir
DDRCS ka lecture nhi hai kya
Thank you so much sir
sir why their is no lec. of plate girder and truss
pls. do that also
Thnku so muchhh👍🏻🔥
❤❤❤❤
why we cann't take rmin from steel table?
Sir essme apne ek mistake kar di hai moment of inertia ko apne 2 se multiply ki jagah 12 se multiple Kara diya.. hai.. please check it..
Design of built-up column ka ek video upload kr skte ho sir Please
Sir truss ka kuch problem
Sir DDRCS ka lecture
Tysm sir
Which is code pls provide in description
can you provide pdf of your soln
how can we know whether the question is built up or not?
Nice explanation chlo ab bhndi bhnjya and dJ cultural 3 Nov 2k23
Slenderness ratio 10 se small ayegato kese karenge
Pr built up column section ki buckling class c di hui hoti hain
iyy nikalne le liye parallel axis theorem kyu use nahikia?????
Jarurat nhi h. Same axis h dono ka
Sir (r) minimum ke value may mistake ha r=83.36mm value ha plz solved this for new student 🙏🙏🙏🙏
Iyy me 12 multiply kese hua
Plase sir tell me???
Sir Iýý me into 12 kyu kia
2 karna hey na
Iyy ke calculation m aapne mistake ki hai
Aisa toh online cls mai bhi nahi padhate bhai
Sirf PPT chalti rheti hai udhar toh
Please yrr like me diya karo ma book se padti hu code ma kitni dikkat jati hai I know humare sare problem solve ho jati h
IYY
Batho na