Crack the IBM Coding Round in Just 20 Mins! 🚀 | Coding Series🔥

[@lubna2425]

s = input("Enter a string: ")
a = [0] * 255
for i in range(0, len(s), 2):
a[ord(s[i])] += int(s[i + 1])
ans = ""
for i in range(255):
if a[i] != 0:
ans += chr(i)
ans += str(a[i])
print("Output:", ans)

[@malavipande4642]

Thanks a million

[@KomalSingh-qb3hx]

question 1 in java
import java.util.*;
public class ibm2 {
public static void main(String []args){
Scanner sc=new Scanner(System.in);
String s=sc.nextLine();
int ch1[]=new int[255];
for(int i=0;i

[@ronit712]

code for binary to decimal
#include
using namespace std;
int main(){
int binary=111,decimal=0,x=0;
while(binary>0){
int rem=binary%10;
decimal+=pow(2,x);
x++;
binary=binary/10;
}
cout

[@ronitsrivastava377]

Integer.toBinaryString(64);
in Java. C++ has something similar?

[@naveen5978]

Binary to decimal:
s = int(input('Enter: '))
res = 0
counter = 0
while s!=0:
res += (2**counter)*(s%10)
s = s//10
counter+=1
print("Output:", res)

[@ankitpundhir9863]

What if the frequency is given in more than 1 digit? Like a5g14c6b1a12b3

[@akashpatil1676]

Good question bhai👍

[@DeveloperRB]

we have to parse the value like:
char key = s[i]; // The character key
i++; // Move to the next character which should be the start of the number
// Extract the number which may have multiple digits
int value = 0;
while (i < s.length() && isdigit(s[i])) {
value = value * 10 + (s[i] - '0');
i++;
}

[@naveen5978]

s = input("Enter: ")
chk_array = [0]*255
res = ""
for i in range(1,len(s),2):
chk_array[ord(s[i-1])] += int(s[i])
for i in range(len(chk_array)):
for j in range(chk_array[i]):
res += chr(i)
print(res)

[@ayushmaansural4896]

Hi Team, I had IBM coding round on 31st of August (ON_Campus) and questions were super huge and complex. Some required concepts from DP too.

[@20-ECE-145ShivamKumar]

which clg

[@ayushmaansural4896]

@@20-ECE-145ShivamKumar Tier 3 college of Kolkata-

[@MARIAM-eb9zw]

Can you please share the questions ?

[@echelon7zulu]

Was the exam proctored? Can we refer syntax

[@nirajkantsingh1666]

Please tell me about the exam

[@ritik.kumar15]

** Ques-1 : JAVA Solution using single loop **
import java.util.HashMap;
import java.util.Map;
import java.util.stream.Collectors;
public class Test7 {
public static void main(String[] args) {
String compStr = "a3b2c5a1g9c2";
Map map = new HashMap();

for (int i = 0; i < compStr.length(); i+=2) {

if (!map.containsKey(compStr.charAt(i))) {
map.put(compStr.charAt(i), Character.getNumericValue(compStr.charAt(i+1)));
} else {
map.replace(compStr.charAt(i), map.get(compStr.charAt(i)) + Character.getNumericValue(compStr.charAt(i+1)));
}
}

String correctStr = map.entrySet().stream().map(e -> e.getKey()+""+e.getValue()).collect(Collectors.joining(""));

System.out.println(correctStr);

}
}

[@bangtangirl8784]

My personal laptop so slow...can i give hackerrank exam in wipro laptop?

[@Rutujak116]

Thank you sir

[@ritikajain9308]

Kya hum javascript me code kr skte hai

[@suryaprasadpadhi2525]

I gave coding assessment for back-end developer I completed Java but while writing half of the sql my time over... So can I get selected for next English round

[@handsome_devil2747]

what was the question can u tell i am written today

[@echelon7zulu]

Was the exam proctored? Can we refer syntax

[@I.Trista-d7c]

Turner Corner

[@arkapravochakrabarti5517]

Bhaiya 1 ka ye dekha jara
s="a3b2c5a1g9c2"
d={}
for i in range(0,len(s),2):
char=s[i]
freq=int(s[i+1])
if char not in d:
d[char]=freq
else:
d[char]+=freq
res=""
for char in sorted(d.keys()):
res+=char
res+=str(d[char])
print(res)

[@KomalSingh-qb3hx]

//program to convert decimal number to binary number
import java.util.*;
public class ibm3 {
public static void main(String []args){
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int rem=0;
StringBuffer sb=new StringBuffer();
while(n>0){
rem=n%2;
sb.append(rem);
n=n/2;
}
sb.reverse();
System.out.println(sb);
}
}

[@akashroy4467]

For 1st question we can use this solution :
import Foundation
var mainArr = ["g","2","b","4","a","2","c","5","a","1","Z","7","A","4"]
var ansArr = [String]()
for var i in 0..0 {
ansArr.append(name)
ansArr.append(String(count))
}
}
print("Hi:",ansArr )
print("Hello World")

[@ritik.kumar15]

** Ques -2 : JAVA Solution **
import java.util.Scanner;
public class Test8 {
public static void main(String[] args) {

Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
sc.close();

String binNum = "";

while (num != 1) {

binNum += num % 2;
num /= 2;

}

binNum += num;

System.out.println(new StringBuilder(binNum).reverse().toString());

}
}

[@mohammadsheesh]

Good morning Sir

[@Anshologey]

Good Morning

[@rohitd09]

Python solution using dict:
import string
st = input('Enter incorrectly compressed string: ')
dt = {}
for i in st:
if i.isalpha():
dt[i] = 0
for i in range(len(st)):
if st[i].isalpha():
dt[st[i]] += int(st[i+1])

print(dt)
ls_keys = list(dt.keys())
ls_keys.sort()
dt_sorted = {i:dt[i] for i in ls_keys}
ls_sorted_keys = list(dt_sorted.keys())
ls_vals = list(dt_sorted.values())
print(dt)
correct_st = ''
dt_len = len(dt)
print(dt_len)
for i in range(dt_len):
correct_st = correct_st + ls_keys[i] + str(ls_vals[i])
print(correct_st)

[@ramkrishnak6371]

brother dont you think this code wont work when frequency is given in more than one digit like a10b5a2c7

[@BhaveshKumar-dz8hq]

st = 'a3b2c4a4d6b5'
l = list(st)
d={}
srr=''
lt=[]
l1=l[::2]
l2 = set(l1)
l3=list(l2)
l3.sort()
for i in l3:
d[i]=l1.count(i)
ll=list(d.items())
ln=len(ll)*2
for j in ll:
for i in j:
lt.append(i)
for t in lt:
srr=srr+str(t)
print(srr)
##python code

[@KomalSingh-qb3hx]

//program to convert binary number to decimal number
import java.util.*;
public class ibm4 {
public static void main(String []args){
Scanner sc=new Scanner(System.in);
String s=sc.nextLine();
StringBuffer sb=new StringBuffer(s);
sb.reverse();
s=new String(sb);
int n=Integer.parseInt(s);
int rem=0;
double dec=0;
int i=0;
while(n>0){
rem=n%10;
dec=dec+rem*Math.pow(2,i);
i++;
n=n/10;
}
int ans=(int)dec;
System.out.println(ans);
}
}