@@THANDOO23 I just took the long route, using congruency of triangles via common sides and common angles. I would say for 4 marks, the approach I took is more plausible. You've provided the alternative approach provided PQRS is a parallelogram.
If it's shown on the diagram that PQRS is a parallelogram, then by all means. I think if the diagram was clear by showing that PQRS is a parallelogram, then the mark allocation would've probably been 2 marks instead of 4.
I don't think I'll fail my maths anymore with u by my side ... Thank you for this video ❤️it is really helpful
This is incredible feedback 😁 Thank you for all the support. I appreciate 👌
@@MDS_Tutoring what if you simply said P=x because R2 is x and opp sides of parallelogram are equal
@@THANDOO23 I just took the long route, using congruency of triangles via common sides and common angles. I would say for 4 marks, the approach I took is more plausible. You've provided the alternative approach provided PQRS is a parallelogram.
@@MDS_Tutoring would I still get the 4 marks if I only did that
If it's shown on the diagram that PQRS is a parallelogram, then by all means. I think if the diagram was clear by showing that PQRS is a parallelogram, then the mark allocation would've probably been 2 marks instead of 4.
Brilliant! Thank you very much!!! Keep making these videos, man. The hard work will pay off.
Thank you, your continuous support will steer me to make more of these videos. I thank you 😁
Sir why did you replace R1 with M????
Same in size
hey can you please prove that PSRQ is a parallelogram please