Hi Prof...Since we know that the function is "analytic" and "continuous"...(along the x-axis)...I've made a silly mistake as -(1/2)*Re(z)^2 by setting (y=0). Then after thoroughly examining the case, I just figured out that you are absolutely right..."the whole (z) function should be analytic"! Stupid me...!
Am trying to find the conjugate function of u = x²-2x-y² but With reference to 5:54, my Vx is not purely a function of x but 2y and I can't see where am making the mistake. Please kindly assist.
Hi! I’m quite late but I’ve seeing that you are confusing things. Yo can find your vx, why? You can integrate 2y and if I am correct your v there is equal to 2yx+g(y), g(y) is a function and in order to find it, you have to do differentiation of that function on y… No sé cómo escribirte lo demás, pero tienes que igualar esa función a tu ux, y volver a integrar. I’m sorry for my broken English!
So, in essence, a harmonic function is a basis for all harmonic functions that are specific to its conjugate? Also, how should one go about proving analytic continuation?
Can somebody help, I'm feeling a bit dense. At 8:12 when we want look at the function along the real axis. To me it looks like we should set x = y to kill the imaginary part but its stated that this corresponds to setting y = 0? Can someone help reiterate the trick that uses analytic continuation?
I really wish I was intelligent enough to understand ANYTHING that was said here. Sad I know but only reason I came here is due to the subject being mentioned in the film Good Will Hunting, I wanted to know what it was about. Absolute respect but I'm still non the wiser. 😳
Gotta be the most explanatory, concise, thorough math teacher out there! Thanks for supplementing what my stupid textbook thought should be clear.
best explanation of complex analysis on youtube, thanks from Poland
Absolutely phenomenal. Thank you for the concise, informative video!
By the way, Prof...I am from Toronto, Canada, your lecture is very very nice and thoroughly explained - prolific. Thanks so much.
Hi Prof...Since we know that the function is "analytic" and "continuous"...(along the x-axis)...I've made a silly mistake as -(1/2)*Re(z)^2 by setting (y=0). Then after thoroughly examining the case, I just figured out that you are absolutely right..."the whole (z) function should be analytic"! Stupid me...!
Am trying to find the conjugate function of u = x²-2x-y² but With reference to 5:54, my Vx is not purely a function of x but 2y and I can't see where am making the mistake. Please kindly assist.
Hi! I’m quite late but I’ve seeing that you are confusing things. Yo can find your vx, why? You can integrate 2y and if I am correct your v there is equal to 2yx+g(y), g(y) is a function and in order to find it, you have to do differentiation of that function on y… No sé cómo escribirte lo demás, pero tienes que igualar esa función a tu ux, y volver a integrar. I’m sorry for my broken English!
Your voice is so soothing 😔
This helped me sooo much! Thank you~! ^-^
Is there a video that goes more into the properties of harmonic functions?
So, in essence, a harmonic function is a basis for all harmonic functions that are specific to its conjugate? Also, how should one go about proving analytic continuation?
Great lesson, thank you.
Great video, but minor differentiation mistake at 11:27 Im component
Thank you so much!!
At 11:10 there is a mistake and at 11:30 also and at both places there must be another nagative sign.But answer is anyway correct
Totally subscribed.
Great explanation! Thanks!
Thank you very much. found very helpful.
why does V component only differ by a constant
can someone help?? how can he get the result in 12:02 ? i don't really understand. i do appreciate for helping me. thanks
He used the trick he mentioned before, the Analytic continuation. What he did was he put y=0 and replaced x with z.
Can somebody help, I'm feeling a bit dense. At 8:12 when we want look at the function along the real axis. To me it looks like we should set x = y to kill the imaginary part but its stated that this corresponds to setting y = 0? Can someone help reiterate the trick that uses analytic continuation?
thank you sir, was about to ask that!
Mathematical mathematics Memes brought me here lol
I really wish I was intelligent enough to understand ANYTHING that was said here.
Sad I know but only reason I came here is due to the subject being mentioned in the film Good Will Hunting, I wanted to know what it was about.
Absolute respect but I'm still non the wiser. 😳
You'll get there soob buddy
@ That’s very kind of you pal but the more I attempt to learn the less I understand.
I think I’ll just stick to big breasts online! 😉
how did you find the imaginary part of 1/z directly??
Neeraj Prakash I know this is way late but use of the conjugate of the denominator will separate the real and imaginary.
At 3:56 how is the partial derivative of u wrt to x equal to y?
u=xy and when you take the partial wrt x, since y is constant, you just get y
Thank you
Bookmark 7:22
Thanks a lot, sir.
Thank you sir.
Another mistake while integrating at 11:27
Aishik Bhattacharya and he found the right result in despite of his mistakes. too sad :(