This is very Important video for understanding Outer and Inner Sphere Electron Transfer Mechanism. Follow me on Unacademy: unacademy.com/u... #labile #inert #coordination
D8 configuration is Inert. Due to symmetry and CFSE Value equal to . HS. -2.00 and LS. -2.00. Experience, see Ajai Kumar he had mentioned this energy is required thus becomes inert
Sir, your videos are very well explained with basic concepts and I loved it. I was having lots of confusion but after watching your videos my doubts are all cleared now.
I'll try to make atleast 2 videos per week. Taking out time for videos alongwith research work is little difficult. But I'll try to make videos regularly
Why d0, d1 ,d2 are labile as you explained sir while they have vacant eg ?? But according to CFT they should be inert in nature as you said sir in this video !! Kindly explain plz sir
Sir it is really helping you have generated concept for me regarding inert and lebile chemistry ... sir while reading through book i find d7 d9 are inert for low spin complex.
Kinetic stability is how fast reaction proceeds if fast then kinetically unstable if slow then kinetically stable it give Idea about activation energy less activation energy means complex is kinetically unstable and.....
14:47 u said if electrons are in eg then they are labile. 15:02 But in case of d1, d2, d3 there is no electron in eg still they are labile. Didn't explained well. Give the reason. Please explain it .
I think because there is empty place in the d orbital so a ligand can make associative reaction and put its lone pair in any place from the empty places i think it is according to valence bond theory
In outer orbital complexes at 3d orbital, only 4 electrons are filled one orbital vacant why ?? 6 chlorine electrons not filled by that vacant 3d orbital.. can u explain
Sir if it is a high spin complex if it is in the influence of weak ligands then pairing should take place in t2g orbitals first why eg orbitals are get paired before t2g in octahedral complexes in CFT
@@dimbeswarbhumij8026 the eg set arises from interaction with the ligand donor orbitals; this set corresponds to a σ antibonding level.since when electrons goes in antibonding the bonding of ligand with metal is weak therefore the complex will be labile and easily undergoes substitution. I hope it cleared ur doubt.🤗
one doubt in that, we find that, this complexes are high spin or low spin get confused... So its easy way to find that strong field ligands are low spin complex and weak field ligands are high spin complexes.....These are said by my faculty its correct or not
in case of [cr(CN)6]-3 complex CN is strong ligand so the electrons are filled against hunds rule but you filled sigle electrons in 3dxy',3dyz,3dzx, why
Sir in sp3d2 hybridised complex dz2 orbital is vacant and until it is fully filled we can't prefer further orbitals. I have this confusion, kindly me help me out with this🙏🙏. Thankyou 🙏
Because hybridisation main outer d orbitals involved hai therefore that only taking part in bonding thus electrons are filled in them leaving inner 3d orbital vacant. I hope it helps..
the species which is less stable has higher eneregy than the species which are more stable, this is common trend in Chemistry which is followed by all intermediates, complexes and bonds, so a weak bond will be less stable and thus it will have higher energy.
That's called explained in short time without any nonsense talk 👍
D8 configuration is Inert. Due to symmetry and CFSE Value equal to .
HS. -2.00 and LS. -2.00. Experience, see Ajai Kumar he had mentioned this
energy is required thus becomes inert
Ryt d8 in inert
Thanks sir..Ur videos really give boost to our preparation of CSIR NET exam...With love from Kashmir.
Thank you 😇
Best wishes from my side.
Sir, your videos are very well explained with basic concepts and I loved it. I was having lots of confusion but after watching your videos my doubts are all cleared now.
Best teacher in the world
For chemistry
I love thz vedio...thankyu so much sir..& sir plz 4 month ke bad csir net exam h so plz keep uploading more n more vedios by series....😊😊
I'll try to make atleast 2 videos per week. Taking out time for videos alongwith research work is little difficult. But I'll try to make videos regularly
Yes sir..I can understand :) well..best off luck with my best wishes for ur research work :))😊
Rashmi Shukla
Thank you 😇
thanks a lot for making concepts easier to understand ,,,thank u sir
You're welcome 😇
Sir, I am pursuing MSc chemistry first year at Ananthapuram arts college,I learnt lot of chemistry from ur videos
D1,d2,d0 also have no repulsion eg0 according to concept it also has no repulsion means inert only know
Why d0, d1 ,d2 are labile as you explained sir while they have vacant eg ?? But according to CFT they should be inert in nature as you said sir in this video !! Kindly explain plz sir
Leave this question as choice..
Very nice sir....mne apka channel dekhna randomly shuru Kia or ab m apke teaching skills ki fan ho gyi ho...keep going sir 🌸
Thank you 😊😊
Thousands of like to this video...ur explanation is appreciable and more than awsm..
Sir , u have made the concepts so clear. Thanks alot.
Sir it is really helping you have generated concept for me regarding inert and lebile chemistry ... sir while reading through book i find d7 d9 are inert for low spin complex.
Thank u sir for teaching in English
Kinetic stability is how fast reaction proceeds if fast then kinetically unstable if slow then kinetically stable it give Idea about activation energy less activation energy means complex is kinetically unstable and.....
Bro u can create a what's app group.
Thermodynamic stability is measure how much tendency reactant have to lower energy when it form product.
Sir d0, d1 and d2, they don't have eg electrons ,then how it become labile and d3 become inert.
Very nice explanation 😊
14:47 u said if electrons are in eg then they are labile.
15:02 But in case of d1, d2, d3 there is no electron in eg still they are labile.
Didn't explained well.
Give the reason.
Please explain it .
Same problem
Sir please explain this
I think because there is empty place in the d orbital so a ligand can make associative reaction and put its lone pair in any place from the empty places i think it is according to valence bond theory
Sir your videos are Helping me a lot... Thank You so much..
In outer orbital complexes at 3d orbital, only 4 electrons are filled one orbital vacant why ?? 6 chlorine electrons not filled by that vacant 3d orbital.. can u explain
Boopathi Kittusamy bro same doubt
Same doubt
Due to oxidation state.
Nice explanation
Thank you and love you
sir thankyou very much for the videos .
happy teachers day.
thank you dear :)
so nice sir.thank you sir
Sir if it is a high spin complex if it is in the influence of weak ligands then pairing should take place in t2g orbitals first why eg orbitals are get paired before t2g in octahedral complexes in CFT
really sir all concept 👌 👌 is well.god bless you sir...
Awesome explanation sir... Thanks much
Best video
Sir last me thoda samjh nahi aya.....😫😫 Jisme eg empty hota hai wo inert hote Hain!?!???
Yes. Eg main agar electrons aa gye toh us complex ne labile hi hona hai .
@@knowingchemistry735 kyun???
@@dimbeswarbhumij8026 the eg set arises from interaction with the ligand donor orbitals; this set corresponds to a σ antibonding level.since when electrons goes in antibonding the bonding of ligand with metal is weak therefore the complex will be labile and easily undergoes substitution.
I hope it cleared ur doubt.🤗
@@knowingchemistry735 thnk u so much
@@knowingchemistry735 may i ask one more qstn??which book should i follow in order to build some good concepts regarding this topic???
Nice explanation.. Tq.. Ur explanation is awesome
Really useful video....thank you sir
I follow you on unacademy :)
Best
Where from you
sir,continue the videos,only few days left for Ap research set exam
It's difficult for me to make videos daily.
I have lab work also, so plz cooperate.
I am trying to provide two videos per week
one doubt in that, we find that, this complexes are high spin or low spin get confused... So its easy way to find that strong field ligands are low spin complex and weak field ligands are high spin complexes.....These are said by my faculty its correct or not
Love your videos. Thank u
in case of [cr(CN)6]-3 complex CN is strong ligand so the electrons are filled against hunds rule but you filled sigle electrons in 3dxy',3dyz,3dzx, why
d8 is inert no ? As cfse of its low and high spin is always -ve .
❤
If possible please make a video on rate of exchange.... Explaination along with questions
tnq sir....i am waiting for more and more videos..
Hi Kamesh, you can join me on Unacademy, there I'm posting more videos 👍
Already i joined
Osm vedio :) Sir plz upload for stereochemistry...🙏🙏
Stereochemistry I'll upload on Unacademy. Plz follow me. There
Thankyou
Sir d4(ls) is labile? d8 is inert?It is exceptional case.Tell me about it sir.
Sir in sp3d2 hybridised complex dz2 orbital is vacant and until it is fully filled we can't prefer further orbitals. I have this confusion, kindly me help me out with this🙏🙏. Thankyou 🙏
Plz explain Hard acid, hard base & saft acid, saft base concepts
Ohhkkk brother
Thank u sir
But in (Cr (CN)6)3- pairing will be occur because CN is strong ligand
So plzz tell how it is possible or the reason of this
one orbital (dz^2) is empty in mn+3 why it doesn"t allow cl to occupy
Tank you for your valuable class sir
Thank you g
A+++++++ Videos dear sir
Bro explain hydration energy & lattice energy in coordination complex
Alright bro... I'll make on this very soon, 👍
TQ so much sir❤️
thank you sir
You're welcome 😇
Thank you sir. 🙏
Sir small doubt 7:55 in 3d orbit one orbital is vacant, but why not fill that orbital (mn3+)
Because hybridisation main outer d orbitals involved hai therefore that only taking part in bonding thus electrons are filled in them leaving inner 3d orbital vacant. I hope it helps..
Thank you 😊
What is the meaning of higher in energy and lower in energy according to VBT....
I can't understand... Plz any one reply.
Tank u sirr
Thank you very much sir
Thank you sir ❤️
You are great 👍👍🔥🙏🙏💥💢 sir
[Cr (H2O)6]3+ and [Mn(H2O)6]3+ is labile or inert please help
sir can u plz provide a video lecture of bio inorganic for csir
sir, are these videos of coordination playlist is enough to study for coordination unit for csir-net.
Where from you
Thank youu ❤😊
But d8 is inert i think because there is no octahedral distortion
👍👍👍👍
👌👌👌👌👌
Sir isomerism part kab ayega???
Outer inner sphere k baad isomerism
achchha hai..
Sir d8 are inert.
nice sir
D8 is most inert
Tq sir
Plz answer this question sir.
Sir how the weaker bond have higher energy?? Plz explain
the species which is less stable has higher eneregy than the species which are more stable, this is common trend in Chemistry which is followed by all intermediates, complexes and bonds,
so a weak bond will be less stable and thus it will have higher energy.
@@AllBoutChemistry
sir if the bond length is larger then bond energy and bond strength decreases. Can u xplain
@@AllBoutChemistry I think if bond is shorter n stronger then it requires more energy to break that bond
8:24 vbt
Sir, d8 is inert right?
Yup
nice
d6 high spin wrong it should be t2g 4 and eg 2
Mistake h .
d1. d2. d3 inert honge.. and d6 high spin me mistake h
That that that. What the fuck!!!
In d6 why eg orbital is filled with 3 electrons?
Not understood.
D⁸ is inert not labile
... D8 inert hota h yrrr🤦♀️
It's nice but try to speak in a fluent english otherwise opt hindi.
First you should understand this topic yourself. After that you should try to teach other.
ajeeb angrezi h it would be better agr ap native language men smjhate…i am unable to stay focused
Thank you Sir
thanku so much sir
Bro u can create a what's app group.
Thank you sir
Thank you sir
Thank u sir